Solve the right triangle? Round decimals to the nearest tenth?












0












$begingroup$


Image of the triangle There is a right triangle DEF with the adjacent is 12 and the acute angle of D being 25 degrees and E being the right angle... I have to figure out angle F, DF, and DE... I'm honestly not sure on what to do and i'm stressing out.. I may have worded this wrong or missed something but any help would be appreciated, thank you so much.






triangle







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$endgroup$












  • $begingroup$
    This is basic trig. Draw a picture
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:00










  • $begingroup$
    Check out my answer, if you dont understand something tell me
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:13
















0












$begingroup$


Image of the triangle There is a right triangle DEF with the adjacent is 12 and the acute angle of D being 25 degrees and E being the right angle... I have to figure out angle F, DF, and DE... I'm honestly not sure on what to do and i'm stressing out.. I may have worded this wrong or missed something but any help would be appreciated, thank you so much.






triangle







share|cite|improve this question











$endgroup$












  • $begingroup$
    This is basic trig. Draw a picture
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:00










  • $begingroup$
    Check out my answer, if you dont understand something tell me
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:13














0












0








0





$begingroup$


Image of the triangle There is a right triangle DEF with the adjacent is 12 and the acute angle of D being 25 degrees and E being the right angle... I have to figure out angle F, DF, and DE... I'm honestly not sure on what to do and i'm stressing out.. I may have worded this wrong or missed something but any help would be appreciated, thank you so much.






triangle







share|cite|improve this question











$endgroup$




Image of the triangle There is a right triangle DEF with the adjacent is 12 and the acute angle of D being 25 degrees and E being the right angle... I have to figure out angle F, DF, and DE... I'm honestly not sure on what to do and i'm stressing out.. I may have worded this wrong or missed something but any help would be appreciated, thank you so much.






triangle




triangle






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Feb 6 '17 at 20:16









K Split X

4,28921232




4,28921232










asked Feb 6 '17 at 19:58









dannehdanneh

13




13












  • $begingroup$
    This is basic trig. Draw a picture
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:00










  • $begingroup$
    Check out my answer, if you dont understand something tell me
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:13


















  • $begingroup$
    This is basic trig. Draw a picture
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:00










  • $begingroup$
    Check out my answer, if you dont understand something tell me
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:13
















$begingroup$
This is basic trig. Draw a picture
$endgroup$
– K Split X
Feb 6 '17 at 20:00




$begingroup$
This is basic trig. Draw a picture
$endgroup$
– K Split X
Feb 6 '17 at 20:00












$begingroup$
Check out my answer, if you dont understand something tell me
$endgroup$
– K Split X
Feb 6 '17 at 20:13




$begingroup$
Check out my answer, if you dont understand something tell me
$endgroup$
– K Split X
Feb 6 '17 at 20:13










1 Answer
1






active

oldest

votes


















0












$begingroup$

enter image description here



Angle $F$. Remember, the insides of a triangle add up to $180$ degrees.



Length of $DF$. Remember, $sin theta=frac{opp}{hyp}=frac{12}{DF}$



So we have $sin 25=frac{12}{DF}$. You can solve from here.



Length of $DE$. After you calculate angle $F$, then we know $tantheta=frac{opp}{adj}=frac{DE}{9}$



So we have $tan text{ (angle F)}=frac{DE}{9}$. You can solve from here.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    I'm not being lazy, but i'm honestly having a hard time understanding this whole section. How do i figure out the sin 25= 12/DF? It makes no sense to me and i'm feeling stupid here. Also, the same with the length of DE. I just don't get any of this and its frustrating
    $endgroup$
    – danneh
    Feb 6 '17 at 20:19










  • $begingroup$
    sin $25$ you just evaluate in your calculator. We basically have $sin(25) = frac{12}{DF}$, and so solving for $DF$, we see that $DF=frac{12}{sin(25)} = 28.4$
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:35










  • $begingroup$
    If you don't understand your textbook, I highly recommend khanacademy.
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:36










  • $begingroup$
    youtube.com/watch?v=Jsiy4TxgIME
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:36










  • $begingroup$
    is solving for DE the same as we solved for DF?
    $endgroup$
    – danneh
    Feb 6 '17 at 20:38











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1 Answer
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active

oldest

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1 Answer
1






active

oldest

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active

oldest

votes






active

oldest

votes









0












$begingroup$

enter image description here



Angle $F$. Remember, the insides of a triangle add up to $180$ degrees.



Length of $DF$. Remember, $sin theta=frac{opp}{hyp}=frac{12}{DF}$



So we have $sin 25=frac{12}{DF}$. You can solve from here.



Length of $DE$. After you calculate angle $F$, then we know $tantheta=frac{opp}{adj}=frac{DE}{9}$



So we have $tan text{ (angle F)}=frac{DE}{9}$. You can solve from here.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    I'm not being lazy, but i'm honestly having a hard time understanding this whole section. How do i figure out the sin 25= 12/DF? It makes no sense to me and i'm feeling stupid here. Also, the same with the length of DE. I just don't get any of this and its frustrating
    $endgroup$
    – danneh
    Feb 6 '17 at 20:19










  • $begingroup$
    sin $25$ you just evaluate in your calculator. We basically have $sin(25) = frac{12}{DF}$, and so solving for $DF$, we see that $DF=frac{12}{sin(25)} = 28.4$
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:35










  • $begingroup$
    If you don't understand your textbook, I highly recommend khanacademy.
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:36










  • $begingroup$
    youtube.com/watch?v=Jsiy4TxgIME
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:36










  • $begingroup$
    is solving for DE the same as we solved for DF?
    $endgroup$
    – danneh
    Feb 6 '17 at 20:38
















0












$begingroup$

enter image description here



Angle $F$. Remember, the insides of a triangle add up to $180$ degrees.



Length of $DF$. Remember, $sin theta=frac{opp}{hyp}=frac{12}{DF}$



So we have $sin 25=frac{12}{DF}$. You can solve from here.



Length of $DE$. After you calculate angle $F$, then we know $tantheta=frac{opp}{adj}=frac{DE}{9}$



So we have $tan text{ (angle F)}=frac{DE}{9}$. You can solve from here.






share|cite|improve this answer









$endgroup$













  • $begingroup$
    I'm not being lazy, but i'm honestly having a hard time understanding this whole section. How do i figure out the sin 25= 12/DF? It makes no sense to me and i'm feeling stupid here. Also, the same with the length of DE. I just don't get any of this and its frustrating
    $endgroup$
    – danneh
    Feb 6 '17 at 20:19










  • $begingroup$
    sin $25$ you just evaluate in your calculator. We basically have $sin(25) = frac{12}{DF}$, and so solving for $DF$, we see that $DF=frac{12}{sin(25)} = 28.4$
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:35










  • $begingroup$
    If you don't understand your textbook, I highly recommend khanacademy.
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:36










  • $begingroup$
    youtube.com/watch?v=Jsiy4TxgIME
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:36










  • $begingroup$
    is solving for DE the same as we solved for DF?
    $endgroup$
    – danneh
    Feb 6 '17 at 20:38














0












0








0





$begingroup$

enter image description here



Angle $F$. Remember, the insides of a triangle add up to $180$ degrees.



Length of $DF$. Remember, $sin theta=frac{opp}{hyp}=frac{12}{DF}$



So we have $sin 25=frac{12}{DF}$. You can solve from here.



Length of $DE$. After you calculate angle $F$, then we know $tantheta=frac{opp}{adj}=frac{DE}{9}$



So we have $tan text{ (angle F)}=frac{DE}{9}$. You can solve from here.






share|cite|improve this answer









$endgroup$



enter image description here



Angle $F$. Remember, the insides of a triangle add up to $180$ degrees.



Length of $DF$. Remember, $sin theta=frac{opp}{hyp}=frac{12}{DF}$



So we have $sin 25=frac{12}{DF}$. You can solve from here.



Length of $DE$. After you calculate angle $F$, then we know $tantheta=frac{opp}{adj}=frac{DE}{9}$



So we have $tan text{ (angle F)}=frac{DE}{9}$. You can solve from here.







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Feb 6 '17 at 20:07









K Split XK Split X

4,28921232




4,28921232












  • $begingroup$
    I'm not being lazy, but i'm honestly having a hard time understanding this whole section. How do i figure out the sin 25= 12/DF? It makes no sense to me and i'm feeling stupid here. Also, the same with the length of DE. I just don't get any of this and its frustrating
    $endgroup$
    – danneh
    Feb 6 '17 at 20:19










  • $begingroup$
    sin $25$ you just evaluate in your calculator. We basically have $sin(25) = frac{12}{DF}$, and so solving for $DF$, we see that $DF=frac{12}{sin(25)} = 28.4$
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:35










  • $begingroup$
    If you don't understand your textbook, I highly recommend khanacademy.
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:36










  • $begingroup$
    youtube.com/watch?v=Jsiy4TxgIME
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:36










  • $begingroup$
    is solving for DE the same as we solved for DF?
    $endgroup$
    – danneh
    Feb 6 '17 at 20:38


















  • $begingroup$
    I'm not being lazy, but i'm honestly having a hard time understanding this whole section. How do i figure out the sin 25= 12/DF? It makes no sense to me and i'm feeling stupid here. Also, the same with the length of DE. I just don't get any of this and its frustrating
    $endgroup$
    – danneh
    Feb 6 '17 at 20:19










  • $begingroup$
    sin $25$ you just evaluate in your calculator. We basically have $sin(25) = frac{12}{DF}$, and so solving for $DF$, we see that $DF=frac{12}{sin(25)} = 28.4$
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:35










  • $begingroup$
    If you don't understand your textbook, I highly recommend khanacademy.
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:36










  • $begingroup$
    youtube.com/watch?v=Jsiy4TxgIME
    $endgroup$
    – K Split X
    Feb 6 '17 at 20:36










  • $begingroup$
    is solving for DE the same as we solved for DF?
    $endgroup$
    – danneh
    Feb 6 '17 at 20:38
















$begingroup$
I'm not being lazy, but i'm honestly having a hard time understanding this whole section. How do i figure out the sin 25= 12/DF? It makes no sense to me and i'm feeling stupid here. Also, the same with the length of DE. I just don't get any of this and its frustrating
$endgroup$
– danneh
Feb 6 '17 at 20:19




$begingroup$
I'm not being lazy, but i'm honestly having a hard time understanding this whole section. How do i figure out the sin 25= 12/DF? It makes no sense to me and i'm feeling stupid here. Also, the same with the length of DE. I just don't get any of this and its frustrating
$endgroup$
– danneh
Feb 6 '17 at 20:19












$begingroup$
sin $25$ you just evaluate in your calculator. We basically have $sin(25) = frac{12}{DF}$, and so solving for $DF$, we see that $DF=frac{12}{sin(25)} = 28.4$
$endgroup$
– K Split X
Feb 6 '17 at 20:35




$begingroup$
sin $25$ you just evaluate in your calculator. We basically have $sin(25) = frac{12}{DF}$, and so solving for $DF$, we see that $DF=frac{12}{sin(25)} = 28.4$
$endgroup$
– K Split X
Feb 6 '17 at 20:35












$begingroup$
If you don't understand your textbook, I highly recommend khanacademy.
$endgroup$
– K Split X
Feb 6 '17 at 20:36




$begingroup$
If you don't understand your textbook, I highly recommend khanacademy.
$endgroup$
– K Split X
Feb 6 '17 at 20:36












$begingroup$
youtube.com/watch?v=Jsiy4TxgIME
$endgroup$
– K Split X
Feb 6 '17 at 20:36




$begingroup$
youtube.com/watch?v=Jsiy4TxgIME
$endgroup$
– K Split X
Feb 6 '17 at 20:36












$begingroup$
is solving for DE the same as we solved for DF?
$endgroup$
– danneh
Feb 6 '17 at 20:38




$begingroup$
is solving for DE the same as we solved for DF?
$endgroup$
– danneh
Feb 6 '17 at 20:38


















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