Probably of winning with 2 dice against 1
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could some of you help me to find out what is the probability of A) obtain with two dice a greather number than another die?
B) and if the dice are 3 how can I do?
Not the sum of the 2 dice, but the greatest value of those 2 against another die
probability recreational-mathematics conditional-probability
New contributor
add a comment |
up vote
-4
down vote
favorite
could some of you help me to find out what is the probability of A) obtain with two dice a greather number than another die?
B) and if the dice are 3 how can I do?
Not the sum of the 2 dice, but the greatest value of those 2 against another die
probability recreational-mathematics conditional-probability
New contributor
There are $;6^3=216;$ possible outcomes when you throws 3 dice. If you don't distinguish between the two dice and the one die, count in how many of these outcomes two results summed is great than the third outcome...
– DonAntonio
Nov 16 at 10:31
add a comment |
up vote
-4
down vote
favorite
up vote
-4
down vote
favorite
could some of you help me to find out what is the probability of A) obtain with two dice a greather number than another die?
B) and if the dice are 3 how can I do?
Not the sum of the 2 dice, but the greatest value of those 2 against another die
probability recreational-mathematics conditional-probability
New contributor
could some of you help me to find out what is the probability of A) obtain with two dice a greather number than another die?
B) and if the dice are 3 how can I do?
Not the sum of the 2 dice, but the greatest value of those 2 against another die
probability recreational-mathematics conditional-probability
probability recreational-mathematics conditional-probability
New contributor
New contributor
edited Nov 16 at 10:28
New contributor
asked Nov 16 at 10:00
Nicholas Salis
62
62
New contributor
New contributor
There are $;6^3=216;$ possible outcomes when you throws 3 dice. If you don't distinguish between the two dice and the one die, count in how many of these outcomes two results summed is great than the third outcome...
– DonAntonio
Nov 16 at 10:31
add a comment |
There are $;6^3=216;$ possible outcomes when you throws 3 dice. If you don't distinguish between the two dice and the one die, count in how many of these outcomes two results summed is great than the third outcome...
– DonAntonio
Nov 16 at 10:31
There are $;6^3=216;$ possible outcomes when you throws 3 dice. If you don't distinguish between the two dice and the one die, count in how many of these outcomes two results summed is great than the third outcome...
– DonAntonio
Nov 16 at 10:31
There are $;6^3=216;$ possible outcomes when you throws 3 dice. If you don't distinguish between the two dice and the one die, count in how many of these outcomes two results summed is great than the third outcome...
– DonAntonio
Nov 16 at 10:31
add a comment |
1 Answer
1
active
oldest
votes
up vote
0
down vote
If $X$ is the sum of the two dice, and $Y$ the value of the one die, then
what are the possible outcomes $(x,y)$ and which one are "winning"? Then compute their probabilities by independence and add.
Or compute when the one die wins :
$P(Y=6)P(X le 5) + P(Y=5)P(X le 4) + P(Y=4)P(X le 3) + P(Y=3)P(X le 2)$
which equals $frac{1}{6}(frac{1}{36} + frac{3}{36} + frac{6}{36} + frac{10}{36})$
and take the complement of that.
I'm not talking about the sum of the dice but about the maximum value of those two. For example, I roll 2 dice and obtain 5 and 2, roll another and I obtain 3. I want to compare 5 with 3, so the max of those 2 against the one
– Nicholas Salis
Nov 16 at 10:26
@NicholasSalis then adapt the computation.
– Henno Brandsma
Nov 16 at 10:26
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
If $X$ is the sum of the two dice, and $Y$ the value of the one die, then
what are the possible outcomes $(x,y)$ and which one are "winning"? Then compute their probabilities by independence and add.
Or compute when the one die wins :
$P(Y=6)P(X le 5) + P(Y=5)P(X le 4) + P(Y=4)P(X le 3) + P(Y=3)P(X le 2)$
which equals $frac{1}{6}(frac{1}{36} + frac{3}{36} + frac{6}{36} + frac{10}{36})$
and take the complement of that.
I'm not talking about the sum of the dice but about the maximum value of those two. For example, I roll 2 dice and obtain 5 and 2, roll another and I obtain 3. I want to compare 5 with 3, so the max of those 2 against the one
– Nicholas Salis
Nov 16 at 10:26
@NicholasSalis then adapt the computation.
– Henno Brandsma
Nov 16 at 10:26
add a comment |
up vote
0
down vote
If $X$ is the sum of the two dice, and $Y$ the value of the one die, then
what are the possible outcomes $(x,y)$ and which one are "winning"? Then compute their probabilities by independence and add.
Or compute when the one die wins :
$P(Y=6)P(X le 5) + P(Y=5)P(X le 4) + P(Y=4)P(X le 3) + P(Y=3)P(X le 2)$
which equals $frac{1}{6}(frac{1}{36} + frac{3}{36} + frac{6}{36} + frac{10}{36})$
and take the complement of that.
I'm not talking about the sum of the dice but about the maximum value of those two. For example, I roll 2 dice and obtain 5 and 2, roll another and I obtain 3. I want to compare 5 with 3, so the max of those 2 against the one
– Nicholas Salis
Nov 16 at 10:26
@NicholasSalis then adapt the computation.
– Henno Brandsma
Nov 16 at 10:26
add a comment |
up vote
0
down vote
up vote
0
down vote
If $X$ is the sum of the two dice, and $Y$ the value of the one die, then
what are the possible outcomes $(x,y)$ and which one are "winning"? Then compute their probabilities by independence and add.
Or compute when the one die wins :
$P(Y=6)P(X le 5) + P(Y=5)P(X le 4) + P(Y=4)P(X le 3) + P(Y=3)P(X le 2)$
which equals $frac{1}{6}(frac{1}{36} + frac{3}{36} + frac{6}{36} + frac{10}{36})$
and take the complement of that.
If $X$ is the sum of the two dice, and $Y$ the value of the one die, then
what are the possible outcomes $(x,y)$ and which one are "winning"? Then compute their probabilities by independence and add.
Or compute when the one die wins :
$P(Y=6)P(X le 5) + P(Y=5)P(X le 4) + P(Y=4)P(X le 3) + P(Y=3)P(X le 2)$
which equals $frac{1}{6}(frac{1}{36} + frac{3}{36} + frac{6}{36} + frac{10}{36})$
and take the complement of that.
answered Nov 16 at 10:23
Henno Brandsma
101k344107
101k344107
I'm not talking about the sum of the dice but about the maximum value of those two. For example, I roll 2 dice and obtain 5 and 2, roll another and I obtain 3. I want to compare 5 with 3, so the max of those 2 against the one
– Nicholas Salis
Nov 16 at 10:26
@NicholasSalis then adapt the computation.
– Henno Brandsma
Nov 16 at 10:26
add a comment |
I'm not talking about the sum of the dice but about the maximum value of those two. For example, I roll 2 dice and obtain 5 and 2, roll another and I obtain 3. I want to compare 5 with 3, so the max of those 2 against the one
– Nicholas Salis
Nov 16 at 10:26
@NicholasSalis then adapt the computation.
– Henno Brandsma
Nov 16 at 10:26
I'm not talking about the sum of the dice but about the maximum value of those two. For example, I roll 2 dice and obtain 5 and 2, roll another and I obtain 3. I want to compare 5 with 3, so the max of those 2 against the one
– Nicholas Salis
Nov 16 at 10:26
I'm not talking about the sum of the dice but about the maximum value of those two. For example, I roll 2 dice and obtain 5 and 2, roll another and I obtain 3. I want to compare 5 with 3, so the max of those 2 against the one
– Nicholas Salis
Nov 16 at 10:26
@NicholasSalis then adapt the computation.
– Henno Brandsma
Nov 16 at 10:26
@NicholasSalis then adapt the computation.
– Henno Brandsma
Nov 16 at 10:26
add a comment |
Nicholas Salis is a new contributor. Be nice, and check out our Code of Conduct.
Nicholas Salis is a new contributor. Be nice, and check out our Code of Conduct.
Nicholas Salis is a new contributor. Be nice, and check out our Code of Conduct.
Nicholas Salis is a new contributor. Be nice, and check out our Code of Conduct.
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There are $;6^3=216;$ possible outcomes when you throws 3 dice. If you don't distinguish between the two dice and the one die, count in how many of these outcomes two results summed is great than the third outcome...
– DonAntonio
Nov 16 at 10:31