Find the stationary points of: $V=(2/r^3)-(3/r^2)$
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I've applied the exponent rules and differentiated to get to the point where i have
$$dr/dv=-6r^{-4}+6r^{-3}$$
I'm starting to get very confused with the math when i set the LHS = 0 in order to find the value of stationary points.
Any guidance would be helpful.
stationary-point
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up vote
1
down vote
favorite
I've applied the exponent rules and differentiated to get to the point where i have
$$dr/dv=-6r^{-4}+6r^{-3}$$
I'm starting to get very confused with the math when i set the LHS = 0 in order to find the value of stationary points.
Any guidance would be helpful.
stationary-point
Hi, welcome to math.SE! Please use Mathjax to format your equations.
– Jam
Nov 18 at 20:17
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up vote
1
down vote
favorite
up vote
1
down vote
favorite
I've applied the exponent rules and differentiated to get to the point where i have
$$dr/dv=-6r^{-4}+6r^{-3}$$
I'm starting to get very confused with the math when i set the LHS = 0 in order to find the value of stationary points.
Any guidance would be helpful.
stationary-point
I've applied the exponent rules and differentiated to get to the point where i have
$$dr/dv=-6r^{-4}+6r^{-3}$$
I'm starting to get very confused with the math when i set the LHS = 0 in order to find the value of stationary points.
Any guidance would be helpful.
stationary-point
stationary-point
edited Nov 18 at 20:17
greedoid
35k114489
35k114489
asked Nov 18 at 20:12
RocketKangaroo
163
163
Hi, welcome to math.SE! Please use Mathjax to format your equations.
– Jam
Nov 18 at 20:17
add a comment |
Hi, welcome to math.SE! Please use Mathjax to format your equations.
– Jam
Nov 18 at 20:17
Hi, welcome to math.SE! Please use Mathjax to format your equations.
– Jam
Nov 18 at 20:17
Hi, welcome to math.SE! Please use Mathjax to format your equations.
– Jam
Nov 18 at 20:17
add a comment |
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So we have $$-6r^{-4}+6r^{-3}=0implies 6r^{-4}=6r^{-3}implies {6over r^4}={6over r^3};;/cdot r^4$$
$$implies 6=6rimplies r=1$$
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
1
down vote
So we have $$-6r^{-4}+6r^{-3}=0implies 6r^{-4}=6r^{-3}implies {6over r^4}={6over r^3};;/cdot r^4$$
$$implies 6=6rimplies r=1$$
add a comment |
up vote
1
down vote
So we have $$-6r^{-4}+6r^{-3}=0implies 6r^{-4}=6r^{-3}implies {6over r^4}={6over r^3};;/cdot r^4$$
$$implies 6=6rimplies r=1$$
add a comment |
up vote
1
down vote
up vote
1
down vote
So we have $$-6r^{-4}+6r^{-3}=0implies 6r^{-4}=6r^{-3}implies {6over r^4}={6over r^3};;/cdot r^4$$
$$implies 6=6rimplies r=1$$
So we have $$-6r^{-4}+6r^{-3}=0implies 6r^{-4}=6r^{-3}implies {6over r^4}={6over r^3};;/cdot r^4$$
$$implies 6=6rimplies r=1$$
answered Nov 18 at 20:15
greedoid
35k114489
35k114489
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