iterate through a list of numbers and break when one of the numbers is not consecutive [on hold]











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 m = 0

    while m < len(pos_1):

        if pos_1[m] == 1 + pos_1[m - 1] or pos_1[m] == pos_1[m + 1] - 1:

            print(pos_1[m])



            if pos_1[4] - 1 != pos_1[3]:

                break

                print(pos_1[3])


this is what my code looks like, PS: it is a part of a larger code, that's why there is no func def and call.
If I have a list like [1, 2, 3, 4, 9, 10]... I want python to go through the list , checking the consecutive number and break when it reaches one that is not consecutive but continue after.
So the output should be:
1, 2, 3, 4
9, 10






python-3.x







share|improve this question







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Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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put on hold as off-topic by Jamal♦ 2 days ago


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – Jamal

If this question can be reworded to fit the rules in the help center, please edit the question.

















    up vote
    0
    down vote

    favorite












     m = 0
    
    while m < len(pos_1):
    
        if pos_1[m] == 1 + pos_1[m - 1] or pos_1[m] == pos_1[m + 1] - 1:
    
            print(pos_1[m])
    

    
            if pos_1[4] - 1 != pos_1[3]:
    
                break
    
                print(pos_1[3])


    this is what my code looks like, PS: it is a part of a larger code, that's why there is no func def and call.
    If I have a list like [1, 2, 3, 4, 9, 10]... I want python to go through the list , checking the consecutive number and break when it reaches one that is not consecutive but continue after.
    So the output should be:
    1, 2, 3, 4
    9, 10






    python-3.x







    share|improve this question







    New contributor




    Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.











    put on hold as off-topic by Jamal♦ 2 days ago


    This question appears to be off-topic. The users who voted to close gave this specific reason:


    • "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – Jamal

    If this question can be reworded to fit the rules in the help center, please edit the question.















      up vote
      0
      down vote

      favorite









      up vote
      0
      down vote

      favorite











       m = 0
      
    while m < len(pos_1):
      
        if pos_1[m] == 1 + pos_1[m - 1] or pos_1[m] == pos_1[m + 1] - 1:
      
            print(pos_1[m])
      

      
            if pos_1[4] - 1 != pos_1[3]:
      
                break
      
                print(pos_1[3])


      this is what my code looks like, PS: it is a part of a larger code, that's why there is no func def and call.
      If I have a list like [1, 2, 3, 4, 9, 10]... I want python to go through the list , checking the consecutive number and break when it reaches one that is not consecutive but continue after.
      So the output should be:
      1, 2, 3, 4
      9, 10






      python-3.x







      share|improve this question







      New contributor




      Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct. 











       m = 0
      
    while m < len(pos_1):
      
        if pos_1[m] == 1 + pos_1[m - 1] or pos_1[m] == pos_1[m + 1] - 1:
      
            print(pos_1[m])
      

      
            if pos_1[4] - 1 != pos_1[3]:
      
                break
      
                print(pos_1[3])


      this is what my code looks like, PS: it is a part of a larger code, that's why there is no func def and call.
      If I have a list like [1, 2, 3, 4, 9, 10]... I want python to go through the list , checking the consecutive number and break when it reaches one that is not consecutive but continue after.
      So the output should be:
      1, 2, 3, 4
      9, 10






      python-3.x




      python-3.x






      share|improve this question







      New contributor




      Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







      New contributor




      Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question






      New contributor




      Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 2 days ago









      Big girl

      1




      1




      New contributor




      Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      Big girl is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




      put on hold as off-topic by Jamal♦ 2 days ago


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – Jamal

      If this question can be reworded to fit the rules in the help center, please edit the question.




      put on hold as off-topic by Jamal♦ 2 days ago


      This question appears to be off-topic. The users who voted to close gave this specific reason:


      • "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – Jamal

      If this question can be reworded to fit the rules in the help center, please edit the question.



























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