how to solve the complex logarithm problem with limit Re(z) converges to infinity?
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Prove that $$lim_{Re(z)rightarrow infty }(logGamma (z+1)-(z+frac{1}{2})log z+z)=frac{1}{2}log2pi.$$
analysis
edited 20 hours ago
Tianlalu
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Jidnoi Kajidlit
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up vote
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down vote
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Prove that $$lim_{Re(z)rightarrow infty }(logGamma (z+1)-(z+frac{1}{2})log z+z)=frac{1}{2}log2pi.$$
analysis
edited 20 hours ago
Tianlalu
2,315632
asked 20 hours ago
Jidnoi Kajidlit
6
New contributor
Jidnoi Kajidlit is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
3
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
20 hours ago
1
Are you allowed the use of the Stirling formula ?
– Yves Daoust
20 hours ago
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Prove that $$lim_{Re(z)rightarrow infty }(logGamma (z+1)-(z+frac{1}{2})log z+z)=frac{1}{2}log2pi.$$
analysis
edited 20 hours ago
Tianlalu
2,315632
asked 20 hours ago
Jidnoi Kajidlit
6
New contributor
Jidnoi Kajidlit is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Prove that $$lim_{Re(z)rightarrow infty }(logGamma (z+1)-(z+frac{1}{2})log z+z)=frac{1}{2}log2pi.$$
analysis
analysis
edited 20 hours ago
Tianlalu
2,315632
asked 20 hours ago
Jidnoi Kajidlit
6
New contributor
Jidnoi Kajidlit is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 20 hours ago
Tianlalu
2,315632
asked 20 hours ago
Jidnoi Kajidlit
6
New contributor
Jidnoi Kajidlit is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 20 hours ago
Tianlalu
2,315632
edited 20 hours ago
Tianlalu
2,315632
edited 20 hours ago
Tianlalu
2,315632
2,315632
asked 20 hours ago
Jidnoi Kajidlit
6
New contributor
Jidnoi Kajidlit is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 20 hours ago
Jidnoi Kajidlit
6
asked 20 hours ago
Jidnoi Kajidlit
6
6
New contributor
Jidnoi Kajidlit is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Jidnoi Kajidlit is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Jidnoi Kajidlit is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
3
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
20 hours ago
1
Are you allowed the use of the Stirling formula ?
– Yves Daoust
20 hours ago
add a comment |
3
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
20 hours ago
1
Are you allowed the use of the Stirling formula ?
– Yves Daoust
20 hours ago
3
3
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
20 hours ago
Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
20 hours ago
1
1
Are you allowed the use of the Stirling formula ?
– Yves Daoust
20 hours ago
Are you allowed the use of the Stirling formula ?
– Yves Daoust
20 hours ago
add a comment |
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Welcome to MSE. It will be more likely that you will get an answer if you show us that you made an effort. This should be added to the question rather than in the comments.
– José Carlos Santos
20 hours ago
1
Are you allowed the use of the Stirling formula ?
– Yves Daoust
20 hours ago