How do I transform $-2tan x + sec^2 x $ into the form $(a +b tan x)^2$?
$begingroup$
How does $frac{1}{cos^2 x}$ translate into $tan^2$? I felt like I missed a formula or so, but what?
It obviously asks to turn it into quadratic form of $tan,$ but I’m lacking $sin^2$ .
algebra-precalculus trigonometry
edited Dec 14 '18 at 15:19
Andrews
3901317
asked Dec 14 '18 at 10:53
WangcincayWangcincay
463
$endgroup$
add a comment |
$begingroup$
How does $frac{1}{cos^2 x}$ translate into $tan^2$? I felt like I missed a formula or so, but what?
It obviously asks to turn it into quadratic form of $tan,$ but I’m lacking $sin^2$ .
algebra-precalculus trigonometry
edited Dec 14 '18 at 15:19
Andrews
3901317
asked Dec 14 '18 at 10:53
WangcincayWangcincay
463
$endgroup$
add a comment |
$begingroup$
How does $frac{1}{cos^2 x}$ translate into $tan^2$? I felt like I missed a formula or so, but what?
It obviously asks to turn it into quadratic form of $tan,$ but I’m lacking $sin^2$ .
algebra-precalculus trigonometry
edited Dec 14 '18 at 15:19
Andrews
3901317
asked Dec 14 '18 at 10:53
WangcincayWangcincay
463
$endgroup$
How does $frac{1}{cos^2 x}$ translate into $tan^2$? I felt like I missed a formula or so, but what?
It obviously asks to turn it into quadratic form of $tan,$ but I’m lacking $sin^2$ .
algebra-precalculus trigonometry
algebra-precalculus trigonometry
edited Dec 14 '18 at 15:19
Andrews
3901317
asked Dec 14 '18 at 10:53
WangcincayWangcincay
463
edited Dec 14 '18 at 15:19
Andrews
3901317
asked Dec 14 '18 at 10:53
WangcincayWangcincay
463
edited Dec 14 '18 at 15:19
Andrews
3901317
edited Dec 14 '18 at 15:19
Andrews
3901317
edited Dec 14 '18 at 15:19
Andrews
3901317
3901317
asked Dec 14 '18 at 10:53
WangcincayWangcincay
463
asked Dec 14 '18 at 10:53
WangcincayWangcincay
463
asked Dec 14 '18 at 10:53
WangcincayWangcincay
463
463
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Hint: Use the following well-known identity
$$sec^2 x = 1+tan^2 x$$
which yields
$$-2tan x+tan^2 x+1$$
answered Dec 14 '18 at 10:55
KM101KM101
5,9251524
$endgroup$
add a comment |
$begingroup$
You may use the identity
$$ sec^2 x = 1 + tan^2 x $$
answered Dec 14 '18 at 10:57
Ken HungKen Hung
613
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
});
});
}, "mathjax-editing");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3039213%2fhow-do-i-transform-2-tan-x-sec2-x-into-the-form-a-b-tan-x2%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Hint: Use the following well-known identity
$$sec^2 x = 1+tan^2 x$$
which yields
$$-2tan x+tan^2 x+1$$
answered Dec 14 '18 at 10:55
KM101KM101
5,9251524
$endgroup$
add a comment |
$begingroup$
Hint: Use the following well-known identity
$$sec^2 x = 1+tan^2 x$$
which yields
$$-2tan x+tan^2 x+1$$
answered Dec 14 '18 at 10:55
KM101KM101
5,9251524
$endgroup$
add a comment |
$begingroup$
Hint: Use the following well-known identity
$$sec^2 x = 1+tan^2 x$$
which yields
$$-2tan x+tan^2 x+1$$
answered Dec 14 '18 at 10:55
KM101KM101
5,9251524
$endgroup$
Hint: Use the following well-known identity
$$sec^2 x = 1+tan^2 x$$
which yields
$$-2tan x+tan^2 x+1$$
answered Dec 14 '18 at 10:55
KM101KM101
5,9251524
answered Dec 14 '18 at 10:55
KM101KM101
5,9251524
answered Dec 14 '18 at 10:55
KM101KM101
5,9251524
answered Dec 14 '18 at 10:55
KM101KM101
5,9251524
5,9251524
add a comment |
add a comment |
$begingroup$
You may use the identity
$$ sec^2 x = 1 + tan^2 x $$
answered Dec 14 '18 at 10:57
Ken HungKen Hung
613
$endgroup$
add a comment |
$begingroup$
You may use the identity
$$ sec^2 x = 1 + tan^2 x $$
answered Dec 14 '18 at 10:57
Ken HungKen Hung
613
$endgroup$
add a comment |
$begingroup$
You may use the identity
$$ sec^2 x = 1 + tan^2 x $$
answered Dec 14 '18 at 10:57
Ken HungKen Hung
613
$endgroup$
You may use the identity
$$ sec^2 x = 1 + tan^2 x $$
answered Dec 14 '18 at 10:57
Ken HungKen Hung
613
answered Dec 14 '18 at 10:57
Ken HungKen Hung
613
answered Dec 14 '18 at 10:57
Ken HungKen Hung
613
answered Dec 14 '18 at 10:57
Ken HungKen Hung
613
613
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3039213%2fhow-do-i-transform-2-tan-x-sec2-x-into-the-form-a-b-tan-x2%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
