Find ideal of Grassmannian in Macaulay 2
1
$begingroup$
This question is a technical question about M2. I know that in Macaulay 2 I can use "Grassmannian$(l,k)$" to get ideal of $(l+1)$-plane in $mathbb{C}^{k+1}$ and the result ideal is in $mathbb{ZZ}[p_I]$, but how can I work in another field, say, $mathbb{ZZ}/32003$?
algebraic-geometry macaulay2
edited Dec 8 '18 at 14:23
Rodrigo de Azevedo
12.9k41857
asked Nov 2 '17 at 15:41
BenBen
2,1631123
$endgroup$
add a comment |
1
$begingroup$
This question is a technical question about M2. I know that in Macaulay 2 I can use "Grassmannian$(l,k)$" to get ideal of $(l+1)$-plane in $mathbb{C}^{k+1}$ and the result ideal is in $mathbb{ZZ}[p_I]$, but how can I work in another field, say, $mathbb{ZZ}/32003$?
algebraic-geometry macaulay2
edited Dec 8 '18 at 14:23
Rodrigo de Azevedo
12.9k41857
asked Nov 2 '17 at 15:41
BenBen
2,1631123
$endgroup$
1
$begingroup$
Fromhelp Grassmannian:J = Grassmannian(2,5, CoefficientRing => ZZ/31, Variable => T).
$endgroup$
– Jan-Magnus Økland
Nov 2 '17 at 16:27
$begingroup$
@Jan-MagnusØkland Thanks a lot. Will try that out!
$endgroup$
– Ben
Nov 2 '17 at 16:31
$begingroup$
Let me provide the answer here: J=Grassmannian(2,5, CoefficientRing => ZZ/31); R=use ring J
$endgroup$
– Ben
Nov 2 '17 at 17:11
add a comment |
1
1
1
1
$begingroup$
This question is a technical question about M2. I know that in Macaulay 2 I can use "Grassmannian$(l,k)$" to get ideal of $(l+1)$-plane in $mathbb{C}^{k+1}$ and the result ideal is in $mathbb{ZZ}[p_I]$, but how can I work in another field, say, $mathbb{ZZ}/32003$?
algebraic-geometry macaulay2
edited Dec 8 '18 at 14:23
Rodrigo de Azevedo
12.9k41857
asked Nov 2 '17 at 15:41
BenBen
2,1631123
$endgroup$
This question is a technical question about M2. I know that in Macaulay 2 I can use "Grassmannian$(l,k)$" to get ideal of $(l+1)$-plane in $mathbb{C}^{k+1}$ and the result ideal is in $mathbb{ZZ}[p_I]$, but how can I work in another field, say, $mathbb{ZZ}/32003$?
algebraic-geometry macaulay2
algebraic-geometry macaulay2
edited Dec 8 '18 at 14:23
Rodrigo de Azevedo
12.9k41857
asked Nov 2 '17 at 15:41
BenBen
2,1631123
edited Dec 8 '18 at 14:23
Rodrigo de Azevedo
12.9k41857
asked Nov 2 '17 at 15:41
BenBen
2,1631123
edited Dec 8 '18 at 14:23
Rodrigo de Azevedo
12.9k41857
edited Dec 8 '18 at 14:23
Rodrigo de Azevedo
12.9k41857
edited Dec 8 '18 at 14:23
Rodrigo de Azevedo
12.9k41857
12.9k41857
asked Nov 2 '17 at 15:41
BenBen
2,1631123
asked Nov 2 '17 at 15:41
BenBen
2,1631123
asked Nov 2 '17 at 15:41
BenBen
2,1631123
2,1631123
1
$begingroup$
Fromhelp Grassmannian:J = Grassmannian(2,5, CoefficientRing => ZZ/31, Variable => T).
$endgroup$
– Jan-Magnus Økland
Nov 2 '17 at 16:27
$begingroup$
@Jan-MagnusØkland Thanks a lot. Will try that out!
$endgroup$
– Ben
Nov 2 '17 at 16:31
$begingroup$
Let me provide the answer here: J=Grassmannian(2,5, CoefficientRing => ZZ/31); R=use ring J
$endgroup$
– Ben
Nov 2 '17 at 17:11
add a comment |
1
$begingroup$
Fromhelp Grassmannian:J = Grassmannian(2,5, CoefficientRing => ZZ/31, Variable => T).
$endgroup$
– Jan-Magnus Økland
Nov 2 '17 at 16:27
$begingroup$
@Jan-MagnusØkland Thanks a lot. Will try that out!
$endgroup$
– Ben
Nov 2 '17 at 16:31
$begingroup$
Let me provide the answer here: J=Grassmannian(2,5, CoefficientRing => ZZ/31); R=use ring J
$endgroup$
– Ben
Nov 2 '17 at 17:11
1
1
$begingroup$
From
help Grassmannian: J = Grassmannian(2,5, CoefficientRing => ZZ/31, Variable => T).$endgroup$
– Jan-Magnus Økland
Nov 2 '17 at 16:27
$begingroup$
From
help Grassmannian: J = Grassmannian(2,5, CoefficientRing => ZZ/31, Variable => T).$endgroup$
– Jan-Magnus Økland
Nov 2 '17 at 16:27
$begingroup$
@Jan-MagnusØkland Thanks a lot. Will try that out!
$endgroup$
– Ben
Nov 2 '17 at 16:31
$begingroup$
@Jan-MagnusØkland Thanks a lot. Will try that out!
$endgroup$
– Ben
Nov 2 '17 at 16:31
$begingroup$
Let me provide the answer here: J=Grassmannian(2,5, CoefficientRing => ZZ/31); R=use ring J
$endgroup$
– Ben
Nov 2 '17 at 17:11
$begingroup$
Let me provide the answer here: J=Grassmannian(2,5, CoefficientRing => ZZ/31); R=use ring J
$endgroup$
– Ben
Nov 2 '17 at 17:11
add a comment |
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1
$begingroup$
From
help Grassmannian:J = Grassmannian(2,5, CoefficientRing => ZZ/31, Variable => T).$endgroup$
– Jan-Magnus Økland
Nov 2 '17 at 16:27
$begingroup$
@Jan-MagnusØkland Thanks a lot. Will try that out!
$endgroup$
– Ben
Nov 2 '17 at 16:31
$begingroup$
Let me provide the answer here: J=Grassmannian(2,5, CoefficientRing => ZZ/31); R=use ring J
$endgroup$
– Ben
Nov 2 '17 at 17:11