how i can find Mod function in excel for large number
0
$begingroup$
How can I find these mods using MS Excel?
$$mbox{mod} (31514^{67},2285771)$$
$$mbox{mod} (60904^{67},2285771)$$
I think it is very large number. When I write it in MS Excel it gives me #NUM! What i should do?
modular-arithmetic
edited Dec 8 '18 at 14:40
saulspatz
14.5k21329
asked Dec 8 '18 at 14:13
karemkarem
12
$endgroup$
add a comment |
0
$begingroup$
How can I find these mods using MS Excel?
$$mbox{mod} (31514^{67},2285771)$$
$$mbox{mod} (60904^{67},2285771)$$
I think it is very large number. When I write it in MS Excel it gives me #NUM! What i should do?
modular-arithmetic
edited Dec 8 '18 at 14:40
saulspatz
14.5k21329
asked Dec 8 '18 at 14:13
karemkarem
12
$endgroup$
1
$begingroup$
Why not use a tool with large integer capable tool like SAGE, Mathematica, Maple, etc or wolframalpha.com/input/?i=mod(31514%5E67,2285771)? There are ways to do this in Excel, but they can be error prone. For example, mod(31514^2,2285771) and keep breaking it down.
$endgroup$
– Moo
Dec 8 '18 at 14:17
$begingroup$
I would suggest PARI/GP
$endgroup$
– Peter
Dec 8 '18 at 14:18
$begingroup$
but i should find it in excel my Doctor told me that first i should find 31514^2,31514^4,31514^8...........31514^66 then it will be easy to find the power 67 but i dont know how
$endgroup$
– karem
Dec 8 '18 at 14:20
$begingroup$
You should use the en.wikipedia.org/wiki/Exponentiation_by_squaring method and immediately reduce the products, see also en.wikipedia.org/wiki/Modular_exponentiation
$endgroup$
– gammatester
Dec 8 '18 at 14:27
$begingroup$
When the exponent has more than one digit, you have to put it in braces.$3^{67}$comes out as $3^{67}.$
$endgroup$
– saulspatz
Dec 8 '18 at 14:42
add a comment |
0
0
0
$begingroup$
How can I find these mods using MS Excel?
$$mbox{mod} (31514^{67},2285771)$$
$$mbox{mod} (60904^{67},2285771)$$
I think it is very large number. When I write it in MS Excel it gives me #NUM! What i should do?
modular-arithmetic
edited Dec 8 '18 at 14:40
saulspatz
14.5k21329
asked Dec 8 '18 at 14:13
karemkarem
12
$endgroup$
How can I find these mods using MS Excel?
$$mbox{mod} (31514^{67},2285771)$$
$$mbox{mod} (60904^{67},2285771)$$
I think it is very large number. When I write it in MS Excel it gives me #NUM! What i should do?
modular-arithmetic
modular-arithmetic
edited Dec 8 '18 at 14:40
saulspatz
14.5k21329
asked Dec 8 '18 at 14:13
karemkarem
12
edited Dec 8 '18 at 14:40
saulspatz
14.5k21329
asked Dec 8 '18 at 14:13
karemkarem
12
edited Dec 8 '18 at 14:40
saulspatz
14.5k21329
edited Dec 8 '18 at 14:40
saulspatz
14.5k21329
edited Dec 8 '18 at 14:40
saulspatz
14.5k21329
14.5k21329
asked Dec 8 '18 at 14:13
karemkarem
12
asked Dec 8 '18 at 14:13
karemkarem
12
asked Dec 8 '18 at 14:13
karemkarem
12
12
1
$begingroup$
Why not use a tool with large integer capable tool like SAGE, Mathematica, Maple, etc or wolframalpha.com/input/?i=mod(31514%5E67,2285771)? There are ways to do this in Excel, but they can be error prone. For example, mod(31514^2,2285771) and keep breaking it down.
$endgroup$
– Moo
Dec 8 '18 at 14:17
$begingroup$
I would suggest PARI/GP
$endgroup$
– Peter
Dec 8 '18 at 14:18
$begingroup$
but i should find it in excel my Doctor told me that first i should find 31514^2,31514^4,31514^8...........31514^66 then it will be easy to find the power 67 but i dont know how
$endgroup$
– karem
Dec 8 '18 at 14:20
$begingroup$
You should use the en.wikipedia.org/wiki/Exponentiation_by_squaring method and immediately reduce the products, see also en.wikipedia.org/wiki/Modular_exponentiation
$endgroup$
– gammatester
Dec 8 '18 at 14:27
$begingroup$
When the exponent has more than one digit, you have to put it in braces.$3^{67}$comes out as $3^{67}.$
$endgroup$
– saulspatz
Dec 8 '18 at 14:42
add a comment |
1
$begingroup$
Why not use a tool with large integer capable tool like SAGE, Mathematica, Maple, etc or wolframalpha.com/input/?i=mod(31514%5E67,2285771)? There are ways to do this in Excel, but they can be error prone. For example, mod(31514^2,2285771) and keep breaking it down.
$endgroup$
– Moo
Dec 8 '18 at 14:17
$begingroup$
I would suggest PARI/GP
$endgroup$
– Peter
Dec 8 '18 at 14:18
$begingroup$
but i should find it in excel my Doctor told me that first i should find 31514^2,31514^4,31514^8...........31514^66 then it will be easy to find the power 67 but i dont know how
$endgroup$
– karem
Dec 8 '18 at 14:20
$begingroup$
You should use the en.wikipedia.org/wiki/Exponentiation_by_squaring method and immediately reduce the products, see also en.wikipedia.org/wiki/Modular_exponentiation
$endgroup$
– gammatester
Dec 8 '18 at 14:27
$begingroup$
When the exponent has more than one digit, you have to put it in braces.$3^{67}$comes out as $3^{67}.$
$endgroup$
– saulspatz
Dec 8 '18 at 14:42
1
1
$begingroup$
Why not use a tool with large integer capable tool like SAGE, Mathematica, Maple, etc or wolframalpha.com/input/?i=mod(31514%5E67,2285771)? There are ways to do this in Excel, but they can be error prone. For example, mod(31514^2,2285771) and keep breaking it down.
$endgroup$
– Moo
Dec 8 '18 at 14:17
$begingroup$
Why not use a tool with large integer capable tool like SAGE, Mathematica, Maple, etc or wolframalpha.com/input/?i=mod(31514%5E67,2285771)? There are ways to do this in Excel, but they can be error prone. For example, mod(31514^2,2285771) and keep breaking it down.
$endgroup$
– Moo
Dec 8 '18 at 14:17
$begingroup$
I would suggest PARI/GP
$endgroup$
– Peter
Dec 8 '18 at 14:18
$begingroup$
I would suggest PARI/GP
$endgroup$
– Peter
Dec 8 '18 at 14:18
$begingroup$
but i should find it in excel my Doctor told me that first i should find 31514^2,31514^4,31514^8...........31514^66 then it will be easy to find the power 67 but i dont know how
$endgroup$
– karem
Dec 8 '18 at 14:20
$begingroup$
but i should find it in excel my Doctor told me that first i should find 31514^2,31514^4,31514^8...........31514^66 then it will be easy to find the power 67 but i dont know how
$endgroup$
– karem
Dec 8 '18 at 14:20
$begingroup$
You should use the en.wikipedia.org/wiki/Exponentiation_by_squaring method and immediately reduce the products, see also en.wikipedia.org/wiki/Modular_exponentiation
$endgroup$
– gammatester
Dec 8 '18 at 14:27
$begingroup$
You should use the en.wikipedia.org/wiki/Exponentiation_by_squaring method and immediately reduce the products, see also en.wikipedia.org/wiki/Modular_exponentiation
$endgroup$
– gammatester
Dec 8 '18 at 14:27
$begingroup$
When the exponent has more than one digit, you have to put it in braces.
$3^{67}$ comes out as $3^{67}.$$endgroup$
– saulspatz
Dec 8 '18 at 14:42
$begingroup$
When the exponent has more than one digit, you have to put it in braces.
$3^{67}$ comes out as $3^{67}.$$endgroup$
– saulspatz
Dec 8 '18 at 14:42
add a comment |
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1
$begingroup$
Why not use a tool with large integer capable tool like SAGE, Mathematica, Maple, etc or wolframalpha.com/input/?i=mod(31514%5E67,2285771)? There are ways to do this in Excel, but they can be error prone. For example, mod(31514^2,2285771) and keep breaking it down.
$endgroup$
– Moo
Dec 8 '18 at 14:17
$begingroup$
I would suggest PARI/GP
$endgroup$
– Peter
Dec 8 '18 at 14:18
$begingroup$
but i should find it in excel my Doctor told me that first i should find 31514^2,31514^4,31514^8...........31514^66 then it will be easy to find the power 67 but i dont know how
$endgroup$
– karem
Dec 8 '18 at 14:20
$begingroup$
You should use the en.wikipedia.org/wiki/Exponentiation_by_squaring method and immediately reduce the products, see also en.wikipedia.org/wiki/Modular_exponentiation
$endgroup$
– gammatester
Dec 8 '18 at 14:27
$begingroup$
When the exponent has more than one digit, you have to put it in braces.
$3^{67}$comes out as $3^{67}.$$endgroup$
– saulspatz
Dec 8 '18 at 14:42