Nested Quantifiers, “Unique” or “Exactly One” Example
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Question
Let L(x, y) be the predicate: "x likes y", where the domains are given by: x is a CS student and y is a kind of food.
Let D(x) be the predicate: "x is a student in this discrete class", where the domain is: all CS students.
Express the following statement using those predicates and any required quantifiers. You may use only universal and existential quantifiers.
(a) There is exactly one CS student who likes tofu.
Response
My answer: ∃x∀y(L(x, tofu) ∧ ((y ≠ x) ⟹ ¬L(x, y))
What is wrong with my answer?
discrete-mathematics logic
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add a comment |
$begingroup$
Question
Let L(x, y) be the predicate: "x likes y", where the domains are given by: x is a CS student and y is a kind of food.
Let D(x) be the predicate: "x is a student in this discrete class", where the domain is: all CS students.
Express the following statement using those predicates and any required quantifiers. You may use only universal and existential quantifiers.
(a) There is exactly one CS student who likes tofu.
Response
My answer: ∃x∀y(L(x, tofu) ∧ ((y ≠ x) ⟹ ¬L(x, y))
What is wrong with my answer?
discrete-mathematics logic
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4
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Your answer expresses "there is a CS student who likes tofu and likes no food other than himself." In particular, this student has to be tofu.
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– Andreas Blass
Nov 30 '18 at 18:33
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@AndreasBlass This has to be one of the funniest replies that I've seen on MSE
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– Andrei
Dec 1 '18 at 18:49
add a comment |
$begingroup$
Question
Let L(x, y) be the predicate: "x likes y", where the domains are given by: x is a CS student and y is a kind of food.
Let D(x) be the predicate: "x is a student in this discrete class", where the domain is: all CS students.
Express the following statement using those predicates and any required quantifiers. You may use only universal and existential quantifiers.
(a) There is exactly one CS student who likes tofu.
Response
My answer: ∃x∀y(L(x, tofu) ∧ ((y ≠ x) ⟹ ¬L(x, y))
What is wrong with my answer?
discrete-mathematics logic
$endgroup$
Question
Let L(x, y) be the predicate: "x likes y", where the domains are given by: x is a CS student and y is a kind of food.
Let D(x) be the predicate: "x is a student in this discrete class", where the domain is: all CS students.
Express the following statement using those predicates and any required quantifiers. You may use only universal and existential quantifiers.
(a) There is exactly one CS student who likes tofu.
Response
My answer: ∃x∀y(L(x, tofu) ∧ ((y ≠ x) ⟹ ¬L(x, y))
What is wrong with my answer?
discrete-mathematics logic
discrete-mathematics logic
asked Nov 30 '18 at 18:04
Nicholas AdamouNicholas Adamou
32
32
4
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Your answer expresses "there is a CS student who likes tofu and likes no food other than himself." In particular, this student has to be tofu.
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– Andreas Blass
Nov 30 '18 at 18:33
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@AndreasBlass This has to be one of the funniest replies that I've seen on MSE
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– Andrei
Dec 1 '18 at 18:49
add a comment |
4
$begingroup$
Your answer expresses "there is a CS student who likes tofu and likes no food other than himself." In particular, this student has to be tofu.
$endgroup$
– Andreas Blass
Nov 30 '18 at 18:33
$begingroup$
@AndreasBlass This has to be one of the funniest replies that I've seen on MSE
$endgroup$
– Andrei
Dec 1 '18 at 18:49
4
4
$begingroup$
Your answer expresses "there is a CS student who likes tofu and likes no food other than himself." In particular, this student has to be tofu.
$endgroup$
– Andreas Blass
Nov 30 '18 at 18:33
$begingroup$
Your answer expresses "there is a CS student who likes tofu and likes no food other than himself." In particular, this student has to be tofu.
$endgroup$
– Andreas Blass
Nov 30 '18 at 18:33
$begingroup$
@AndreasBlass This has to be one of the funniest replies that I've seen on MSE
$endgroup$
– Andrei
Dec 1 '18 at 18:49
$begingroup$
@AndreasBlass This has to be one of the funniest replies that I've seen on MSE
$endgroup$
– Andrei
Dec 1 '18 at 18:49
add a comment |
2 Answers
2
active
oldest
votes
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Let $t$ stand for tofu. Let $CS$ be the set of all CS majors.
Then
begin{align}
&
&
&exists! x in CS , L(x,t)
&
&text{Exactly one CS student likes $t$.}
\[1ex]
&text{i.e.,} &quad
&exists x in CS , bigl[ L(x,t) wedge forall y in CS , (L(y,t) to y = x ) bigr]
&
&begin{array}
$text{A CS student $x$ likes $t$, and every} \ text{CS student that likes $t$ must be $x$.}end{array}
end{align}
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add a comment |
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There is at least one student $x$ that likes tofu such as all students in the CS class that are not $x$ don't like tofu. It's easy to show that $x$ is unique.
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add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Let $t$ stand for tofu. Let $CS$ be the set of all CS majors.
Then
begin{align}
&
&
&exists! x in CS , L(x,t)
&
&text{Exactly one CS student likes $t$.}
\[1ex]
&text{i.e.,} &quad
&exists x in CS , bigl[ L(x,t) wedge forall y in CS , (L(y,t) to y = x ) bigr]
&
&begin{array}
$text{A CS student $x$ likes $t$, and every} \ text{CS student that likes $t$ must be $x$.}end{array}
end{align}
$endgroup$
add a comment |
$begingroup$
Let $t$ stand for tofu. Let $CS$ be the set of all CS majors.
Then
begin{align}
&
&
&exists! x in CS , L(x,t)
&
&text{Exactly one CS student likes $t$.}
\[1ex]
&text{i.e.,} &quad
&exists x in CS , bigl[ L(x,t) wedge forall y in CS , (L(y,t) to y = x ) bigr]
&
&begin{array}
$text{A CS student $x$ likes $t$, and every} \ text{CS student that likes $t$ must be $x$.}end{array}
end{align}
$endgroup$
add a comment |
$begingroup$
Let $t$ stand for tofu. Let $CS$ be the set of all CS majors.
Then
begin{align}
&
&
&exists! x in CS , L(x,t)
&
&text{Exactly one CS student likes $t$.}
\[1ex]
&text{i.e.,} &quad
&exists x in CS , bigl[ L(x,t) wedge forall y in CS , (L(y,t) to y = x ) bigr]
&
&begin{array}
$text{A CS student $x$ likes $t$, and every} \ text{CS student that likes $t$ must be $x$.}end{array}
end{align}
$endgroup$
Let $t$ stand for tofu. Let $CS$ be the set of all CS majors.
Then
begin{align}
&
&
&exists! x in CS , L(x,t)
&
&text{Exactly one CS student likes $t$.}
\[1ex]
&text{i.e.,} &quad
&exists x in CS , bigl[ L(x,t) wedge forall y in CS , (L(y,t) to y = x ) bigr]
&
&begin{array}
$text{A CS student $x$ likes $t$, and every} \ text{CS student that likes $t$ must be $x$.}end{array}
end{align}
answered Nov 30 '18 at 18:28
Mark TwainMark Twain
1,861510
1,861510
add a comment |
add a comment |
$begingroup$
There is at least one student $x$ that likes tofu such as all students in the CS class that are not $x$ don't like tofu. It's easy to show that $x$ is unique.
$endgroup$
add a comment |
$begingroup$
There is at least one student $x$ that likes tofu such as all students in the CS class that are not $x$ don't like tofu. It's easy to show that $x$ is unique.
$endgroup$
add a comment |
$begingroup$
There is at least one student $x$ that likes tofu such as all students in the CS class that are not $x$ don't like tofu. It's easy to show that $x$ is unique.
$endgroup$
There is at least one student $x$ that likes tofu such as all students in the CS class that are not $x$ don't like tofu. It's easy to show that $x$ is unique.
answered Nov 30 '18 at 18:13
AndreiAndrei
11.6k21026
11.6k21026
add a comment |
add a comment |
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4
$begingroup$
Your answer expresses "there is a CS student who likes tofu and likes no food other than himself." In particular, this student has to be tofu.
$endgroup$
– Andreas Blass
Nov 30 '18 at 18:33
$begingroup$
@AndreasBlass This has to be one of the funniest replies that I've seen on MSE
$endgroup$
– Andrei
Dec 1 '18 at 18:49