How to show that eigenvalues of AB and BA are same?











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Let $A$ be an $mtimes n$ matrix and $B$ be an $ntimes m$ matrix. How to use Jordan canonical form to prove the matrix shown below are similar.
Given matrices are $$begin{bmatrix} AB&0\ B&0end{bmatrix}$$ and $$begin{bmatrix} 0&0\ B&BAend{bmatrix}$$
How to find their Jordan forms? I have no idea.










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  • No need to use any Jordan form. See, e.g., here.
    – Algebraic Pavel
    Nov 23 at 15:21















up vote
0
down vote

favorite












Let $A$ be an $mtimes n$ matrix and $B$ be an $ntimes m$ matrix. How to use Jordan canonical form to prove the matrix shown below are similar.
Given matrices are $$begin{bmatrix} AB&0\ B&0end{bmatrix}$$ and $$begin{bmatrix} 0&0\ B&BAend{bmatrix}$$
How to find their Jordan forms? I have no idea.










share|cite|improve this question
























  • No need to use any Jordan form. See, e.g., here.
    – Algebraic Pavel
    Nov 23 at 15:21













up vote
0
down vote

favorite









up vote
0
down vote

favorite











Let $A$ be an $mtimes n$ matrix and $B$ be an $ntimes m$ matrix. How to use Jordan canonical form to prove the matrix shown below are similar.
Given matrices are $$begin{bmatrix} AB&0\ B&0end{bmatrix}$$ and $$begin{bmatrix} 0&0\ B&BAend{bmatrix}$$
How to find their Jordan forms? I have no idea.










share|cite|improve this question















Let $A$ be an $mtimes n$ matrix and $B$ be an $ntimes m$ matrix. How to use Jordan canonical form to prove the matrix shown below are similar.
Given matrices are $$begin{bmatrix} AB&0\ B&0end{bmatrix}$$ and $$begin{bmatrix} 0&0\ B&BAend{bmatrix}$$
How to find their Jordan forms? I have no idea.







matrices eigenvalues-eigenvectors jordan-normal-form






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edited Nov 23 at 12:13









GNUSupporter 8964民主女神 地下教會

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asked Nov 23 at 11:50









Mittal G

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  • No need to use any Jordan form. See, e.g., here.
    – Algebraic Pavel
    Nov 23 at 15:21


















  • No need to use any Jordan form. See, e.g., here.
    – Algebraic Pavel
    Nov 23 at 15:21
















No need to use any Jordan form. See, e.g., here.
– Algebraic Pavel
Nov 23 at 15:21




No need to use any Jordan form. See, e.g., here.
– Algebraic Pavel
Nov 23 at 15:21















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