calculating volume of a horizontal cylindrical tank from depth
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Has anyone found a good formula to convert a depth of fluid to a volume remaining in a tank for a cylindrical tank laying horizontal? (with or without half sphere end caps)
Much Thanks!
geometry euclidean-geometry
edited Sep 6 '12 at 15:44
Ross Millikan
297k23198371
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migrated from mathematica.stackexchange.com Sep 6 '12 at 15:41
This question came from our site for users of Wolfram Mathematica.
add a comment |
$begingroup$
Has anyone found a good formula to convert a depth of fluid to a volume remaining in a tank for a cylindrical tank laying horizontal? (with or without half sphere end caps)
Much Thanks!
geometry euclidean-geometry
edited Sep 6 '12 at 15:44
Ross Millikan
297k23198371
$endgroup$
migrated from mathematica.stackexchange.com Sep 6 '12 at 15:41
This question came from our site for users of Wolfram Mathematica.
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Is this a mathematical or Mathematica-related question? If it is generally about math, this question should be migrated...
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– Yves Klett
Sep 6 '12 at 15:33
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The version without half sphere end caps was asked here.
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– Américo Tavares
Sep 6 '12 at 16:11
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(Pi*r^2)/2 + Sqrt[h]*(h - r)*Sqrt[-h + 2*r] + r^2*ArcTan[(h - r)/(Sqrt[h]*Sqrt[-h + 2*r])]
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– Dr. belisarius
Sep 6 '12 at 16:14
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Not a duplicate: This tank has half-sphere end caps.
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– Lord_Farin
Oct 24 '13 at 10:30
add a comment |
$begingroup$
Has anyone found a good formula to convert a depth of fluid to a volume remaining in a tank for a cylindrical tank laying horizontal? (with or without half sphere end caps)
Much Thanks!
geometry euclidean-geometry
edited Sep 6 '12 at 15:44
Ross Millikan
297k23198371
$endgroup$
Has anyone found a good formula to convert a depth of fluid to a volume remaining in a tank for a cylindrical tank laying horizontal? (with or without half sphere end caps)
Much Thanks!
geometry euclidean-geometry
geometry euclidean-geometry
edited Sep 6 '12 at 15:44
Ross Millikan
297k23198371
edited Sep 6 '12 at 15:44
Ross Millikan
297k23198371
edited Sep 6 '12 at 15:44
Ross Millikan
297k23198371
edited Sep 6 '12 at 15:44
Ross Millikan
297k23198371
edited Sep 6 '12 at 15:44
Ross Millikan
297k23198371
297k23198371
asked Sep 6 '12 at 15:31
Geof Thompson
migrated from mathematica.stackexchange.com Sep 6 '12 at 15:41
This question came from our site for users of Wolfram Mathematica.
migrated from mathematica.stackexchange.com Sep 6 '12 at 15:41
This question came from our site for users of Wolfram Mathematica.
$begingroup$
Is this a mathematical or Mathematica-related question? If it is generally about math, this question should be migrated...
$endgroup$
– Yves Klett
Sep 6 '12 at 15:33
$begingroup$
The version without half sphere end caps was asked here.
$endgroup$
– Américo Tavares
Sep 6 '12 at 16:11
$begingroup$
(Pi*r^2)/2 + Sqrt[h]*(h - r)*Sqrt[-h + 2*r] + r^2*ArcTan[(h - r)/(Sqrt[h]*Sqrt[-h + 2*r])]
$endgroup$
– Dr. belisarius
Sep 6 '12 at 16:14
$begingroup$
Not a duplicate: This tank has half-sphere end caps.
$endgroup$
– Lord_Farin
Oct 24 '13 at 10:30
add a comment |
$begingroup$
Is this a mathematical or Mathematica-related question? If it is generally about math, this question should be migrated...
$endgroup$
– Yves Klett
Sep 6 '12 at 15:33
$begingroup$
The version without half sphere end caps was asked here.
$endgroup$
– Américo Tavares
Sep 6 '12 at 16:11
$begingroup$
(Pi*r^2)/2 + Sqrt[h]*(h - r)*Sqrt[-h + 2*r] + r^2*ArcTan[(h - r)/(Sqrt[h]*Sqrt[-h + 2*r])]
$endgroup$
– Dr. belisarius
Sep 6 '12 at 16:14
$begingroup$
Not a duplicate: This tank has half-sphere end caps.
$endgroup$
– Lord_Farin
Oct 24 '13 at 10:30
$begingroup$
Is this a mathematical or Mathematica-related question? If it is generally about math, this question should be migrated...
$endgroup$
– Yves Klett
Sep 6 '12 at 15:33
$begingroup$
Is this a mathematical or Mathematica-related question? If it is generally about math, this question should be migrated...
$endgroup$
– Yves Klett
Sep 6 '12 at 15:33
$begingroup$
The version without half sphere end caps was asked here.
$endgroup$
– Américo Tavares
Sep 6 '12 at 16:11
$begingroup$
The version without half sphere end caps was asked here.
$endgroup$
– Américo Tavares
Sep 6 '12 at 16:11
$begingroup$
(Pi*r^2)/2 + Sqrt[h]*(h - r)*Sqrt[-h + 2*r] + r^2*ArcTan[(h - r)/(Sqrt[h]*Sqrt[-h + 2*r])]
$endgroup$
– Dr. belisarius
Sep 6 '12 at 16:14
$begingroup$
(Pi*r^2)/2 + Sqrt[h]*(h - r)*Sqrt[-h + 2*r] + r^2*ArcTan[(h - r)/(Sqrt[h]*Sqrt[-h + 2*r])]
$endgroup$
– Dr. belisarius
Sep 6 '12 at 16:14
$begingroup$
Not a duplicate: This tank has half-sphere end caps.
$endgroup$
– Lord_Farin
Oct 24 '13 at 10:30
$begingroup$
Not a duplicate: This tank has half-sphere end caps.
$endgroup$
– Lord_Farin
Oct 24 '13 at 10:30
add a comment |
1 Answer
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$begingroup$
You could see Wikipedia on the area of a circular segment and multiply by the length. If you want spherical end caps, see Wikipedia on a spherical cap. The two ends together make a sphere.
answered Sep 6 '12 at 15:46
Ross MillikanRoss Millikan
297k23198371
$endgroup$
add a comment |
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1 Answer
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$begingroup$
You could see Wikipedia on the area of a circular segment and multiply by the length. If you want spherical end caps, see Wikipedia on a spherical cap. The two ends together make a sphere.
answered Sep 6 '12 at 15:46
Ross MillikanRoss Millikan
297k23198371
$endgroup$
add a comment |
$begingroup$
You could see Wikipedia on the area of a circular segment and multiply by the length. If you want spherical end caps, see Wikipedia on a spherical cap. The two ends together make a sphere.
answered Sep 6 '12 at 15:46
Ross MillikanRoss Millikan
297k23198371
$endgroup$
add a comment |
$begingroup$
You could see Wikipedia on the area of a circular segment and multiply by the length. If you want spherical end caps, see Wikipedia on a spherical cap. The two ends together make a sphere.
answered Sep 6 '12 at 15:46
Ross MillikanRoss Millikan
297k23198371
$endgroup$
You could see Wikipedia on the area of a circular segment and multiply by the length. If you want spherical end caps, see Wikipedia on a spherical cap. The two ends together make a sphere.
answered Sep 6 '12 at 15:46
Ross MillikanRoss Millikan
297k23198371
answered Sep 6 '12 at 15:46
Ross MillikanRoss Millikan
297k23198371
answered Sep 6 '12 at 15:46
Ross MillikanRoss Millikan
297k23198371
answered Sep 6 '12 at 15:46
Ross MillikanRoss Millikan
297k23198371
297k23198371
add a comment |
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$begingroup$
Is this a mathematical or Mathematica-related question? If it is generally about math, this question should be migrated...
$endgroup$
– Yves Klett
Sep 6 '12 at 15:33
$begingroup$
The version without half sphere end caps was asked here.
$endgroup$
– Américo Tavares
Sep 6 '12 at 16:11
$begingroup$
(Pi*r^2)/2 + Sqrt[h]*(h - r)*Sqrt[-h + 2*r] + r^2*ArcTan[(h - r)/(Sqrt[h]*Sqrt[-h + 2*r])]
$endgroup$
– Dr. belisarius
Sep 6 '12 at 16:14
$begingroup$
Not a duplicate: This tank has half-sphere end caps.
$endgroup$
– Lord_Farin
Oct 24 '13 at 10:30