Can nonisomorphic groupoids have homotopy equivalent classifying spaces?












2












$begingroup$


We know that two discrete groups having the same classifying space up to homotopy are isomorphic. One can just take fundamental groups and conclude.



The situation with topological groups is subtler. The fundamental group argument doesn't work, but the loop space could work. See this unanswered question.



What if I pass to groupoids? If two discrete groupoids have homotopic classifying spaces, are they equivalent as groupoids? I suspect that taking the fundamental groupoid should suffice, but I am not sure: could anything give me help or clue?



And more subtle again: what happens with topological groupoids? Here I'm afraid I don't have a clue, in fact.



Thank you in advance.










share|cite|improve this question











$endgroup$








  • 3




    $begingroup$
    the groupoids don't have to be isomorphic, only equivalent
    $endgroup$
    – user8268
    Jan 4 at 20:52










  • $begingroup$
    Of course, thanks. Fixed.
    $endgroup$
    – W. Rether
    Jan 4 at 20:57










  • $begingroup$
    for discrete groupoids the answer is yes, for somewhat trivial reasons - just take the fundamental group of each of the path-connected component of the classifying space. No idea about topological groupoids.
    $endgroup$
    – user8268
    Jan 4 at 21:03










  • $begingroup$
    Good point! Just for curiosity: do you think that the fundamental groupoid could work as well? The idea is more or less the same...
    $endgroup$
    – W. Rether
    Jan 4 at 21:06






  • 1




    $begingroup$
    yes, it's basically the same thing
    $endgroup$
    – user8268
    Jan 4 at 21:08
















2












$begingroup$


We know that two discrete groups having the same classifying space up to homotopy are isomorphic. One can just take fundamental groups and conclude.



The situation with topological groups is subtler. The fundamental group argument doesn't work, but the loop space could work. See this unanswered question.



What if I pass to groupoids? If two discrete groupoids have homotopic classifying spaces, are they equivalent as groupoids? I suspect that taking the fundamental groupoid should suffice, but I am not sure: could anything give me help or clue?



And more subtle again: what happens with topological groupoids? Here I'm afraid I don't have a clue, in fact.



Thank you in advance.










share|cite|improve this question











$endgroup$








  • 3




    $begingroup$
    the groupoids don't have to be isomorphic, only equivalent
    $endgroup$
    – user8268
    Jan 4 at 20:52










  • $begingroup$
    Of course, thanks. Fixed.
    $endgroup$
    – W. Rether
    Jan 4 at 20:57










  • $begingroup$
    for discrete groupoids the answer is yes, for somewhat trivial reasons - just take the fundamental group of each of the path-connected component of the classifying space. No idea about topological groupoids.
    $endgroup$
    – user8268
    Jan 4 at 21:03










  • $begingroup$
    Good point! Just for curiosity: do you think that the fundamental groupoid could work as well? The idea is more or less the same...
    $endgroup$
    – W. Rether
    Jan 4 at 21:06






  • 1




    $begingroup$
    yes, it's basically the same thing
    $endgroup$
    – user8268
    Jan 4 at 21:08














2












2








2





$begingroup$


We know that two discrete groups having the same classifying space up to homotopy are isomorphic. One can just take fundamental groups and conclude.



The situation with topological groups is subtler. The fundamental group argument doesn't work, but the loop space could work. See this unanswered question.



What if I pass to groupoids? If two discrete groupoids have homotopic classifying spaces, are they equivalent as groupoids? I suspect that taking the fundamental groupoid should suffice, but I am not sure: could anything give me help or clue?



And more subtle again: what happens with topological groupoids? Here I'm afraid I don't have a clue, in fact.



Thank you in advance.










share|cite|improve this question











$endgroup$




We know that two discrete groups having the same classifying space up to homotopy are isomorphic. One can just take fundamental groups and conclude.



The situation with topological groups is subtler. The fundamental group argument doesn't work, but the loop space could work. See this unanswered question.



What if I pass to groupoids? If two discrete groupoids have homotopic classifying spaces, are they equivalent as groupoids? I suspect that taking the fundamental groupoid should suffice, but I am not sure: could anything give me help or clue?



And more subtle again: what happens with topological groupoids? Here I'm afraid I don't have a clue, in fact.



Thank you in advance.







algebraic-topology fundamental-groups simplicial-stuff groupoids






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 4 at 20:57







W. Rether

















asked Jan 4 at 20:49









W. RetherW. Rether

748417




748417








  • 3




    $begingroup$
    the groupoids don't have to be isomorphic, only equivalent
    $endgroup$
    – user8268
    Jan 4 at 20:52










  • $begingroup$
    Of course, thanks. Fixed.
    $endgroup$
    – W. Rether
    Jan 4 at 20:57










  • $begingroup$
    for discrete groupoids the answer is yes, for somewhat trivial reasons - just take the fundamental group of each of the path-connected component of the classifying space. No idea about topological groupoids.
    $endgroup$
    – user8268
    Jan 4 at 21:03










  • $begingroup$
    Good point! Just for curiosity: do you think that the fundamental groupoid could work as well? The idea is more or less the same...
    $endgroup$
    – W. Rether
    Jan 4 at 21:06






  • 1




    $begingroup$
    yes, it's basically the same thing
    $endgroup$
    – user8268
    Jan 4 at 21:08














  • 3




    $begingroup$
    the groupoids don't have to be isomorphic, only equivalent
    $endgroup$
    – user8268
    Jan 4 at 20:52










  • $begingroup$
    Of course, thanks. Fixed.
    $endgroup$
    – W. Rether
    Jan 4 at 20:57










  • $begingroup$
    for discrete groupoids the answer is yes, for somewhat trivial reasons - just take the fundamental group of each of the path-connected component of the classifying space. No idea about topological groupoids.
    $endgroup$
    – user8268
    Jan 4 at 21:03










  • $begingroup$
    Good point! Just for curiosity: do you think that the fundamental groupoid could work as well? The idea is more or less the same...
    $endgroup$
    – W. Rether
    Jan 4 at 21:06






  • 1




    $begingroup$
    yes, it's basically the same thing
    $endgroup$
    – user8268
    Jan 4 at 21:08








3




3




$begingroup$
the groupoids don't have to be isomorphic, only equivalent
$endgroup$
– user8268
Jan 4 at 20:52




$begingroup$
the groupoids don't have to be isomorphic, only equivalent
$endgroup$
– user8268
Jan 4 at 20:52












$begingroup$
Of course, thanks. Fixed.
$endgroup$
– W. Rether
Jan 4 at 20:57




$begingroup$
Of course, thanks. Fixed.
$endgroup$
– W. Rether
Jan 4 at 20:57












$begingroup$
for discrete groupoids the answer is yes, for somewhat trivial reasons - just take the fundamental group of each of the path-connected component of the classifying space. No idea about topological groupoids.
$endgroup$
– user8268
Jan 4 at 21:03




$begingroup$
for discrete groupoids the answer is yes, for somewhat trivial reasons - just take the fundamental group of each of the path-connected component of the classifying space. No idea about topological groupoids.
$endgroup$
– user8268
Jan 4 at 21:03












$begingroup$
Good point! Just for curiosity: do you think that the fundamental groupoid could work as well? The idea is more or less the same...
$endgroup$
– W. Rether
Jan 4 at 21:06




$begingroup$
Good point! Just for curiosity: do you think that the fundamental groupoid could work as well? The idea is more or less the same...
$endgroup$
– W. Rether
Jan 4 at 21:06




1




1




$begingroup$
yes, it's basically the same thing
$endgroup$
– user8268
Jan 4 at 21:08




$begingroup$
yes, it's basically the same thing
$endgroup$
– user8268
Jan 4 at 21:08










0






active

oldest

votes











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3062095%2fcan-nonisomorphic-groupoids-have-homotopy-equivalent-classifying-spaces%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























0






active

oldest

votes








0






active

oldest

votes









active

oldest

votes






active

oldest

votes
















draft saved

draft discarded




















































Thanks for contributing an answer to Mathematics Stack Exchange!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


Use MathJax to format equations. MathJax reference.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3062095%2fcan-nonisomorphic-groupoids-have-homotopy-equivalent-classifying-spaces%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Quarter-circle Tiles

build a pushdown automaton that recognizes the reverse language of a given pushdown automaton?

Mont Emei