How to exclude a circle from a rectangle when drawing a contour figure?

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I need to draw a contour figure defined by coordinate x and y. The domain is a rectangle (-100<=x<=100,-100<=y<=100) excluding a circle (center at the origin, and radius of 5). The object function is 'z=x+y'.

What confuses me is how to exclude the circle from the rectangle. How can I draw such a contour figure?

asked 22 hours ago

Robin_Lyn

816

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up vote
3
down vote

favorite

What confuses me is how to exclude the circle from the rectangle. How can I draw such a contour figure?

asked 22 hours ago

Robin_Lyn

816

add a comment |

up vote
3
down vote

favorite

What confuses me is how to exclude the circle from the rectangle. How can I draw such a contour figure?

asked 22 hours ago

Robin_Lyn

816

What confuses me is how to exclude the circle from the rectangle. How can I draw such a contour figure?

plotting

asked 22 hours ago

Robin_Lyn

816

asked 22 hours ago

Robin_Lyn

816

asked 22 hours ago

Robin_Lyn

816

asked 22 hours ago

Robin_Lyn

816

asked 22 hours ago

Robin_Lyn

816

add a comment |

2 Answers
2

active

oldest

votes

up vote
2
down vote

accepted

You can also use ConditionalExpression as the first argument of ContourPlot:

ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],

  {x, -100, 100}, {y, -100, 100},  PlotLegends -> Automatic]

enter image description here

answered 20 hours ago

kglr

171k8193399

add a comment |

up vote
6
down vote

How about this?

ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

 RegionFunction -> Function[{x, y, z}, x^2 + y^2 >= 5^2], 

 PlotPoints -> 100, PerformanceGoal -> "Quality", 

 PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]

enter image description here

If the smoothness of disk bothers you (it bothers me), you can cheat it like so:

Show[ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

  PlotPoints -> 100, PerformanceGoal -> "Quality", 

  PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"], 

 Graphics[{White, Disk[{0, 0}, 5]}]]

enter image description here

edited 9 hours ago

answered 21 hours ago

Okkes Dulgerci

3,5511716

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
19 hours ago

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

up vote
2
down vote

accepted

You can also use ConditionalExpression as the first argument of ContourPlot:

ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],

  {x, -100, 100}, {y, -100, 100},  PlotLegends -> Automatic]

enter image description here

answered 20 hours ago

kglr

171k8193399

add a comment |

up vote
2
down vote

accepted

You can also use ConditionalExpression as the first argument of ContourPlot:

ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],

  {x, -100, 100}, {y, -100, 100},  PlotLegends -> Automatic]

enter image description here

answered 20 hours ago

kglr

171k8193399

add a comment |

up vote
2
down vote

accepted

You can also use ConditionalExpression as the first argument of ContourPlot:

ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],

  {x, -100, 100}, {y, -100, 100},  PlotLegends -> Automatic]

enter image description here

answered 20 hours ago

kglr

171k8193399

You can also use ConditionalExpression as the first argument of ContourPlot:

ContourPlot[ConditionalExpression[x + y, x^2 + y^2 >= 5^2],

  {x, -100, 100}, {y, -100, 100},  PlotLegends -> Automatic]

enter image description here

answered 20 hours ago

kglr

171k8193399

answered 20 hours ago

kglr

171k8193399

answered 20 hours ago

kglr

171k8193399

answered 20 hours ago

kglr

171k8193399

add a comment |

up vote
6
down vote

How about this?

ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

 RegionFunction -> Function[{x, y, z}, x^2 + y^2 >= 5^2], 

 PlotPoints -> 100, PerformanceGoal -> "Quality", 

 PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]

enter image description here

If the smoothness of disk bothers you (it bothers me), you can cheat it like so:

Show[ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

  PlotPoints -> 100, PerformanceGoal -> "Quality", 

  PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"], 

 Graphics[{White, Disk[{0, 0}, 5]}]]

enter image description here

edited 9 hours ago

answered 21 hours ago

Okkes Dulgerci

3,5511716

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
19 hours ago

add a comment |

up vote
6
down vote

How about this?

ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

 RegionFunction -> Function[{x, y, z}, x^2 + y^2 >= 5^2], 

 PlotPoints -> 100, PerformanceGoal -> "Quality", 

 PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]

enter image description here

If the smoothness of disk bothers you (it bothers me), you can cheat it like so:

Show[ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

  PlotPoints -> 100, PerformanceGoal -> "Quality", 

  PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"], 

 Graphics[{White, Disk[{0, 0}, 5]}]]

enter image description here

edited 9 hours ago

answered 21 hours ago

Okkes Dulgerci

3,5511716

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
19 hours ago

add a comment |

up vote
6
down vote

How about this?

ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

 RegionFunction -> Function[{x, y, z}, x^2 + y^2 >= 5^2], 

 PlotPoints -> 100, PerformanceGoal -> "Quality", 

 PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]

enter image description here

If the smoothness of disk bothers you (it bothers me), you can cheat it like so:

Show[ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

  PlotPoints -> 100, PerformanceGoal -> "Quality", 

  PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"], 

 Graphics[{White, Disk[{0, 0}, 5]}]]

enter image description here

edited 9 hours ago

answered 21 hours ago

Okkes Dulgerci

3,5511716

How about this?

ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

 RegionFunction -> Function[{x, y, z}, x^2 + y^2 >= 5^2], 

 PlotPoints -> 100, PerformanceGoal -> "Quality", 

 PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"]

enter image description here

If the smoothness of disk bothers you (it bothers me), you can cheat it like so:

Show[ContourPlot[x + y, {x, -100, 100}, {y, -100, 100}, 

  PlotPoints -> 100, PerformanceGoal -> "Quality", 

  PlotLegends -> Automatic, ColorFunction -> "ThermometerColors"], 

 Graphics[{White, Disk[{0, 0}, 5]}]]

enter image description here

edited 9 hours ago

answered 21 hours ago

Okkes Dulgerci

3,5511716

edited 9 hours ago

answered 21 hours ago

Okkes Dulgerci

3,5511716

answered 21 hours ago

Okkes Dulgerci

3,5511716

answered 21 hours ago

Okkes Dulgerci

3,5511716

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
19 hours ago

add a comment |

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
19 hours ago

Nice quality of the figure! Got it~ Thank you!
– Robin_Lyn
19 hours ago

add a comment |

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