The sum of two non-units of a ring $R$ is a non-unit implies that the Jacobson radical is maximal.












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My problem is: If the sum of to non-units in a ring $R$ is non-unit, then the Jacobson radical $J(R)$ is maximal. I need help please. I have no idea how to start.
I thought that if the set of all non-units is an ideal of $R$, then it turns to be the unique maximal left ideal of $R$ and so it is $J(R)$.










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  • $begingroup$
    Can you show that this implies the set of non-units is an ideal?
    $endgroup$
    – Lord Shark the Unknown
    Dec 24 '18 at 21:52
















1












$begingroup$


My problem is: If the sum of to non-units in a ring $R$ is non-unit, then the Jacobson radical $J(R)$ is maximal. I need help please. I have no idea how to start.
I thought that if the set of all non-units is an ideal of $R$, then it turns to be the unique maximal left ideal of $R$ and so it is $J(R)$.










share|cite|improve this question









$endgroup$












  • $begingroup$
    Can you show that this implies the set of non-units is an ideal?
    $endgroup$
    – Lord Shark the Unknown
    Dec 24 '18 at 21:52














1












1








1





$begingroup$


My problem is: If the sum of to non-units in a ring $R$ is non-unit, then the Jacobson radical $J(R)$ is maximal. I need help please. I have no idea how to start.
I thought that if the set of all non-units is an ideal of $R$, then it turns to be the unique maximal left ideal of $R$ and so it is $J(R)$.










share|cite|improve this question









$endgroup$




My problem is: If the sum of to non-units in a ring $R$ is non-unit, then the Jacobson radical $J(R)$ is maximal. I need help please. I have no idea how to start.
I thought that if the set of all non-units is an ideal of $R$, then it turns to be the unique maximal left ideal of $R$ and so it is $J(R)$.







noncommutative-algebra






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asked Dec 24 '18 at 21:50









Hussein EidHussein Eid

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  • $begingroup$
    Can you show that this implies the set of non-units is an ideal?
    $endgroup$
    – Lord Shark the Unknown
    Dec 24 '18 at 21:52


















  • $begingroup$
    Can you show that this implies the set of non-units is an ideal?
    $endgroup$
    – Lord Shark the Unknown
    Dec 24 '18 at 21:52
















$begingroup$
Can you show that this implies the set of non-units is an ideal?
$endgroup$
– Lord Shark the Unknown
Dec 24 '18 at 21:52




$begingroup$
Can you show that this implies the set of non-units is an ideal?
$endgroup$
– Lord Shark the Unknown
Dec 24 '18 at 21:52










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