Chord of a Circle [closed]
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Simple question regarding chords in a circle.
Is the midpoint of a circle's chord always perpendicular to the circle's centre?
geometry circle
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closed as off-topic by Saad, Abcd, Cesareo, Daniel McLaury, John Bentin Jan 6 at 19:37
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Abcd, Cesareo
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
$begingroup$
Simple question regarding chords in a circle.
Is the midpoint of a circle's chord always perpendicular to the circle's centre?
geometry circle
$endgroup$
closed as off-topic by Saad, Abcd, Cesareo, Daniel McLaury, John Bentin Jan 6 at 19:37
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Abcd, Cesareo
If this question can be reworded to fit the rules in the help center, please edit the question.
3
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A point cannot be perpendicular to anything. The perpendicular bisector of a chord indeed always passes through the circle's center, though.
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– David G. Stork
Jan 6 at 7:51
1
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What do you mean by a point being perpendicular to another point?
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– Anurag A
Jan 6 at 7:51
add a comment |
$begingroup$
Simple question regarding chords in a circle.
Is the midpoint of a circle's chord always perpendicular to the circle's centre?
geometry circle
$endgroup$
Simple question regarding chords in a circle.
Is the midpoint of a circle's chord always perpendicular to the circle's centre?
geometry circle
geometry circle
edited Jan 6 at 10:01
Michael Rozenberg
107k1894199
107k1894199
asked Jan 6 at 7:49
nicknick
334
334
closed as off-topic by Saad, Abcd, Cesareo, Daniel McLaury, John Bentin Jan 6 at 19:37
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Abcd, Cesareo
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Saad, Abcd, Cesareo, Daniel McLaury, John Bentin Jan 6 at 19:37
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Abcd, Cesareo
If this question can be reworded to fit the rules in the help center, please edit the question.
3
$begingroup$
A point cannot be perpendicular to anything. The perpendicular bisector of a chord indeed always passes through the circle's center, though.
$endgroup$
– David G. Stork
Jan 6 at 7:51
1
$begingroup$
What do you mean by a point being perpendicular to another point?
$endgroup$
– Anurag A
Jan 6 at 7:51
add a comment |
3
$begingroup$
A point cannot be perpendicular to anything. The perpendicular bisector of a chord indeed always passes through the circle's center, though.
$endgroup$
– David G. Stork
Jan 6 at 7:51
1
$begingroup$
What do you mean by a point being perpendicular to another point?
$endgroup$
– Anurag A
Jan 6 at 7:51
3
3
$begingroup$
A point cannot be perpendicular to anything. The perpendicular bisector of a chord indeed always passes through the circle's center, though.
$endgroup$
– David G. Stork
Jan 6 at 7:51
$begingroup$
A point cannot be perpendicular to anything. The perpendicular bisector of a chord indeed always passes through the circle's center, though.
$endgroup$
– David G. Stork
Jan 6 at 7:51
1
1
$begingroup$
What do you mean by a point being perpendicular to another point?
$endgroup$
– Anurag A
Jan 6 at 7:51
$begingroup$
What do you mean by a point being perpendicular to another point?
$endgroup$
– Anurag A
Jan 6 at 7:51
add a comment |
2 Answers
2
active
oldest
votes
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The theorem says that: Any line drawn from the center that bisects a chord is perpendicular to the chord. Your statement is missing the word "line" and also it will be perpendicular to the chord instead of circle's centre.
Hope this helps.
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add a comment |
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Let $AB$ be our chord with midpoint $M$ and $O$ be the center of the circle.
If your question is "Is $OMperp AB$ true?" so the answer is "no".
For the counterexample take $AB$ is a diameter of the circle and take another diameter, which is not perpendicular to $AB$.
If our chord $AB$ is not diameter of the circle so $OMperp AB$, of course.
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add a comment |
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The theorem says that: Any line drawn from the center that bisects a chord is perpendicular to the chord. Your statement is missing the word "line" and also it will be perpendicular to the chord instead of circle's centre.
Hope this helps.
$endgroup$
add a comment |
$begingroup$
The theorem says that: Any line drawn from the center that bisects a chord is perpendicular to the chord. Your statement is missing the word "line" and also it will be perpendicular to the chord instead of circle's centre.
Hope this helps.
$endgroup$
add a comment |
$begingroup$
The theorem says that: Any line drawn from the center that bisects a chord is perpendicular to the chord. Your statement is missing the word "line" and also it will be perpendicular to the chord instead of circle's centre.
Hope this helps.
$endgroup$
The theorem says that: Any line drawn from the center that bisects a chord is perpendicular to the chord. Your statement is missing the word "line" and also it will be perpendicular to the chord instead of circle's centre.
Hope this helps.
answered Jan 6 at 7:57
user629353
add a comment |
add a comment |
$begingroup$
Let $AB$ be our chord with midpoint $M$ and $O$ be the center of the circle.
If your question is "Is $OMperp AB$ true?" so the answer is "no".
For the counterexample take $AB$ is a diameter of the circle and take another diameter, which is not perpendicular to $AB$.
If our chord $AB$ is not diameter of the circle so $OMperp AB$, of course.
$endgroup$
add a comment |
$begingroup$
Let $AB$ be our chord with midpoint $M$ and $O$ be the center of the circle.
If your question is "Is $OMperp AB$ true?" so the answer is "no".
For the counterexample take $AB$ is a diameter of the circle and take another diameter, which is not perpendicular to $AB$.
If our chord $AB$ is not diameter of the circle so $OMperp AB$, of course.
$endgroup$
add a comment |
$begingroup$
Let $AB$ be our chord with midpoint $M$ and $O$ be the center of the circle.
If your question is "Is $OMperp AB$ true?" so the answer is "no".
For the counterexample take $AB$ is a diameter of the circle and take another diameter, which is not perpendicular to $AB$.
If our chord $AB$ is not diameter of the circle so $OMperp AB$, of course.
$endgroup$
Let $AB$ be our chord with midpoint $M$ and $O$ be the center of the circle.
If your question is "Is $OMperp AB$ true?" so the answer is "no".
For the counterexample take $AB$ is a diameter of the circle and take another diameter, which is not perpendicular to $AB$.
If our chord $AB$ is not diameter of the circle so $OMperp AB$, of course.
answered Jan 6 at 9:08
Michael RozenbergMichael Rozenberg
107k1894199
107k1894199
add a comment |
add a comment |
3
$begingroup$
A point cannot be perpendicular to anything. The perpendicular bisector of a chord indeed always passes through the circle's center, though.
$endgroup$
– David G. Stork
Jan 6 at 7:51
1
$begingroup$
What do you mean by a point being perpendicular to another point?
$endgroup$
– Anurag A
Jan 6 at 7:51