iterate through a list of numbers and break when one of the numbers is not consecutive [on hold]
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0
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m = 0
while m < len(pos_1):
if pos_1[m] == 1 + pos_1[m - 1] or pos_1[m] == pos_1[m + 1] - 1:
print(pos_1[m])
if pos_1[4] - 1 != pos_1[3]:
break
print(pos_1[3])
this is what my code looks like, PS: it is a part of a larger code, that's why there is no func def and call.
If I have a list like [1, 2, 3, 4, 9, 10]... I want python to go through the list , checking the consecutive number and break when it reaches one that is not consecutive but continue after.
So the output should be:
1, 2, 3, 4
9, 10
python-3.x
New contributor
put on hold as off-topic by Jamal♦ 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – Jamal
If this question can be reworded to fit the rules in the help center, please edit the question.
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up vote
0
down vote
favorite
m = 0
while m < len(pos_1):
if pos_1[m] == 1 + pos_1[m - 1] or pos_1[m] == pos_1[m + 1] - 1:
print(pos_1[m])
if pos_1[4] - 1 != pos_1[3]:
break
print(pos_1[3])
this is what my code looks like, PS: it is a part of a larger code, that's why there is no func def and call.
If I have a list like [1, 2, 3, 4, 9, 10]... I want python to go through the list , checking the consecutive number and break when it reaches one that is not consecutive but continue after.
So the output should be:
1, 2, 3, 4
9, 10
python-3.x
New contributor
put on hold as off-topic by Jamal♦ 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – Jamal
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
m = 0
while m < len(pos_1):
if pos_1[m] == 1 + pos_1[m - 1] or pos_1[m] == pos_1[m + 1] - 1:
print(pos_1[m])
if pos_1[4] - 1 != pos_1[3]:
break
print(pos_1[3])
this is what my code looks like, PS: it is a part of a larger code, that's why there is no func def and call.
If I have a list like [1, 2, 3, 4, 9, 10]... I want python to go through the list , checking the consecutive number and break when it reaches one that is not consecutive but continue after.
So the output should be:
1, 2, 3, 4
9, 10
python-3.x
New contributor
m = 0
while m < len(pos_1):
if pos_1[m] == 1 + pos_1[m - 1] or pos_1[m] == pos_1[m + 1] - 1:
print(pos_1[m])
if pos_1[4] - 1 != pos_1[3]:
break
print(pos_1[3])
this is what my code looks like, PS: it is a part of a larger code, that's why there is no func def and call.
If I have a list like [1, 2, 3, 4, 9, 10]... I want python to go through the list , checking the consecutive number and break when it reaches one that is not consecutive but continue after.
So the output should be:
1, 2, 3, 4
9, 10
python-3.x
python-3.x
New contributor
New contributor
New contributor
asked 2 days ago
Big girl
1
1
New contributor
New contributor
put on hold as off-topic by Jamal♦ 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – Jamal
If this question can be reworded to fit the rules in the help center, please edit the question.
put on hold as off-topic by Jamal♦ 2 days ago
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "Code not implemented or not working as intended: Code Review is a community where programmers peer-review your working code to address issues such as security, maintainability, performance, and scalability. We require that the code be working correctly, to the best of the author's knowledge, before proceeding with a review." – Jamal
If this question can be reworded to fit the rules in the help center, please edit the question.
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add a comment |
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