Particular infinite product convergence











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My question is a little bit technical but if someone has a clue... I have the following infinite product
$$
P = prod_{n=1}^infty( 1 - q^n(n))
$$

where $q(n)$ is an increasing sequence whose limit for $ntoinfty$ is 1.

If $q(n) = (1/n)^{1/n}$ then $q(n) to 1$ (as $log(n)/nto 0$) and $P to 0$. I am looking for the slowest convergence of the $q(n)$ sequence that makes $P to 0$, or at least examples of convergence slower than the one achieved by $(1/n)^{1/n}to 1$.



Thanks for any help










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    up vote
    1
    down vote

    favorite












    My question is a little bit technical but if someone has a clue... I have the following infinite product
    $$
    P = prod_{n=1}^infty( 1 - q^n(n))
    $$

    where $q(n)$ is an increasing sequence whose limit for $ntoinfty$ is 1.

    If $q(n) = (1/n)^{1/n}$ then $q(n) to 1$ (as $log(n)/nto 0$) and $P to 0$. I am looking for the slowest convergence of the $q(n)$ sequence that makes $P to 0$, or at least examples of convergence slower than the one achieved by $(1/n)^{1/n}to 1$.



    Thanks for any help










    share|cite|improve this question


























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      My question is a little bit technical but if someone has a clue... I have the following infinite product
      $$
      P = prod_{n=1}^infty( 1 - q^n(n))
      $$

      where $q(n)$ is an increasing sequence whose limit for $ntoinfty$ is 1.

      If $q(n) = (1/n)^{1/n}$ then $q(n) to 1$ (as $log(n)/nto 0$) and $P to 0$. I am looking for the slowest convergence of the $q(n)$ sequence that makes $P to 0$, or at least examples of convergence slower than the one achieved by $(1/n)^{1/n}to 1$.



      Thanks for any help










      share|cite|improve this question















      My question is a little bit technical but if someone has a clue... I have the following infinite product
      $$
      P = prod_{n=1}^infty( 1 - q^n(n))
      $$

      where $q(n)$ is an increasing sequence whose limit for $ntoinfty$ is 1.

      If $q(n) = (1/n)^{1/n}$ then $q(n) to 1$ (as $log(n)/nto 0$) and $P to 0$. I am looking for the slowest convergence of the $q(n)$ sequence that makes $P to 0$, or at least examples of convergence slower than the one achieved by $(1/n)^{1/n}to 1$.



      Thanks for any help







      sequences-and-series infinite-product






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      edited Nov 18 at 19:10









      Daniele Tampieri

      1,5471619




      1,5471619










      asked Nov 18 at 18:26









      Gianfranco OLDANI

      765




      765



























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