How is $cos (pi/2+h)$ equal to $-sin(h)$? [duplicate]












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This question already has an answer here:




  • How do I prove: $cos (theta + 90^circ) equiv - sin theta $ [duplicate]

    6 answers




I am not able to grasp the logic behind how $cos(frac pi2+h) = -sin(h)$.
I was able to find an explanation on Reddit but it is not clear. Can anybody elaborate in a better way?



Here is the link to the explanation - reddit link










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marked as duplicate by Community Jan 3 at 14:46


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.


















  • $begingroup$
    What definitions of $sin x$ and $cos x$ are you using?
    $endgroup$
    – Shaun
    Jan 3 at 14:14










  • $begingroup$
    What is $cos(A+B)$
    $endgroup$
    – lab bhattacharjee
    Jan 3 at 14:14










  • $begingroup$
    The question i am referring to is available at targetpublications.org/download/hsc-maharashtra-board/…. It is problem no xiii) and solution is given as well. Its just that the solution mentions cos(π/2+h) equal to -sinh without any explanation or citation like trig. identity. Hence needed elaboration on this.
    $endgroup$
    – Shaikh Sakib
    Jan 3 at 14:20










  • $begingroup$
    The question on reddit is about computing a limit. Here you are just asking about a trigonometric identity. I am confused about what it is that you actually want to know. It would also be helpful if you could provide more context. What theorem and definitions can you work with? How are you defining the trigonometric functions (in terms of triangles? circles? power series? differential equations?)? Do you know any complex analysis (one of the answer provided below uses it)? Do you know any angle addition formulae (another answer uses that)?
    $endgroup$
    – Xander Henderson
    Jan 3 at 14:44










  • $begingroup$
    Yes it a limits and continuity chapter with trig. identities used in solution to simplify and arrive at a conclusion. Its just I wanted to see pattern of same kind. This solution math.stackexchange.com/questions/349495/… was what i was looking for.
    $endgroup$
    – Shaikh Sakib
    Jan 3 at 14:54
















-2












$begingroup$



This question already has an answer here:




  • How do I prove: $cos (theta + 90^circ) equiv - sin theta $ [duplicate]

    6 answers




I am not able to grasp the logic behind how $cos(frac pi2+h) = -sin(h)$.
I was able to find an explanation on Reddit but it is not clear. Can anybody elaborate in a better way?



Here is the link to the explanation - reddit link










share|cite|improve this question











$endgroup$



marked as duplicate by Community Jan 3 at 14:46


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.


















  • $begingroup$
    What definitions of $sin x$ and $cos x$ are you using?
    $endgroup$
    – Shaun
    Jan 3 at 14:14










  • $begingroup$
    What is $cos(A+B)$
    $endgroup$
    – lab bhattacharjee
    Jan 3 at 14:14










  • $begingroup$
    The question i am referring to is available at targetpublications.org/download/hsc-maharashtra-board/…. It is problem no xiii) and solution is given as well. Its just that the solution mentions cos(π/2+h) equal to -sinh without any explanation or citation like trig. identity. Hence needed elaboration on this.
    $endgroup$
    – Shaikh Sakib
    Jan 3 at 14:20










  • $begingroup$
    The question on reddit is about computing a limit. Here you are just asking about a trigonometric identity. I am confused about what it is that you actually want to know. It would also be helpful if you could provide more context. What theorem and definitions can you work with? How are you defining the trigonometric functions (in terms of triangles? circles? power series? differential equations?)? Do you know any complex analysis (one of the answer provided below uses it)? Do you know any angle addition formulae (another answer uses that)?
    $endgroup$
    – Xander Henderson
    Jan 3 at 14:44










  • $begingroup$
    Yes it a limits and continuity chapter with trig. identities used in solution to simplify and arrive at a conclusion. Its just I wanted to see pattern of same kind. This solution math.stackexchange.com/questions/349495/… was what i was looking for.
    $endgroup$
    – Shaikh Sakib
    Jan 3 at 14:54














-2












-2








-2





$begingroup$



This question already has an answer here:




  • How do I prove: $cos (theta + 90^circ) equiv - sin theta $ [duplicate]

    6 answers




I am not able to grasp the logic behind how $cos(frac pi2+h) = -sin(h)$.
I was able to find an explanation on Reddit but it is not clear. Can anybody elaborate in a better way?



Here is the link to the explanation - reddit link










share|cite|improve this question











$endgroup$





This question already has an answer here:




  • How do I prove: $cos (theta + 90^circ) equiv - sin theta $ [duplicate]

    6 answers




I am not able to grasp the logic behind how $cos(frac pi2+h) = -sin(h)$.
I was able to find an explanation on Reddit but it is not clear. Can anybody elaborate in a better way?



Here is the link to the explanation - reddit link





This question already has an answer here:




  • How do I prove: $cos (theta + 90^circ) equiv - sin theta $ [duplicate]

    6 answers








trigonometry






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share|cite|improve this question








edited Jan 3 at 14:40









Xander Henderson

14.8k103555




14.8k103555










asked Jan 3 at 14:11









Shaikh SakibShaikh Sakib

195




195




marked as duplicate by Community Jan 3 at 14:46


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.









marked as duplicate by Community Jan 3 at 14:46


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.














  • $begingroup$
    What definitions of $sin x$ and $cos x$ are you using?
    $endgroup$
    – Shaun
    Jan 3 at 14:14










  • $begingroup$
    What is $cos(A+B)$
    $endgroup$
    – lab bhattacharjee
    Jan 3 at 14:14










  • $begingroup$
    The question i am referring to is available at targetpublications.org/download/hsc-maharashtra-board/…. It is problem no xiii) and solution is given as well. Its just that the solution mentions cos(π/2+h) equal to -sinh without any explanation or citation like trig. identity. Hence needed elaboration on this.
    $endgroup$
    – Shaikh Sakib
    Jan 3 at 14:20










  • $begingroup$
    The question on reddit is about computing a limit. Here you are just asking about a trigonometric identity. I am confused about what it is that you actually want to know. It would also be helpful if you could provide more context. What theorem and definitions can you work with? How are you defining the trigonometric functions (in terms of triangles? circles? power series? differential equations?)? Do you know any complex analysis (one of the answer provided below uses it)? Do you know any angle addition formulae (another answer uses that)?
    $endgroup$
    – Xander Henderson
    Jan 3 at 14:44










  • $begingroup$
    Yes it a limits and continuity chapter with trig. identities used in solution to simplify and arrive at a conclusion. Its just I wanted to see pattern of same kind. This solution math.stackexchange.com/questions/349495/… was what i was looking for.
    $endgroup$
    – Shaikh Sakib
    Jan 3 at 14:54


















  • $begingroup$
    What definitions of $sin x$ and $cos x$ are you using?
    $endgroup$
    – Shaun
    Jan 3 at 14:14










  • $begingroup$
    What is $cos(A+B)$
    $endgroup$
    – lab bhattacharjee
    Jan 3 at 14:14










  • $begingroup$
    The question i am referring to is available at targetpublications.org/download/hsc-maharashtra-board/…. It is problem no xiii) and solution is given as well. Its just that the solution mentions cos(π/2+h) equal to -sinh without any explanation or citation like trig. identity. Hence needed elaboration on this.
    $endgroup$
    – Shaikh Sakib
    Jan 3 at 14:20










  • $begingroup$
    The question on reddit is about computing a limit. Here you are just asking about a trigonometric identity. I am confused about what it is that you actually want to know. It would also be helpful if you could provide more context. What theorem and definitions can you work with? How are you defining the trigonometric functions (in terms of triangles? circles? power series? differential equations?)? Do you know any complex analysis (one of the answer provided below uses it)? Do you know any angle addition formulae (another answer uses that)?
    $endgroup$
    – Xander Henderson
    Jan 3 at 14:44










  • $begingroup$
    Yes it a limits and continuity chapter with trig. identities used in solution to simplify and arrive at a conclusion. Its just I wanted to see pattern of same kind. This solution math.stackexchange.com/questions/349495/… was what i was looking for.
    $endgroup$
    – Shaikh Sakib
    Jan 3 at 14:54
















$begingroup$
What definitions of $sin x$ and $cos x$ are you using?
$endgroup$
– Shaun
Jan 3 at 14:14




$begingroup$
What definitions of $sin x$ and $cos x$ are you using?
$endgroup$
– Shaun
Jan 3 at 14:14












$begingroup$
What is $cos(A+B)$
$endgroup$
– lab bhattacharjee
Jan 3 at 14:14




$begingroup$
What is $cos(A+B)$
$endgroup$
– lab bhattacharjee
Jan 3 at 14:14












$begingroup$
The question i am referring to is available at targetpublications.org/download/hsc-maharashtra-board/…. It is problem no xiii) and solution is given as well. Its just that the solution mentions cos(π/2+h) equal to -sinh without any explanation or citation like trig. identity. Hence needed elaboration on this.
$endgroup$
– Shaikh Sakib
Jan 3 at 14:20




$begingroup$
The question i am referring to is available at targetpublications.org/download/hsc-maharashtra-board/…. It is problem no xiii) and solution is given as well. Its just that the solution mentions cos(π/2+h) equal to -sinh without any explanation or citation like trig. identity. Hence needed elaboration on this.
$endgroup$
– Shaikh Sakib
Jan 3 at 14:20












$begingroup$
The question on reddit is about computing a limit. Here you are just asking about a trigonometric identity. I am confused about what it is that you actually want to know. It would also be helpful if you could provide more context. What theorem and definitions can you work with? How are you defining the trigonometric functions (in terms of triangles? circles? power series? differential equations?)? Do you know any complex analysis (one of the answer provided below uses it)? Do you know any angle addition formulae (another answer uses that)?
$endgroup$
– Xander Henderson
Jan 3 at 14:44




$begingroup$
The question on reddit is about computing a limit. Here you are just asking about a trigonometric identity. I am confused about what it is that you actually want to know. It would also be helpful if you could provide more context. What theorem and definitions can you work with? How are you defining the trigonometric functions (in terms of triangles? circles? power series? differential equations?)? Do you know any complex analysis (one of the answer provided below uses it)? Do you know any angle addition formulae (another answer uses that)?
$endgroup$
– Xander Henderson
Jan 3 at 14:44












$begingroup$
Yes it a limits and continuity chapter with trig. identities used in solution to simplify and arrive at a conclusion. Its just I wanted to see pattern of same kind. This solution math.stackexchange.com/questions/349495/… was what i was looking for.
$endgroup$
– Shaikh Sakib
Jan 3 at 14:54




$begingroup$
Yes it a limits and continuity chapter with trig. identities used in solution to simplify and arrive at a conclusion. Its just I wanted to see pattern of same kind. This solution math.stackexchange.com/questions/349495/… was what i was looking for.
$endgroup$
– Shaikh Sakib
Jan 3 at 14:54










2 Answers
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Use that $$cos(alpha+beta)=cos(alpha)cos(beta)-sin(alpha)sin(beta)$$






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    $begingroup$

    Hint: One way to define $cos x$ is $$frac{e^{ix}+e^{-ix}}{2}$$ and, similarly, one can write $sin x$ as $$frac{e^{ix}-e^{-ix}}{2i},$$ where $i$ is defined such that $i^2=-1$. Use $e^{ipi}=-1$.






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      2 Answers
      2






      active

      oldest

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      2 Answers
      2






      active

      oldest

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      active

      oldest

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      0












      $begingroup$

      Use that $$cos(alpha+beta)=cos(alpha)cos(beta)-sin(alpha)sin(beta)$$






      share|cite|improve this answer









      $endgroup$


















        0












        $begingroup$

        Use that $$cos(alpha+beta)=cos(alpha)cos(beta)-sin(alpha)sin(beta)$$






        share|cite|improve this answer









        $endgroup$
















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          0





          $begingroup$

          Use that $$cos(alpha+beta)=cos(alpha)cos(beta)-sin(alpha)sin(beta)$$






          share|cite|improve this answer









          $endgroup$



          Use that $$cos(alpha+beta)=cos(alpha)cos(beta)-sin(alpha)sin(beta)$$







          share|cite|improve this answer












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          share|cite|improve this answer










          answered Jan 3 at 14:15









          Dr. Sonnhard GraubnerDr. Sonnhard Graubner

          76.8k42866




          76.8k42866























              0












              $begingroup$

              Hint: One way to define $cos x$ is $$frac{e^{ix}+e^{-ix}}{2}$$ and, similarly, one can write $sin x$ as $$frac{e^{ix}-e^{-ix}}{2i},$$ where $i$ is defined such that $i^2=-1$. Use $e^{ipi}=-1$.






              share|cite|improve this answer











              $endgroup$


















                0












                $begingroup$

                Hint: One way to define $cos x$ is $$frac{e^{ix}+e^{-ix}}{2}$$ and, similarly, one can write $sin x$ as $$frac{e^{ix}-e^{-ix}}{2i},$$ where $i$ is defined such that $i^2=-1$. Use $e^{ipi}=-1$.






                share|cite|improve this answer











                $endgroup$
















                  0












                  0








                  0





                  $begingroup$

                  Hint: One way to define $cos x$ is $$frac{e^{ix}+e^{-ix}}{2}$$ and, similarly, one can write $sin x$ as $$frac{e^{ix}-e^{-ix}}{2i},$$ where $i$ is defined such that $i^2=-1$. Use $e^{ipi}=-1$.






                  share|cite|improve this answer











                  $endgroup$



                  Hint: One way to define $cos x$ is $$frac{e^{ix}+e^{-ix}}{2}$$ and, similarly, one can write $sin x$ as $$frac{e^{ix}-e^{-ix}}{2i},$$ where $i$ is defined such that $i^2=-1$. Use $e^{ipi}=-1$.







                  share|cite|improve this answer














                  share|cite|improve this answer



                  share|cite|improve this answer








                  edited Jan 12 at 9:59

























                  answered Jan 3 at 14:29









                  ShaunShaun

                  9,366113684




                  9,366113684















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