Integral algebra problems
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I guess the integral part is irrelevant but can anybody tell me how
∫(u+1)√u*du
is equivalent to
∫u$^frac 32$ + u$^frac 12$*du ?
Should it not be
∫u*du + u$^frac 12$*du ?
∫u$^frac 32$ + u$^frac 12$*du is given to me as a solution but it doesn't make sense to me.
Thanks!
integration
asked Nov 23 at 0:43
M Do
124
add a comment |
up vote
0
down vote
favorite
I guess the integral part is irrelevant but can anybody tell me how
∫(u+1)√u*du
is equivalent to
∫u$^frac 32$ + u$^frac 12$*du ?
Should it not be
∫u*du + u$^frac 12$*du ?
∫u$^frac 32$ + u$^frac 12$*du is given to me as a solution but it doesn't make sense to me.
Thanks!
integration
asked Nov 23 at 0:43
M Do
124
2
It's just the distributive property. Note also that integration is linear so the two are equivalent.
– Sean Roberson
Nov 23 at 0:46
Both of the expressions are awkward, because they lack brackets. Enclose things in brackets and both of them will start making sense
– Yuriy S
Nov 23 at 0:56
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I guess the integral part is irrelevant but can anybody tell me how
∫(u+1)√u*du
is equivalent to
∫u$^frac 32$ + u$^frac 12$*du ?
Should it not be
∫u*du + u$^frac 12$*du ?
∫u$^frac 32$ + u$^frac 12$*du is given to me as a solution but it doesn't make sense to me.
Thanks!
integration
asked Nov 23 at 0:43
M Do
124
I guess the integral part is irrelevant but can anybody tell me how
∫(u+1)√u*du
is equivalent to
∫u$^frac 32$ + u$^frac 12$*du ?
Should it not be
∫u*du + u$^frac 12$*du ?
∫u$^frac 32$ + u$^frac 12$*du is given to me as a solution but it doesn't make sense to me.
Thanks!
integration
integration
asked Nov 23 at 0:43
M Do
124
asked Nov 23 at 0:43
M Do
124
asked Nov 23 at 0:43
M Do
124
asked Nov 23 at 0:43
M Do
124
asked Nov 23 at 0:43
M Do
124
124
2
It's just the distributive property. Note also that integration is linear so the two are equivalent.
– Sean Roberson
Nov 23 at 0:46
Both of the expressions are awkward, because they lack brackets. Enclose things in brackets and both of them will start making sense
– Yuriy S
Nov 23 at 0:56
add a comment |
2
It's just the distributive property. Note also that integration is linear so the two are equivalent.
– Sean Roberson
Nov 23 at 0:46
Both of the expressions are awkward, because they lack brackets. Enclose things in brackets and both of them will start making sense
– Yuriy S
Nov 23 at 0:56
2
2
It's just the distributive property. Note also that integration is linear so the two are equivalent.
– Sean Roberson
Nov 23 at 0:46
It's just the distributive property. Note also that integration is linear so the two are equivalent.
– Sean Roberson
Nov 23 at 0:46
Both of the expressions are awkward, because they lack brackets. Enclose things in brackets and both of them will start making sense
– Yuriy S
Nov 23 at 0:56
Both of the expressions are awkward, because they lack brackets. Enclose things in brackets and both of them will start making sense
– Yuriy S
Nov 23 at 0:56
add a comment |
1 Answer
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Note that $(a+b)c = ac + bc$ and $sqrt{x}=x^{frac{1}{2}}$. Apply those to the given equation and the result follows.
answered Nov 23 at 0:56
CyclotomicField
2,1641312
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1 Answer
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1 Answer
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active
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up vote
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Note that $(a+b)c = ac + bc$ and $sqrt{x}=x^{frac{1}{2}}$. Apply those to the given equation and the result follows.
answered Nov 23 at 0:56
CyclotomicField
2,1641312
add a comment |
up vote
2
down vote
Note that $(a+b)c = ac + bc$ and $sqrt{x}=x^{frac{1}{2}}$. Apply those to the given equation and the result follows.
answered Nov 23 at 0:56
CyclotomicField
2,1641312
add a comment |
up vote
2
down vote
up vote
2
down vote
Note that $(a+b)c = ac + bc$ and $sqrt{x}=x^{frac{1}{2}}$. Apply those to the given equation and the result follows.
answered Nov 23 at 0:56
CyclotomicField
2,1641312
Note that $(a+b)c = ac + bc$ and $sqrt{x}=x^{frac{1}{2}}$. Apply those to the given equation and the result follows.
answered Nov 23 at 0:56
CyclotomicField
2,1641312
answered Nov 23 at 0:56
CyclotomicField
2,1641312
answered Nov 23 at 0:56
CyclotomicField
2,1641312
answered Nov 23 at 0:56
CyclotomicField
2,1641312
2,1641312
add a comment |
add a comment |
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2
It's just the distributive property. Note also that integration is linear so the two are equivalent.
– Sean Roberson
Nov 23 at 0:46
Both of the expressions are awkward, because they lack brackets. Enclose things in brackets and both of them will start making sense
– Yuriy S
Nov 23 at 0:56