Edit text file to add space
up vote
3
down vote
favorite
I have a text file which looks like this
../pool/main/a/aalib/libaa1_1.4p5-44build2_amd64.deb
../pool/main/a/accountsservice/accountsservice_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/gir1.2-accountsservice-1.0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/libaccountsservice0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/acl/acl_2.2.52-3build1_amd64.deb
../pool/main/a/acl/libacl1_2.2.52-3build1_amd64.deb
../pool/main/a/acl/libacl1-dev_2.2.52-3build1_amd64.deb
../pool/main/a/acpid/acpid_2.0.28-1ubuntu1_amd64.deb
../pool/main/a/acpi-support/acpi-support_0.142_amd64.deb
../pool/main/a/adduser/adduser_3.116ubuntu1_all.deb
../pool/main/a/adium-theme-ubuntu/adium-theme-ubuntu_0.3.4-0ubuntu4_all.deb
../pool/main/a/advancecomp/advancecomp_2.1-1_amd64.deb
../pool/main/a/adwaita-icon-theme/adwaita-icon-theme_3.28.0-1ubuntu1_all.deb
../pool/main/a/aisleriot/aisleriot_3.22.5-1_amd64.deb
../pool/main/a/alabaster/python3-alabaster_0.7.8-1_all.deb
../pool/main/a/alembic/alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/python3-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/python-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alsa-driver/alsa-base_1.0.25+dfsg-0ubuntu5_all.deb
../pool/main/a/alsa-driver/linux-sound-base_1.0.25+dfsg-0ubuntu5_all.deb
I want to add space between last slash and name of deb package file e.g.
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
I tried using sed but couldn't get it right.
bash 18.04 sed awk
add a comment |
up vote
3
down vote
favorite
I have a text file which looks like this
../pool/main/a/aalib/libaa1_1.4p5-44build2_amd64.deb
../pool/main/a/accountsservice/accountsservice_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/gir1.2-accountsservice-1.0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/libaccountsservice0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/acl/acl_2.2.52-3build1_amd64.deb
../pool/main/a/acl/libacl1_2.2.52-3build1_amd64.deb
../pool/main/a/acl/libacl1-dev_2.2.52-3build1_amd64.deb
../pool/main/a/acpid/acpid_2.0.28-1ubuntu1_amd64.deb
../pool/main/a/acpi-support/acpi-support_0.142_amd64.deb
../pool/main/a/adduser/adduser_3.116ubuntu1_all.deb
../pool/main/a/adium-theme-ubuntu/adium-theme-ubuntu_0.3.4-0ubuntu4_all.deb
../pool/main/a/advancecomp/advancecomp_2.1-1_amd64.deb
../pool/main/a/adwaita-icon-theme/adwaita-icon-theme_3.28.0-1ubuntu1_all.deb
../pool/main/a/aisleriot/aisleriot_3.22.5-1_amd64.deb
../pool/main/a/alabaster/python3-alabaster_0.7.8-1_all.deb
../pool/main/a/alembic/alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/python3-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/python-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alsa-driver/alsa-base_1.0.25+dfsg-0ubuntu5_all.deb
../pool/main/a/alsa-driver/linux-sound-base_1.0.25+dfsg-0ubuntu5_all.deb
I want to add space between last slash and name of deb package file e.g.
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
I tried using sed but couldn't get it right.
bash 18.04 sed awk
add a comment |
up vote
3
down vote
favorite
up vote
3
down vote
favorite
I have a text file which looks like this
../pool/main/a/aalib/libaa1_1.4p5-44build2_amd64.deb
../pool/main/a/accountsservice/accountsservice_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/gir1.2-accountsservice-1.0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/libaccountsservice0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/acl/acl_2.2.52-3build1_amd64.deb
../pool/main/a/acl/libacl1_2.2.52-3build1_amd64.deb
../pool/main/a/acl/libacl1-dev_2.2.52-3build1_amd64.deb
../pool/main/a/acpid/acpid_2.0.28-1ubuntu1_amd64.deb
../pool/main/a/acpi-support/acpi-support_0.142_amd64.deb
../pool/main/a/adduser/adduser_3.116ubuntu1_all.deb
../pool/main/a/adium-theme-ubuntu/adium-theme-ubuntu_0.3.4-0ubuntu4_all.deb
../pool/main/a/advancecomp/advancecomp_2.1-1_amd64.deb
../pool/main/a/adwaita-icon-theme/adwaita-icon-theme_3.28.0-1ubuntu1_all.deb
../pool/main/a/aisleriot/aisleriot_3.22.5-1_amd64.deb
../pool/main/a/alabaster/python3-alabaster_0.7.8-1_all.deb
../pool/main/a/alembic/alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/python3-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/python-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alsa-driver/alsa-base_1.0.25+dfsg-0ubuntu5_all.deb
../pool/main/a/alsa-driver/linux-sound-base_1.0.25+dfsg-0ubuntu5_all.deb
I want to add space between last slash and name of deb package file e.g.
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
I tried using sed but couldn't get it right.
bash 18.04 sed awk
I have a text file which looks like this
../pool/main/a/aalib/libaa1_1.4p5-44build2_amd64.deb
../pool/main/a/accountsservice/accountsservice_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/gir1.2-accountsservice-1.0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/libaccountsservice0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/acl/acl_2.2.52-3build1_amd64.deb
../pool/main/a/acl/libacl1_2.2.52-3build1_amd64.deb
../pool/main/a/acl/libacl1-dev_2.2.52-3build1_amd64.deb
../pool/main/a/acpid/acpid_2.0.28-1ubuntu1_amd64.deb
../pool/main/a/acpi-support/acpi-support_0.142_amd64.deb
../pool/main/a/adduser/adduser_3.116ubuntu1_all.deb
../pool/main/a/adium-theme-ubuntu/adium-theme-ubuntu_0.3.4-0ubuntu4_all.deb
../pool/main/a/advancecomp/advancecomp_2.1-1_amd64.deb
../pool/main/a/adwaita-icon-theme/adwaita-icon-theme_3.28.0-1ubuntu1_all.deb
../pool/main/a/aisleriot/aisleriot_3.22.5-1_amd64.deb
../pool/main/a/alabaster/python3-alabaster_0.7.8-1_all.deb
../pool/main/a/alembic/alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/python3-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/python-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alsa-driver/alsa-base_1.0.25+dfsg-0ubuntu5_all.deb
../pool/main/a/alsa-driver/linux-sound-base_1.0.25+dfsg-0ubuntu5_all.deb
I want to add space between last slash and name of deb package file e.g.
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
I tried using sed but couldn't get it right.
bash 18.04 sed awk
bash 18.04 sed awk
asked Dec 2 at 22:40
harshit
949
949
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
up vote
4
down vote
accepted
sed 's_.*/_& _'
s
ubstitutes everything until the last slash (.*/
, regexes are greedy) with itself followed by a space (&␣
) in every line.
Example run
Provided your text file is called file
and resides in the current working directory:
$ <file sed 's_.*/_& _'
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
../pool/main/a/accountsservice/ accountsservice_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ gir1.2-accountsservice-1.0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ libaccountsservice0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/acl/ acl_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1-dev_2.2.52-3build1_amd64.deb
../pool/main/a/acpid/ acpid_2.0.28-1ubuntu1_amd64.deb
../pool/main/a/acpi-support/ acpi-support_0.142_amd64.deb
../pool/main/a/adduser/ adduser_3.116ubuntu1_all.deb
../pool/main/a/adium-theme-ubuntu/ adium-theme-ubuntu_0.3.4-0ubuntu4_all.deb
../pool/main/a/advancecomp/ advancecomp_2.1-1_amd64.deb
../pool/main/a/adwaita-icon-theme/ adwaita-icon-theme_3.28.0-1ubuntu1_all.deb
../pool/main/a/aisleriot/ aisleriot_3.22.5-1_amd64.deb
../pool/main/a/alabaster/ python3-alabaster_0.7.8-1_all.deb
../pool/main/a/alembic/ alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/ python3-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/ python-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alsa-driver/ alsa-base_1.0.25+dfsg-0ubuntu5_all.deb
../pool/main/a/alsa-driver/ linux-sound-base_1.0.25+dfsg-0ubuntu5_all.deb
To alter the file in-place, use:
sed -i 's_.*/_& _' file
add a comment |
up vote
4
down vote
What can be done is to use pattern grouping and take advantage of greedy globbing:
$ echo '../pool/main/a/aalib/libaa1_1.4p5-44build2_amd64.deb' |
> sed -r 's/(^.*/)(.*.deb)/1 2/'
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
The parenthesis correspond to integer
items in replacement pattern. Thus first parenthesis will greedily match everything to the last slash and the second - everything after that
With input file in the question:
$ sed -r 's/(^.*/)(.*.deb)/1 2/' pool.txt
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
../pool/main/a/accountsservice/ accountsservice_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ gir1.2-accountsservice-1.0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ libaccountsservice0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/acl/ acl_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1_2.2.52-3build1_amd64.deb
<...and so on and so forth...>
add a comment |
up vote
1
down vote
And for good measure an awk version
$ awk -F/ '{ OFS="/"; $NF=" "$NF; print; }' /tmp/XXXX
[...]
../pool/main/a/acl/ libacl1_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1-dev_2.2.52-3build1_amd64.deb
[...]
-F/
set the field separator to be/
- for each line of input, taken from
/tmp/XXXX
which contains your data
- set output field separator to be
/
as well
NF
contains the number of fields, so$NF
is the last field- Set the last field to be a space string concatenated with the original last field value
- and print
- set output field separator to be
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
4
down vote
accepted
sed 's_.*/_& _'
s
ubstitutes everything until the last slash (.*/
, regexes are greedy) with itself followed by a space (&␣
) in every line.
Example run
Provided your text file is called file
and resides in the current working directory:
$ <file sed 's_.*/_& _'
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
../pool/main/a/accountsservice/ accountsservice_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ gir1.2-accountsservice-1.0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ libaccountsservice0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/acl/ acl_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1-dev_2.2.52-3build1_amd64.deb
../pool/main/a/acpid/ acpid_2.0.28-1ubuntu1_amd64.deb
../pool/main/a/acpi-support/ acpi-support_0.142_amd64.deb
../pool/main/a/adduser/ adduser_3.116ubuntu1_all.deb
../pool/main/a/adium-theme-ubuntu/ adium-theme-ubuntu_0.3.4-0ubuntu4_all.deb
../pool/main/a/advancecomp/ advancecomp_2.1-1_amd64.deb
../pool/main/a/adwaita-icon-theme/ adwaita-icon-theme_3.28.0-1ubuntu1_all.deb
../pool/main/a/aisleriot/ aisleriot_3.22.5-1_amd64.deb
../pool/main/a/alabaster/ python3-alabaster_0.7.8-1_all.deb
../pool/main/a/alembic/ alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/ python3-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/ python-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alsa-driver/ alsa-base_1.0.25+dfsg-0ubuntu5_all.deb
../pool/main/a/alsa-driver/ linux-sound-base_1.0.25+dfsg-0ubuntu5_all.deb
To alter the file in-place, use:
sed -i 's_.*/_& _' file
add a comment |
up vote
4
down vote
accepted
sed 's_.*/_& _'
s
ubstitutes everything until the last slash (.*/
, regexes are greedy) with itself followed by a space (&␣
) in every line.
Example run
Provided your text file is called file
and resides in the current working directory:
$ <file sed 's_.*/_& _'
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
../pool/main/a/accountsservice/ accountsservice_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ gir1.2-accountsservice-1.0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ libaccountsservice0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/acl/ acl_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1-dev_2.2.52-3build1_amd64.deb
../pool/main/a/acpid/ acpid_2.0.28-1ubuntu1_amd64.deb
../pool/main/a/acpi-support/ acpi-support_0.142_amd64.deb
../pool/main/a/adduser/ adduser_3.116ubuntu1_all.deb
../pool/main/a/adium-theme-ubuntu/ adium-theme-ubuntu_0.3.4-0ubuntu4_all.deb
../pool/main/a/advancecomp/ advancecomp_2.1-1_amd64.deb
../pool/main/a/adwaita-icon-theme/ adwaita-icon-theme_3.28.0-1ubuntu1_all.deb
../pool/main/a/aisleriot/ aisleriot_3.22.5-1_amd64.deb
../pool/main/a/alabaster/ python3-alabaster_0.7.8-1_all.deb
../pool/main/a/alembic/ alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/ python3-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/ python-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alsa-driver/ alsa-base_1.0.25+dfsg-0ubuntu5_all.deb
../pool/main/a/alsa-driver/ linux-sound-base_1.0.25+dfsg-0ubuntu5_all.deb
To alter the file in-place, use:
sed -i 's_.*/_& _' file
add a comment |
up vote
4
down vote
accepted
up vote
4
down vote
accepted
sed 's_.*/_& _'
s
ubstitutes everything until the last slash (.*/
, regexes are greedy) with itself followed by a space (&␣
) in every line.
Example run
Provided your text file is called file
and resides in the current working directory:
$ <file sed 's_.*/_& _'
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
../pool/main/a/accountsservice/ accountsservice_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ gir1.2-accountsservice-1.0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ libaccountsservice0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/acl/ acl_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1-dev_2.2.52-3build1_amd64.deb
../pool/main/a/acpid/ acpid_2.0.28-1ubuntu1_amd64.deb
../pool/main/a/acpi-support/ acpi-support_0.142_amd64.deb
../pool/main/a/adduser/ adduser_3.116ubuntu1_all.deb
../pool/main/a/adium-theme-ubuntu/ adium-theme-ubuntu_0.3.4-0ubuntu4_all.deb
../pool/main/a/advancecomp/ advancecomp_2.1-1_amd64.deb
../pool/main/a/adwaita-icon-theme/ adwaita-icon-theme_3.28.0-1ubuntu1_all.deb
../pool/main/a/aisleriot/ aisleriot_3.22.5-1_amd64.deb
../pool/main/a/alabaster/ python3-alabaster_0.7.8-1_all.deb
../pool/main/a/alembic/ alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/ python3-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/ python-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alsa-driver/ alsa-base_1.0.25+dfsg-0ubuntu5_all.deb
../pool/main/a/alsa-driver/ linux-sound-base_1.0.25+dfsg-0ubuntu5_all.deb
To alter the file in-place, use:
sed -i 's_.*/_& _' file
sed 's_.*/_& _'
s
ubstitutes everything until the last slash (.*/
, regexes are greedy) with itself followed by a space (&␣
) in every line.
Example run
Provided your text file is called file
and resides in the current working directory:
$ <file sed 's_.*/_& _'
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
../pool/main/a/accountsservice/ accountsservice_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ gir1.2-accountsservice-1.0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ libaccountsservice0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/acl/ acl_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1-dev_2.2.52-3build1_amd64.deb
../pool/main/a/acpid/ acpid_2.0.28-1ubuntu1_amd64.deb
../pool/main/a/acpi-support/ acpi-support_0.142_amd64.deb
../pool/main/a/adduser/ adduser_3.116ubuntu1_all.deb
../pool/main/a/adium-theme-ubuntu/ adium-theme-ubuntu_0.3.4-0ubuntu4_all.deb
../pool/main/a/advancecomp/ advancecomp_2.1-1_amd64.deb
../pool/main/a/adwaita-icon-theme/ adwaita-icon-theme_3.28.0-1ubuntu1_all.deb
../pool/main/a/aisleriot/ aisleriot_3.22.5-1_amd64.deb
../pool/main/a/alabaster/ python3-alabaster_0.7.8-1_all.deb
../pool/main/a/alembic/ alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/ python3-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alembic/ python-alembic_0.9.3-2ubuntu1_all.deb
../pool/main/a/alsa-driver/ alsa-base_1.0.25+dfsg-0ubuntu5_all.deb
../pool/main/a/alsa-driver/ linux-sound-base_1.0.25+dfsg-0ubuntu5_all.deb
To alter the file in-place, use:
sed -i 's_.*/_& _' file
edited Dec 2 at 23:02
answered Dec 2 at 22:49
dessert
21.8k55896
21.8k55896
add a comment |
add a comment |
up vote
4
down vote
What can be done is to use pattern grouping and take advantage of greedy globbing:
$ echo '../pool/main/a/aalib/libaa1_1.4p5-44build2_amd64.deb' |
> sed -r 's/(^.*/)(.*.deb)/1 2/'
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
The parenthesis correspond to integer
items in replacement pattern. Thus first parenthesis will greedily match everything to the last slash and the second - everything after that
With input file in the question:
$ sed -r 's/(^.*/)(.*.deb)/1 2/' pool.txt
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
../pool/main/a/accountsservice/ accountsservice_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ gir1.2-accountsservice-1.0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ libaccountsservice0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/acl/ acl_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1_2.2.52-3build1_amd64.deb
<...and so on and so forth...>
add a comment |
up vote
4
down vote
What can be done is to use pattern grouping and take advantage of greedy globbing:
$ echo '../pool/main/a/aalib/libaa1_1.4p5-44build2_amd64.deb' |
> sed -r 's/(^.*/)(.*.deb)/1 2/'
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
The parenthesis correspond to integer
items in replacement pattern. Thus first parenthesis will greedily match everything to the last slash and the second - everything after that
With input file in the question:
$ sed -r 's/(^.*/)(.*.deb)/1 2/' pool.txt
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
../pool/main/a/accountsservice/ accountsservice_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ gir1.2-accountsservice-1.0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ libaccountsservice0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/acl/ acl_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1_2.2.52-3build1_amd64.deb
<...and so on and so forth...>
add a comment |
up vote
4
down vote
up vote
4
down vote
What can be done is to use pattern grouping and take advantage of greedy globbing:
$ echo '../pool/main/a/aalib/libaa1_1.4p5-44build2_amd64.deb' |
> sed -r 's/(^.*/)(.*.deb)/1 2/'
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
The parenthesis correspond to integer
items in replacement pattern. Thus first parenthesis will greedily match everything to the last slash and the second - everything after that
With input file in the question:
$ sed -r 's/(^.*/)(.*.deb)/1 2/' pool.txt
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
../pool/main/a/accountsservice/ accountsservice_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ gir1.2-accountsservice-1.0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ libaccountsservice0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/acl/ acl_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1_2.2.52-3build1_amd64.deb
<...and so on and so forth...>
What can be done is to use pattern grouping and take advantage of greedy globbing:
$ echo '../pool/main/a/aalib/libaa1_1.4p5-44build2_amd64.deb' |
> sed -r 's/(^.*/)(.*.deb)/1 2/'
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
The parenthesis correspond to integer
items in replacement pattern. Thus first parenthesis will greedily match everything to the last slash and the second - everything after that
With input file in the question:
$ sed -r 's/(^.*/)(.*.deb)/1 2/' pool.txt
../pool/main/a/aalib/ libaa1_1.4p5-44build2_amd64.deb
../pool/main/a/accountsservice/ accountsservice_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ gir1.2-accountsservice-1.0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/accountsservice/ libaccountsservice0_0.6.45-1ubuntu1_amd64.deb
../pool/main/a/acl/ acl_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1_2.2.52-3build1_amd64.deb
<...and so on and so forth...>
edited Dec 2 at 22:59
answered Dec 2 at 22:49
Sergiy Kolodyazhnyy
69k9143303
69k9143303
add a comment |
add a comment |
up vote
1
down vote
And for good measure an awk version
$ awk -F/ '{ OFS="/"; $NF=" "$NF; print; }' /tmp/XXXX
[...]
../pool/main/a/acl/ libacl1_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1-dev_2.2.52-3build1_amd64.deb
[...]
-F/
set the field separator to be/
- for each line of input, taken from
/tmp/XXXX
which contains your data
- set output field separator to be
/
as well
NF
contains the number of fields, so$NF
is the last field- Set the last field to be a space string concatenated with the original last field value
- and print
- set output field separator to be
add a comment |
up vote
1
down vote
And for good measure an awk version
$ awk -F/ '{ OFS="/"; $NF=" "$NF; print; }' /tmp/XXXX
[...]
../pool/main/a/acl/ libacl1_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1-dev_2.2.52-3build1_amd64.deb
[...]
-F/
set the field separator to be/
- for each line of input, taken from
/tmp/XXXX
which contains your data
- set output field separator to be
/
as well
NF
contains the number of fields, so$NF
is the last field- Set the last field to be a space string concatenated with the original last field value
- and print
- set output field separator to be
add a comment |
up vote
1
down vote
up vote
1
down vote
And for good measure an awk version
$ awk -F/ '{ OFS="/"; $NF=" "$NF; print; }' /tmp/XXXX
[...]
../pool/main/a/acl/ libacl1_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1-dev_2.2.52-3build1_amd64.deb
[...]
-F/
set the field separator to be/
- for each line of input, taken from
/tmp/XXXX
which contains your data
- set output field separator to be
/
as well
NF
contains the number of fields, so$NF
is the last field- Set the last field to be a space string concatenated with the original last field value
- and print
- set output field separator to be
And for good measure an awk version
$ awk -F/ '{ OFS="/"; $NF=" "$NF; print; }' /tmp/XXXX
[...]
../pool/main/a/acl/ libacl1_2.2.52-3build1_amd64.deb
../pool/main/a/acl/ libacl1-dev_2.2.52-3build1_amd64.deb
[...]
-F/
set the field separator to be/
- for each line of input, taken from
/tmp/XXXX
which contains your data
- set output field separator to be
/
as well
NF
contains the number of fields, so$NF
is the last field- Set the last field to be a space string concatenated with the original last field value
- and print
- set output field separator to be
answered Dec 3 at 1:41
jonathanjo
1313
1313
add a comment |
add a comment |
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