Statistics: Point estimation












-1












$begingroup$


If we have a sample of $x=2$ from a $Po(6 cdot lambda)$ distribution.



How do we calculate $lambda*$ and $d(lambda*)$?



I think that $lambda* = frac{2}{6} = frac{1}{3} $ but I am not sure about the other one.






statistics parameter-estimation







share|cite|improve this question









$endgroup$












  • $begingroup$
    What is $lambda*$?
    $endgroup$
    – Sean Roberson
    Dec 4 '18 at 18:04










  • $begingroup$
    could you define $lambda*$ and $d(lambda*)$ more specifically?
    $endgroup$
    – MoonKnight
    Dec 4 '18 at 18:05










  • $begingroup$
    $lambda*$ is the parameter that we estimate and $d(lambda*)$ is the standard deviation.
    $endgroup$
    – Clone
    Dec 4 '18 at 18:20
















-1












$begingroup$


If we have a sample of $x=2$ from a $Po(6 cdot lambda)$ distribution.



How do we calculate $lambda*$ and $d(lambda*)$?



I think that $lambda* = frac{2}{6} = frac{1}{3} $ but I am not sure about the other one.






statistics parameter-estimation







share|cite|improve this question









$endgroup$












  • $begingroup$
    What is $lambda*$?
    $endgroup$
    – Sean Roberson
    Dec 4 '18 at 18:04










  • $begingroup$
    could you define $lambda*$ and $d(lambda*)$ more specifically?
    $endgroup$
    – MoonKnight
    Dec 4 '18 at 18:05










  • $begingroup$
    $lambda*$ is the parameter that we estimate and $d(lambda*)$ is the standard deviation.
    $endgroup$
    – Clone
    Dec 4 '18 at 18:20














-1












-1








-1


1



$begingroup$


If we have a sample of $x=2$ from a $Po(6 cdot lambda)$ distribution.



How do we calculate $lambda*$ and $d(lambda*)$?



I think that $lambda* = frac{2}{6} = frac{1}{3} $ but I am not sure about the other one.






statistics parameter-estimation







share|cite|improve this question









$endgroup$




If we have a sample of $x=2$ from a $Po(6 cdot lambda)$ distribution.



How do we calculate $lambda*$ and $d(lambda*)$?



I think that $lambda* = frac{2}{6} = frac{1}{3} $ but I am not sure about the other one.






statistics parameter-estimation




statistics parameter-estimation






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Dec 4 '18 at 17:57









CloneClone

99




99












  • $begingroup$
    What is $lambda*$?
    $endgroup$
    – Sean Roberson
    Dec 4 '18 at 18:04










  • $begingroup$
    could you define $lambda*$ and $d(lambda*)$ more specifically?
    $endgroup$
    – MoonKnight
    Dec 4 '18 at 18:05










  • $begingroup$
    $lambda*$ is the parameter that we estimate and $d(lambda*)$ is the standard deviation.
    $endgroup$
    – Clone
    Dec 4 '18 at 18:20


















  • $begingroup$
    What is $lambda*$?
    $endgroup$
    – Sean Roberson
    Dec 4 '18 at 18:04










  • $begingroup$
    could you define $lambda*$ and $d(lambda*)$ more specifically?
    $endgroup$
    – MoonKnight
    Dec 4 '18 at 18:05










  • $begingroup$
    $lambda*$ is the parameter that we estimate and $d(lambda*)$ is the standard deviation.
    $endgroup$
    – Clone
    Dec 4 '18 at 18:20
















$begingroup$
What is $lambda*$?
$endgroup$
– Sean Roberson
Dec 4 '18 at 18:04




$begingroup$
What is $lambda*$?
$endgroup$
– Sean Roberson
Dec 4 '18 at 18:04












$begingroup$
could you define $lambda*$ and $d(lambda*)$ more specifically?
$endgroup$
– MoonKnight
Dec 4 '18 at 18:05




$begingroup$
could you define $lambda*$ and $d(lambda*)$ more specifically?
$endgroup$
– MoonKnight
Dec 4 '18 at 18:05












$begingroup$
$lambda*$ is the parameter that we estimate and $d(lambda*)$ is the standard deviation.
$endgroup$
– Clone
Dec 4 '18 at 18:20




$begingroup$
$lambda*$ is the parameter that we estimate and $d(lambda*)$ is the standard deviation.
$endgroup$
– Clone
Dec 4 '18 at 18:20










1 Answer
1






active

oldest

votes


















0












$begingroup$

Whatever you may mean by $lambda *$ and $d(lambda *),$ which I suppose are defined in your text or notes, the following
information may be helpful.



If $X_1$ and $X_2$ are independently $mathsf{Pois}(6lambda),$ Then $$S = X_1 + X_2 sim mathsf{Pois}(12lambda).$$ Then $E(S) = 12lambda$ and $Var(S) = 12lambda.$



So $S$ is a point estimate of $12 lambda$ and
$S/12$ is a point estimate of $lambda.$






share|cite|improve this answer









$endgroup$













    Your Answer





    StackExchange.ifUsing("editor", function () {
    return StackExchange.using("mathjaxEditing", function () {
    StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
    StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
    });
    });
    }, "mathjax-editing");

    StackExchange.ready(function() {
    var channelOptions = {
    tags: "".split(" "),
    id: "69"
    };
    initTagRenderer("".split(" "), "".split(" "), channelOptions);

    StackExchange.using("externalEditor", function() {
    // Have to fire editor after snippets, if snippets enabled
    if (StackExchange.settings.snippets.snippetsEnabled) {
    StackExchange.using("snippets", function() {
    createEditor();
    });
    }
    else {
    createEditor();
    }
    });

    function createEditor() {
    StackExchange.prepareEditor({
    heartbeatType: 'answer',
    autoActivateHeartbeat: false,
    convertImagesToLinks: true,
    noModals: true,
    showLowRepImageUploadWarning: true,
    reputationToPostImages: 10,
    bindNavPrevention: true,
    postfix: "",
    imageUploader: {
    brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
    contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
    allowUrls: true
    },
    noCode: true, onDemand: true,
    discardSelector: ".discard-answer"
    ,immediatelyShowMarkdownHelp:true
    });


    }
    });














    draft saved

    draft discarded


















    StackExchange.ready(
    function () {
    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3025901%2fstatistics-point-estimation%23new-answer', 'question_page');
    }
    );

    Post as a guest















    Required, but never shown

























    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0












    $begingroup$

    Whatever you may mean by $lambda *$ and $d(lambda *),$ which I suppose are defined in your text or notes, the following
    information may be helpful.



    If $X_1$ and $X_2$ are independently $mathsf{Pois}(6lambda),$ Then $$S = X_1 + X_2 sim mathsf{Pois}(12lambda).$$ Then $E(S) = 12lambda$ and $Var(S) = 12lambda.$



    So $S$ is a point estimate of $12 lambda$ and
    $S/12$ is a point estimate of $lambda.$






    share|cite|improve this answer









    $endgroup$


















      0












      $begingroup$

      Whatever you may mean by $lambda *$ and $d(lambda *),$ which I suppose are defined in your text or notes, the following
      information may be helpful.



      If $X_1$ and $X_2$ are independently $mathsf{Pois}(6lambda),$ Then $$S = X_1 + X_2 sim mathsf{Pois}(12lambda).$$ Then $E(S) = 12lambda$ and $Var(S) = 12lambda.$



      So $S$ is a point estimate of $12 lambda$ and
      $S/12$ is a point estimate of $lambda.$






      share|cite|improve this answer









      $endgroup$
















        0












        0








        0





        $begingroup$

        Whatever you may mean by $lambda *$ and $d(lambda *),$ which I suppose are defined in your text or notes, the following
        information may be helpful.



        If $X_1$ and $X_2$ are independently $mathsf{Pois}(6lambda),$ Then $$S = X_1 + X_2 sim mathsf{Pois}(12lambda).$$ Then $E(S) = 12lambda$ and $Var(S) = 12lambda.$



        So $S$ is a point estimate of $12 lambda$ and
        $S/12$ is a point estimate of $lambda.$






        share|cite|improve this answer









        $endgroup$



        Whatever you may mean by $lambda *$ and $d(lambda *),$ which I suppose are defined in your text or notes, the following
        information may be helpful.



        If $X_1$ and $X_2$ are independently $mathsf{Pois}(6lambda),$ Then $$S = X_1 + X_2 sim mathsf{Pois}(12lambda).$$ Then $E(S) = 12lambda$ and $Var(S) = 12lambda.$



        So $S$ is a point estimate of $12 lambda$ and
        $S/12$ is a point estimate of $lambda.$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 4 '18 at 20:44









        BruceETBruceET

        35.3k71440




        35.3k71440






























            draft saved

            draft discarded




















































            Thanks for contributing an answer to Mathematics Stack Exchange!


            • Please be sure to answer the question. Provide details and share your research!

            But avoid …



            • Asking for help, clarification, or responding to other answers.

            • Making statements based on opinion; back them up with references or personal experience.


            Use MathJax to format equations. MathJax reference.


            To learn more, see our tips on writing great answers.




            draft saved


            draft discarded














            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3025901%2fstatistics-point-estimation%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown





















































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown

































            Required, but never shown














            Required, but never shown












            Required, but never shown







            Required, but never shown







            -

            Popular posts from this blog

            Quarter-circle Tiles

            Image
            up vote 0 down vote favorite I have $99$ identical square tiles, each with a quarter-circle drawn on it like this: [asy] size(1.5cm); draw(Arc((2,0),1,90,180),red+1); draw((0,0)--(2,0)--(2,2)--(0,2)--(0,0)); [/asy] When I arrange the tiles in a $9times 11$ rectangular grid, each with a random orientation, what is the expected value of the number of full circles I form? I think this problem has to do with finding the chance any given 2x2 square has a circle, but I can't find it. expected-value share | cite | improve this question asked Nov 20 at 15:03 6minecraftninja 1 2
            Read more

            build a pushdown automaton that recognizes the reverse language of a given pushdown automaton?

            Image
            0 I think it's similiar to NFAs. I replace the finite states of the given automaton for start-states for my new automaton. I do it with $epsilon$ -transition from the start state to the actual finite states of the given automaton. The start state of the given automaton will be my accepting(finite) state of my new one. All transitions will be reversed of course to recognize the reversed word. But how do I have to change the stack of the pushdown automaton? That's tricky. formal-languages automata context-free-grammar share | cite | improve this question edited Nov 29 '18 at 14:20 joee
            Read more

            Mont Emei

            Image
            Mont Emei.mw-parser-output .entete.map{background-image:url("//upload.wikimedia.org/wikipedia/commons/7/7a/Picto_infobox_map.png")} Vue du sommet Wanfo du mont Emei Géographie Altitude 3 099  m , Wanfo Coordonnées 29° 31′ 11″ nord, 103° 19′ 57″ est Administration Pays   Chine Province Sichuan Ville-préfecture Leshan Géolocalisation sur la carte : Sichuan Mont Emei Géolocalisation sur la carte : Chine Mont Emei modifier   Paysage panoramique du mont Emei, incluant le paysage panoramique du grand Bouddha de Leshan *   Patrimoine mondial de l'UNESCO Passerelle en bois sur le versant ouest Pays   Chine Subdivision Sichuan Type Mixte Critères (iv) (vi) (x) Superficie 15 400 ha Numéro d’identification 779 Zone géographique Asie et Pacifique  ** Année d’inscription 1996 (20 e session) * Descriptif officiel UNESCO ** Classification géog
            Read more