Program that finds prime numbers in a specific range











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I'm kinda new to programming, and as a solution to an exercise, I made a program to find prime numbers in a range. It runs just right for small ranges of numbers, but for this exercise we are given a high range of nums, and it just takes much time to finish examining. Any suggestions how can I make it faster?



#include <stdio.h>

#define START 190000000
#define END 200000000

int main()
{
int primenum = 0, i = 0, j = 0, c = 0;
for (i = START; i <= END; i++)
{
printf("EXMINING %drn", i);
c = 2;
for (j = 2; j <= i-1; j++)
{
if (i%j == 0)
{ c=1;
break;
}
}
if (c == 2) primenum = primenum + 1;
printf("Prime Numbers Found so far: %drn", primenum);
}
printf("THE PRIME NUMBERS ARE %d", primenum);
return 0;
}









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  • 4




    You probably are after a sieve of eratosthenes.
    – Gerrit0
    Oct 20 at 21:05















up vote
2
down vote

favorite












I'm kinda new to programming, and as a solution to an exercise, I made a program to find prime numbers in a range. It runs just right for small ranges of numbers, but for this exercise we are given a high range of nums, and it just takes much time to finish examining. Any suggestions how can I make it faster?



#include <stdio.h>

#define START 190000000
#define END 200000000

int main()
{
int primenum = 0, i = 0, j = 0, c = 0;
for (i = START; i <= END; i++)
{
printf("EXMINING %drn", i);
c = 2;
for (j = 2; j <= i-1; j++)
{
if (i%j == 0)
{ c=1;
break;
}
}
if (c == 2) primenum = primenum + 1;
printf("Prime Numbers Found so far: %drn", primenum);
}
printf("THE PRIME NUMBERS ARE %d", primenum);
return 0;
}









share|improve this question
















bumped to the homepage by Community 2 days ago


This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.











  • 4




    You probably are after a sieve of eratosthenes.
    – Gerrit0
    Oct 20 at 21:05













up vote
2
down vote

favorite









up vote
2
down vote

favorite











I'm kinda new to programming, and as a solution to an exercise, I made a program to find prime numbers in a range. It runs just right for small ranges of numbers, but for this exercise we are given a high range of nums, and it just takes much time to finish examining. Any suggestions how can I make it faster?



#include <stdio.h>

#define START 190000000
#define END 200000000

int main()
{
int primenum = 0, i = 0, j = 0, c = 0;
for (i = START; i <= END; i++)
{
printf("EXMINING %drn", i);
c = 2;
for (j = 2; j <= i-1; j++)
{
if (i%j == 0)
{ c=1;
break;
}
}
if (c == 2) primenum = primenum + 1;
printf("Prime Numbers Found so far: %drn", primenum);
}
printf("THE PRIME NUMBERS ARE %d", primenum);
return 0;
}









share|improve this question















I'm kinda new to programming, and as a solution to an exercise, I made a program to find prime numbers in a range. It runs just right for small ranges of numbers, but for this exercise we are given a high range of nums, and it just takes much time to finish examining. Any suggestions how can I make it faster?



#include <stdio.h>

#define START 190000000
#define END 200000000

int main()
{
int primenum = 0, i = 0, j = 0, c = 0;
for (i = START; i <= END; i++)
{
printf("EXMINING %drn", i);
c = 2;
for (j = 2; j <= i-1; j++)
{
if (i%j == 0)
{ c=1;
break;
}
}
if (c == 2) primenum = primenum + 1;
printf("Prime Numbers Found so far: %drn", primenum);
}
printf("THE PRIME NUMBERS ARE %d", primenum);
return 0;
}






beginner c time-limit-exceeded primes






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edited Oct 20 at 22:14









200_success

127k15148411




127k15148411










asked Oct 20 at 20:35









Δημήτρης Σπανάκης

92




92





bumped to the homepage by Community 2 days ago


This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.







bumped to the homepage by Community 2 days ago


This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.










  • 4




    You probably are after a sieve of eratosthenes.
    – Gerrit0
    Oct 20 at 21:05














  • 4




    You probably are after a sieve of eratosthenes.
    – Gerrit0
    Oct 20 at 21:05








4




4




You probably are after a sieve of eratosthenes.
– Gerrit0
Oct 20 at 21:05




You probably are after a sieve of eratosthenes.
– Gerrit0
Oct 20 at 21:05










1 Answer
1






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oldest

votes

















up vote
0
down vote













I combine here all the above and look up tables.




  1. Use the threshold of sqrt(test_prime) to shrink the range to be tested, as said by @Gaurav.

  2. Increase the prime number to be tested by 2, as said by @1201ProgramAlarm.

  3. Use a look up tables to check only with the prime numbers we have detected until that moment (we remove a lot of unnecessary checks).

  4. Load/Save the look up table for future executions.

  5. Use SIMD instrinsics (not implemented in this solution), so that you can check 4 primes into the look up table at the same time.


My tests took about 4 minutes without pre-calculated lookup table, and about 30 seconds using pre-calculated lookup table.



The code here



#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#include <string.h>

#define START 190000000
#define END 200000000

int is_prime(long test, long n_primes, long* list_primes) {
long max = sqrt(test);
long index = 1;
long prime = list_primes[index];
while (prime <= max) {
if (test % prime == 0)
return 0;
if (++index >= n_primes)
break;
prime = list_primes[index];
}
return 1;
}


void append_prime(long prime, long* size, long* n_primes, long** list_primes) {
if (*n_primes == *size) {
*list_primes = (long*)realloc(*list_primes, (*size + 4096)*sizeof(long));
*size += 1024;
}
(*list_primes)[*n_primes] = prime;
*n_primes += 1;
}


int load_from_disk(long* size, long* n_primes, long** list_primes) {
FILE* f = fopen("primes.dat", "rb");
if (f == NULL)
return 0;
fread(size, sizeof(long), 1, f);
fread(n_primes, sizeof(long), 1, f);
*list_primes = (long*)malloc( ( (*n_primes + 4095) / 4096 ) * 4096 * sizeof(long) );
fread(*list_primes, sizeof(long), *n_primes, f);
fclose(f);
f = NULL;
return 1;
}


int save_to_disk(long* size, long* n_primes, long** list_primes) {
FILE* f = fopen("primes.dat", "w");
if (f == NULL)
return 0;
fwrite(size, sizeof(long), 1, f);
fwrite(n_primes, sizeof(long), 1, f);
fwrite(*list_primes, sizeof(long), *n_primes, f);
fclose(f);
f = NULL;
return 1;
}


long find_primes_until(long threshold, long* size, long* n_primes, long** list_primes) {
if (!load_from_disk(size, n_primes, list_primes)) {
*size = 4096;
*n_primes = 0;
*list_primes = (long*)malloc((*size) * sizeof(long));
memset(*list_primes, 0, (*size) * sizeof(long));

if (threshold > 2) {
(*list_primes)[(*n_primes)++] = 2;
} else {
return *n_primes;
}

if (threshold > 3) {
(*list_primes)[(*n_primes)++] = 3;
} else {
return *n_primes;
}

if (threshold > 5) {
(*list_primes)[(*n_primes)++] = 5;
} else {
return *n_primes;
}

if (threshold > 7) {
(*list_primes)[(*n_primes)++] = 7;
} else {
return *n_primes;
}
}


long prime = (*list_primes)[(*n_primes)-1] + 2;
while (prime < threshold) {
//printf("Examining number: %ld / %ld r", prime, threshold);
if (is_prime(prime, *n_primes, *list_primes)) {
//printf("nPrime number found: %ldn", prime);
append_prime(prime, size, n_primes, list_primes);
}
prime += 2;
}
save_to_disk(size, n_primes, list_primes);

return *n_primes;
}


void find_primes_interval(long start, long end)
{
long* list_primes = NULL;
long size = 0;
long n_primes = 0;

find_primes_until(start, &size, &n_primes, &list_primes);

if ((start & 0x01) == 0)
start++;
while (start < end) {
printf("Examining number: %ld r", start);
if (is_prime(start, n_primes, list_primes)) {
printf("nPrime number found: %ldn", start);
append_prime(start, &size, &n_primes, &list_primes);
}
start += 2;
}
}


int main()
{
find_primes_interval(START, END);
return 0;
}





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    I combine here all the above and look up tables.




    1. Use the threshold of sqrt(test_prime) to shrink the range to be tested, as said by @Gaurav.

    2. Increase the prime number to be tested by 2, as said by @1201ProgramAlarm.

    3. Use a look up tables to check only with the prime numbers we have detected until that moment (we remove a lot of unnecessary checks).

    4. Load/Save the look up table for future executions.

    5. Use SIMD instrinsics (not implemented in this solution), so that you can check 4 primes into the look up table at the same time.


    My tests took about 4 minutes without pre-calculated lookup table, and about 30 seconds using pre-calculated lookup table.



    The code here



    #include <stdio.h>
    #include <stdlib.h>
    #include <math.h>
    #include <string.h>

    #define START 190000000
    #define END 200000000

    int is_prime(long test, long n_primes, long* list_primes) {
    long max = sqrt(test);
    long index = 1;
    long prime = list_primes[index];
    while (prime <= max) {
    if (test % prime == 0)
    return 0;
    if (++index >= n_primes)
    break;
    prime = list_primes[index];
    }
    return 1;
    }


    void append_prime(long prime, long* size, long* n_primes, long** list_primes) {
    if (*n_primes == *size) {
    *list_primes = (long*)realloc(*list_primes, (*size + 4096)*sizeof(long));
    *size += 1024;
    }
    (*list_primes)[*n_primes] = prime;
    *n_primes += 1;
    }


    int load_from_disk(long* size, long* n_primes, long** list_primes) {
    FILE* f = fopen("primes.dat", "rb");
    if (f == NULL)
    return 0;
    fread(size, sizeof(long), 1, f);
    fread(n_primes, sizeof(long), 1, f);
    *list_primes = (long*)malloc( ( (*n_primes + 4095) / 4096 ) * 4096 * sizeof(long) );
    fread(*list_primes, sizeof(long), *n_primes, f);
    fclose(f);
    f = NULL;
    return 1;
    }


    int save_to_disk(long* size, long* n_primes, long** list_primes) {
    FILE* f = fopen("primes.dat", "w");
    if (f == NULL)
    return 0;
    fwrite(size, sizeof(long), 1, f);
    fwrite(n_primes, sizeof(long), 1, f);
    fwrite(*list_primes, sizeof(long), *n_primes, f);
    fclose(f);
    f = NULL;
    return 1;
    }


    long find_primes_until(long threshold, long* size, long* n_primes, long** list_primes) {
    if (!load_from_disk(size, n_primes, list_primes)) {
    *size = 4096;
    *n_primes = 0;
    *list_primes = (long*)malloc((*size) * sizeof(long));
    memset(*list_primes, 0, (*size) * sizeof(long));

    if (threshold > 2) {
    (*list_primes)[(*n_primes)++] = 2;
    } else {
    return *n_primes;
    }

    if (threshold > 3) {
    (*list_primes)[(*n_primes)++] = 3;
    } else {
    return *n_primes;
    }

    if (threshold > 5) {
    (*list_primes)[(*n_primes)++] = 5;
    } else {
    return *n_primes;
    }

    if (threshold > 7) {
    (*list_primes)[(*n_primes)++] = 7;
    } else {
    return *n_primes;
    }
    }


    long prime = (*list_primes)[(*n_primes)-1] + 2;
    while (prime < threshold) {
    //printf("Examining number: %ld / %ld r", prime, threshold);
    if (is_prime(prime, *n_primes, *list_primes)) {
    //printf("nPrime number found: %ldn", prime);
    append_prime(prime, size, n_primes, list_primes);
    }
    prime += 2;
    }
    save_to_disk(size, n_primes, list_primes);

    return *n_primes;
    }


    void find_primes_interval(long start, long end)
    {
    long* list_primes = NULL;
    long size = 0;
    long n_primes = 0;

    find_primes_until(start, &size, &n_primes, &list_primes);

    if ((start & 0x01) == 0)
    start++;
    while (start < end) {
    printf("Examining number: %ld r", start);
    if (is_prime(start, n_primes, list_primes)) {
    printf("nPrime number found: %ldn", start);
    append_prime(start, &size, &n_primes, &list_primes);
    }
    start += 2;
    }
    }


    int main()
    {
    find_primes_interval(START, END);
    return 0;
    }





    share|improve this answer



























      up vote
      0
      down vote













      I combine here all the above and look up tables.




      1. Use the threshold of sqrt(test_prime) to shrink the range to be tested, as said by @Gaurav.

      2. Increase the prime number to be tested by 2, as said by @1201ProgramAlarm.

      3. Use a look up tables to check only with the prime numbers we have detected until that moment (we remove a lot of unnecessary checks).

      4. Load/Save the look up table for future executions.

      5. Use SIMD instrinsics (not implemented in this solution), so that you can check 4 primes into the look up table at the same time.


      My tests took about 4 minutes without pre-calculated lookup table, and about 30 seconds using pre-calculated lookup table.



      The code here



      #include <stdio.h>
      #include <stdlib.h>
      #include <math.h>
      #include <string.h>

      #define START 190000000
      #define END 200000000

      int is_prime(long test, long n_primes, long* list_primes) {
      long max = sqrt(test);
      long index = 1;
      long prime = list_primes[index];
      while (prime <= max) {
      if (test % prime == 0)
      return 0;
      if (++index >= n_primes)
      break;
      prime = list_primes[index];
      }
      return 1;
      }


      void append_prime(long prime, long* size, long* n_primes, long** list_primes) {
      if (*n_primes == *size) {
      *list_primes = (long*)realloc(*list_primes, (*size + 4096)*sizeof(long));
      *size += 1024;
      }
      (*list_primes)[*n_primes] = prime;
      *n_primes += 1;
      }


      int load_from_disk(long* size, long* n_primes, long** list_primes) {
      FILE* f = fopen("primes.dat", "rb");
      if (f == NULL)
      return 0;
      fread(size, sizeof(long), 1, f);
      fread(n_primes, sizeof(long), 1, f);
      *list_primes = (long*)malloc( ( (*n_primes + 4095) / 4096 ) * 4096 * sizeof(long) );
      fread(*list_primes, sizeof(long), *n_primes, f);
      fclose(f);
      f = NULL;
      return 1;
      }


      int save_to_disk(long* size, long* n_primes, long** list_primes) {
      FILE* f = fopen("primes.dat", "w");
      if (f == NULL)
      return 0;
      fwrite(size, sizeof(long), 1, f);
      fwrite(n_primes, sizeof(long), 1, f);
      fwrite(*list_primes, sizeof(long), *n_primes, f);
      fclose(f);
      f = NULL;
      return 1;
      }


      long find_primes_until(long threshold, long* size, long* n_primes, long** list_primes) {
      if (!load_from_disk(size, n_primes, list_primes)) {
      *size = 4096;
      *n_primes = 0;
      *list_primes = (long*)malloc((*size) * sizeof(long));
      memset(*list_primes, 0, (*size) * sizeof(long));

      if (threshold > 2) {
      (*list_primes)[(*n_primes)++] = 2;
      } else {
      return *n_primes;
      }

      if (threshold > 3) {
      (*list_primes)[(*n_primes)++] = 3;
      } else {
      return *n_primes;
      }

      if (threshold > 5) {
      (*list_primes)[(*n_primes)++] = 5;
      } else {
      return *n_primes;
      }

      if (threshold > 7) {
      (*list_primes)[(*n_primes)++] = 7;
      } else {
      return *n_primes;
      }
      }


      long prime = (*list_primes)[(*n_primes)-1] + 2;
      while (prime < threshold) {
      //printf("Examining number: %ld / %ld r", prime, threshold);
      if (is_prime(prime, *n_primes, *list_primes)) {
      //printf("nPrime number found: %ldn", prime);
      append_prime(prime, size, n_primes, list_primes);
      }
      prime += 2;
      }
      save_to_disk(size, n_primes, list_primes);

      return *n_primes;
      }


      void find_primes_interval(long start, long end)
      {
      long* list_primes = NULL;
      long size = 0;
      long n_primes = 0;

      find_primes_until(start, &size, &n_primes, &list_primes);

      if ((start & 0x01) == 0)
      start++;
      while (start < end) {
      printf("Examining number: %ld r", start);
      if (is_prime(start, n_primes, list_primes)) {
      printf("nPrime number found: %ldn", start);
      append_prime(start, &size, &n_primes, &list_primes);
      }
      start += 2;
      }
      }


      int main()
      {
      find_primes_interval(START, END);
      return 0;
      }





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        0
        down vote










        up vote
        0
        down vote









        I combine here all the above and look up tables.




        1. Use the threshold of sqrt(test_prime) to shrink the range to be tested, as said by @Gaurav.

        2. Increase the prime number to be tested by 2, as said by @1201ProgramAlarm.

        3. Use a look up tables to check only with the prime numbers we have detected until that moment (we remove a lot of unnecessary checks).

        4. Load/Save the look up table for future executions.

        5. Use SIMD instrinsics (not implemented in this solution), so that you can check 4 primes into the look up table at the same time.


        My tests took about 4 minutes without pre-calculated lookup table, and about 30 seconds using pre-calculated lookup table.



        The code here



        #include <stdio.h>
        #include <stdlib.h>
        #include <math.h>
        #include <string.h>

        #define START 190000000
        #define END 200000000

        int is_prime(long test, long n_primes, long* list_primes) {
        long max = sqrt(test);
        long index = 1;
        long prime = list_primes[index];
        while (prime <= max) {
        if (test % prime == 0)
        return 0;
        if (++index >= n_primes)
        break;
        prime = list_primes[index];
        }
        return 1;
        }


        void append_prime(long prime, long* size, long* n_primes, long** list_primes) {
        if (*n_primes == *size) {
        *list_primes = (long*)realloc(*list_primes, (*size + 4096)*sizeof(long));
        *size += 1024;
        }
        (*list_primes)[*n_primes] = prime;
        *n_primes += 1;
        }


        int load_from_disk(long* size, long* n_primes, long** list_primes) {
        FILE* f = fopen("primes.dat", "rb");
        if (f == NULL)
        return 0;
        fread(size, sizeof(long), 1, f);
        fread(n_primes, sizeof(long), 1, f);
        *list_primes = (long*)malloc( ( (*n_primes + 4095) / 4096 ) * 4096 * sizeof(long) );
        fread(*list_primes, sizeof(long), *n_primes, f);
        fclose(f);
        f = NULL;
        return 1;
        }


        int save_to_disk(long* size, long* n_primes, long** list_primes) {
        FILE* f = fopen("primes.dat", "w");
        if (f == NULL)
        return 0;
        fwrite(size, sizeof(long), 1, f);
        fwrite(n_primes, sizeof(long), 1, f);
        fwrite(*list_primes, sizeof(long), *n_primes, f);
        fclose(f);
        f = NULL;
        return 1;
        }


        long find_primes_until(long threshold, long* size, long* n_primes, long** list_primes) {
        if (!load_from_disk(size, n_primes, list_primes)) {
        *size = 4096;
        *n_primes = 0;
        *list_primes = (long*)malloc((*size) * sizeof(long));
        memset(*list_primes, 0, (*size) * sizeof(long));

        if (threshold > 2) {
        (*list_primes)[(*n_primes)++] = 2;
        } else {
        return *n_primes;
        }

        if (threshold > 3) {
        (*list_primes)[(*n_primes)++] = 3;
        } else {
        return *n_primes;
        }

        if (threshold > 5) {
        (*list_primes)[(*n_primes)++] = 5;
        } else {
        return *n_primes;
        }

        if (threshold > 7) {
        (*list_primes)[(*n_primes)++] = 7;
        } else {
        return *n_primes;
        }
        }


        long prime = (*list_primes)[(*n_primes)-1] + 2;
        while (prime < threshold) {
        //printf("Examining number: %ld / %ld r", prime, threshold);
        if (is_prime(prime, *n_primes, *list_primes)) {
        //printf("nPrime number found: %ldn", prime);
        append_prime(prime, size, n_primes, list_primes);
        }
        prime += 2;
        }
        save_to_disk(size, n_primes, list_primes);

        return *n_primes;
        }


        void find_primes_interval(long start, long end)
        {
        long* list_primes = NULL;
        long size = 0;
        long n_primes = 0;

        find_primes_until(start, &size, &n_primes, &list_primes);

        if ((start & 0x01) == 0)
        start++;
        while (start < end) {
        printf("Examining number: %ld r", start);
        if (is_prime(start, n_primes, list_primes)) {
        printf("nPrime number found: %ldn", start);
        append_prime(start, &size, &n_primes, &list_primes);
        }
        start += 2;
        }
        }


        int main()
        {
        find_primes_interval(START, END);
        return 0;
        }





        share|improve this answer














        I combine here all the above and look up tables.




        1. Use the threshold of sqrt(test_prime) to shrink the range to be tested, as said by @Gaurav.

        2. Increase the prime number to be tested by 2, as said by @1201ProgramAlarm.

        3. Use a look up tables to check only with the prime numbers we have detected until that moment (we remove a lot of unnecessary checks).

        4. Load/Save the look up table for future executions.

        5. Use SIMD instrinsics (not implemented in this solution), so that you can check 4 primes into the look up table at the same time.


        My tests took about 4 minutes without pre-calculated lookup table, and about 30 seconds using pre-calculated lookup table.



        The code here



        #include <stdio.h>
        #include <stdlib.h>
        #include <math.h>
        #include <string.h>

        #define START 190000000
        #define END 200000000

        int is_prime(long test, long n_primes, long* list_primes) {
        long max = sqrt(test);
        long index = 1;
        long prime = list_primes[index];
        while (prime <= max) {
        if (test % prime == 0)
        return 0;
        if (++index >= n_primes)
        break;
        prime = list_primes[index];
        }
        return 1;
        }


        void append_prime(long prime, long* size, long* n_primes, long** list_primes) {
        if (*n_primes == *size) {
        *list_primes = (long*)realloc(*list_primes, (*size + 4096)*sizeof(long));
        *size += 1024;
        }
        (*list_primes)[*n_primes] = prime;
        *n_primes += 1;
        }


        int load_from_disk(long* size, long* n_primes, long** list_primes) {
        FILE* f = fopen("primes.dat", "rb");
        if (f == NULL)
        return 0;
        fread(size, sizeof(long), 1, f);
        fread(n_primes, sizeof(long), 1, f);
        *list_primes = (long*)malloc( ( (*n_primes + 4095) / 4096 ) * 4096 * sizeof(long) );
        fread(*list_primes, sizeof(long), *n_primes, f);
        fclose(f);
        f = NULL;
        return 1;
        }


        int save_to_disk(long* size, long* n_primes, long** list_primes) {
        FILE* f = fopen("primes.dat", "w");
        if (f == NULL)
        return 0;
        fwrite(size, sizeof(long), 1, f);
        fwrite(n_primes, sizeof(long), 1, f);
        fwrite(*list_primes, sizeof(long), *n_primes, f);
        fclose(f);
        f = NULL;
        return 1;
        }


        long find_primes_until(long threshold, long* size, long* n_primes, long** list_primes) {
        if (!load_from_disk(size, n_primes, list_primes)) {
        *size = 4096;
        *n_primes = 0;
        *list_primes = (long*)malloc((*size) * sizeof(long));
        memset(*list_primes, 0, (*size) * sizeof(long));

        if (threshold > 2) {
        (*list_primes)[(*n_primes)++] = 2;
        } else {
        return *n_primes;
        }

        if (threshold > 3) {
        (*list_primes)[(*n_primes)++] = 3;
        } else {
        return *n_primes;
        }

        if (threshold > 5) {
        (*list_primes)[(*n_primes)++] = 5;
        } else {
        return *n_primes;
        }

        if (threshold > 7) {
        (*list_primes)[(*n_primes)++] = 7;
        } else {
        return *n_primes;
        }
        }


        long prime = (*list_primes)[(*n_primes)-1] + 2;
        while (prime < threshold) {
        //printf("Examining number: %ld / %ld r", prime, threshold);
        if (is_prime(prime, *n_primes, *list_primes)) {
        //printf("nPrime number found: %ldn", prime);
        append_prime(prime, size, n_primes, list_primes);
        }
        prime += 2;
        }
        save_to_disk(size, n_primes, list_primes);

        return *n_primes;
        }


        void find_primes_interval(long start, long end)
        {
        long* list_primes = NULL;
        long size = 0;
        long n_primes = 0;

        find_primes_until(start, &size, &n_primes, &list_primes);

        if ((start & 0x01) == 0)
        start++;
        while (start < end) {
        printf("Examining number: %ld r", start);
        if (is_prime(start, n_primes, list_primes)) {
        printf("nPrime number found: %ldn", start);
        append_prime(start, &size, &n_primes, &list_primes);
        }
        start += 2;
        }
        }


        int main()
        {
        find_primes_interval(START, END);
        return 0;
        }






        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Oct 21 at 9:58

























        answered Oct 21 at 9:44









        Alejandro Visiedo

        1012




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