solving exponential function with linear function











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I want to solve the solutions to x for below equation.



For, $a,b,c,dinmathbb{R}$, $x^a(bx+c) = d$.



Is it possible to express the solution of $x$ with $a,b,c,d$ for this equation? If possible, how can I find it?










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  • 1




    Even when $a$ is a positive integer you cannot solve it explicitly.
    – Kavi Rama Murthy
    Nov 19 at 5:44










  • @KaviRamaMurthy then, is there any way to get an approximated solution of $x$?
    – kyub
    Nov 19 at 5:52










  • Only a numerical method would work. This is not an equation that would yield a closed form solution.
    – Rebellos
    Nov 19 at 6:03










  • Numerical schemes could be regula falsi or newton's method. However to which solution the scheme converges (and if it converges at all) is highly dependent on the starting values and the explicit values of $a,b,c,d$. Especially the value of $a$ is crucial for the behaviour.
    – maxmilgram
    Nov 19 at 6:36

















up vote
0
down vote

favorite












I want to solve the solutions to x for below equation.



For, $a,b,c,dinmathbb{R}$, $x^a(bx+c) = d$.



Is it possible to express the solution of $x$ with $a,b,c,d$ for this equation? If possible, how can I find it?










share|cite|improve this question


















  • 1




    Even when $a$ is a positive integer you cannot solve it explicitly.
    – Kavi Rama Murthy
    Nov 19 at 5:44










  • @KaviRamaMurthy then, is there any way to get an approximated solution of $x$?
    – kyub
    Nov 19 at 5:52










  • Only a numerical method would work. This is not an equation that would yield a closed form solution.
    – Rebellos
    Nov 19 at 6:03










  • Numerical schemes could be regula falsi or newton's method. However to which solution the scheme converges (and if it converges at all) is highly dependent on the starting values and the explicit values of $a,b,c,d$. Especially the value of $a$ is crucial for the behaviour.
    – maxmilgram
    Nov 19 at 6:36















up vote
0
down vote

favorite









up vote
0
down vote

favorite











I want to solve the solutions to x for below equation.



For, $a,b,c,dinmathbb{R}$, $x^a(bx+c) = d$.



Is it possible to express the solution of $x$ with $a,b,c,d$ for this equation? If possible, how can I find it?










share|cite|improve this question













I want to solve the solutions to x for below equation.



For, $a,b,c,dinmathbb{R}$, $x^a(bx+c) = d$.



Is it possible to express the solution of $x$ with $a,b,c,d$ for this equation? If possible, how can I find it?







algebra-precalculus






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Nov 19 at 5:42









kyub

325




325








  • 1




    Even when $a$ is a positive integer you cannot solve it explicitly.
    – Kavi Rama Murthy
    Nov 19 at 5:44










  • @KaviRamaMurthy then, is there any way to get an approximated solution of $x$?
    – kyub
    Nov 19 at 5:52










  • Only a numerical method would work. This is not an equation that would yield a closed form solution.
    – Rebellos
    Nov 19 at 6:03










  • Numerical schemes could be regula falsi or newton's method. However to which solution the scheme converges (and if it converges at all) is highly dependent on the starting values and the explicit values of $a,b,c,d$. Especially the value of $a$ is crucial for the behaviour.
    – maxmilgram
    Nov 19 at 6:36
















  • 1




    Even when $a$ is a positive integer you cannot solve it explicitly.
    – Kavi Rama Murthy
    Nov 19 at 5:44










  • @KaviRamaMurthy then, is there any way to get an approximated solution of $x$?
    – kyub
    Nov 19 at 5:52










  • Only a numerical method would work. This is not an equation that would yield a closed form solution.
    – Rebellos
    Nov 19 at 6:03










  • Numerical schemes could be regula falsi or newton's method. However to which solution the scheme converges (and if it converges at all) is highly dependent on the starting values and the explicit values of $a,b,c,d$. Especially the value of $a$ is crucial for the behaviour.
    – maxmilgram
    Nov 19 at 6:36










1




1




Even when $a$ is a positive integer you cannot solve it explicitly.
– Kavi Rama Murthy
Nov 19 at 5:44




Even when $a$ is a positive integer you cannot solve it explicitly.
– Kavi Rama Murthy
Nov 19 at 5:44












@KaviRamaMurthy then, is there any way to get an approximated solution of $x$?
– kyub
Nov 19 at 5:52




@KaviRamaMurthy then, is there any way to get an approximated solution of $x$?
– kyub
Nov 19 at 5:52












Only a numerical method would work. This is not an equation that would yield a closed form solution.
– Rebellos
Nov 19 at 6:03




Only a numerical method would work. This is not an equation that would yield a closed form solution.
– Rebellos
Nov 19 at 6:03












Numerical schemes could be regula falsi or newton's method. However to which solution the scheme converges (and if it converges at all) is highly dependent on the starting values and the explicit values of $a,b,c,d$. Especially the value of $a$ is crucial for the behaviour.
– maxmilgram
Nov 19 at 6:36






Numerical schemes could be regula falsi or newton's method. However to which solution the scheme converges (and if it converges at all) is highly dependent on the starting values and the explicit values of $a,b,c,d$. Especially the value of $a$ is crucial for the behaviour.
– maxmilgram
Nov 19 at 6:36

















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