Alternatives of lists vs Alternatives of strings











up vote
4
down vote

favorite












Obviously I am missing something obvious.



I have:



lis = {"a"}|{"b"}|{"c"}


but I want:



lis2 = "a"|"b"|"c"


Thanks as always for suggestions...






list-manipulation







share|improve this question


























    up vote
    4
    down vote

    favorite












    Obviously I am missing something obvious.



    I have:



    lis = {"a"}|{"b"}|{"c"}


    but I want:



    lis2 = "a"|"b"|"c"


    Thanks as always for suggestions...






    list-manipulation







    share|improve this question
























      up vote
      4
      down vote

      favorite









      up vote
      4
      down vote

      favorite











      Obviously I am missing something obvious.



      I have:



      lis = {"a"}|{"b"}|{"c"}


      but I want:



      lis2 = "a"|"b"|"c"


      Thanks as always for suggestions...






      list-manipulation







      share|improve this question













      Obviously I am missing something obvious.



      I have:



      lis = {"a"}|{"b"}|{"c"}


      but I want:



      lis2 = "a"|"b"|"c"


      Thanks as always for suggestions...






      list-manipulation




      list-manipulation






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 2 days ago









      Suite401

      959312




      959312






















          2 Answers
          2






          active

          oldest

          votes

















          up vote
          6
          down vote



          accepted










          Use lis[[All, 1]] or First /@ list. See Part and First.






          share|improve this answer




























            up vote
            6
            down vote













            You can also Apply (@@@) Sequence at level 1:



            Sequence @@@ lis



            "a" | "b" | "c"




            Also



            ## & @@@ lis



            "a" | "b" | "c"




            Alternatively, use ReplaceAll to replace List with Sequence: 



            lis /. List -> Sequence



            "a" | "b" | "c"




            Additional methods:



            MapAt[Sequence &, lis, {All, 0}]
            
ReplacePart[lis, {_, 0} :> Sequence]
            
lis[[All, 0]] = Sequence; lis


            all give "a" | "b" | "c".






            share|improve this answer























              Your Answer





              StackExchange.ifUsing("editor", function () {
              return StackExchange.using("mathjaxEditing", function () {
              StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
              StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
              });
              });
              }, "mathjax-editing");

              StackExchange.ready(function() {
              var channelOptions = {
              tags: "".split(" "),
              id: "387"
              };
              initTagRenderer("".split(" "), "".split(" "), channelOptions);

              StackExchange.using("externalEditor", function() {
              // Have to fire editor after snippets, if snippets enabled
              if (StackExchange.settings.snippets.snippetsEnabled) {
              StackExchange.using("snippets", function() {
              createEditor();
              });
              }
              else {
              createEditor();
              }
              });

              function createEditor() {
              StackExchange.prepareEditor({
              heartbeatType: 'answer',
              convertImagesToLinks: false,
              noModals: true,
              showLowRepImageUploadWarning: true,
              reputationToPostImages: null,
              bindNavPrevention: true,
              postfix: "",
              imageUploader: {
              brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
              contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
              allowUrls: true
              },
              onDemand: true,
              discardSelector: ".discard-answer"
              ,immediatelyShowMarkdownHelp:true
              });


              }
              });














               

              draft saved


              draft discarded


















              StackExchange.ready(
              function () {
              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f186640%2falternatives-of-lists-vs-alternatives-of-strings%23new-answer', 'question_page');
              }
              );

              Post as a guest















              Required, but never shown

























              2 Answers
              2






              active

              oldest

              votes








              2 Answers
              2






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes








              up vote
              6
              down vote



              accepted










              Use lis[[All, 1]] or First /@ list. See Part and First.






              share|improve this answer

























                up vote
                6
                down vote



                accepted










                Use lis[[All, 1]] or First /@ list. See Part and First.






                share|improve this answer























                  up vote
                  6
                  down vote



                  accepted







                  up vote
                  6
                  down vote



                  accepted






                  Use lis[[All, 1]] or First /@ list. See Part and First.






                  share|improve this answer












                  Use lis[[All, 1]] or First /@ list. See Part and First.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 2 days ago









                  Szabolcs

                  157k13430917




                  157k13430917






















                      up vote
                      6
                      down vote













                      You can also Apply (@@@) Sequence at level 1:



                      Sequence @@@ lis



                      "a" | "b" | "c"




                      Also



                      ## & @@@ lis



                      "a" | "b" | "c"




                      Alternatively, use ReplaceAll to replace List with Sequence: 



                      lis /. List -> Sequence



                      "a" | "b" | "c"




                      Additional methods:



                      MapAt[Sequence &, lis, {All, 0}]
                      
ReplacePart[lis, {_, 0} :> Sequence]
                      
lis[[All, 0]] = Sequence; lis


                      all give "a" | "b" | "c".






                      share|improve this answer



























                        up vote
                        6
                        down vote













                        You can also Apply (@@@) Sequence at level 1:



                        Sequence @@@ lis



                        "a" | "b" | "c"




                        Also



                        ## & @@@ lis



                        "a" | "b" | "c"




                        Alternatively, use ReplaceAll to replace List with Sequence: 



                        lis /. List -> Sequence



                        "a" | "b" | "c"




                        Additional methods:



                        MapAt[Sequence &, lis, {All, 0}]
                        
ReplacePart[lis, {_, 0} :> Sequence]
                        
lis[[All, 0]] = Sequence; lis


                        all give "a" | "b" | "c".






                        share|improve this answer

























                          up vote
                          6
                          down vote










                          up vote
                          6
                          down vote









                          You can also Apply (@@@) Sequence at level 1:



                          Sequence @@@ lis



                          "a" | "b" | "c"




                          Also



                          ## & @@@ lis



                          "a" | "b" | "c"




                          Alternatively, use ReplaceAll to replace List with Sequence: 



                          lis /. List -> Sequence



                          "a" | "b" | "c"




                          Additional methods:



                          MapAt[Sequence &, lis, {All, 0}]
                          
ReplacePart[lis, {_, 0} :> Sequence]
                          
lis[[All, 0]] = Sequence; lis


                          all give "a" | "b" | "c".






                          share|improve this answer














                          You can also Apply (@@@) Sequence at level 1:



                          Sequence @@@ lis



                          "a" | "b" | "c"




                          Also



                          ## & @@@ lis



                          "a" | "b" | "c"




                          Alternatively, use ReplaceAll to replace List with Sequence: 



                          lis /. List -> Sequence



                          "a" | "b" | "c"




                          Additional methods:



                          MapAt[Sequence &, lis, {All, 0}]
                          
ReplacePart[lis, {_, 0} :> Sequence]
                          
lis[[All, 0]] = Sequence; lis


                          all give "a" | "b" | "c".







                          share|improve this answer














                          share|improve this answer



                          share|improve this answer








                          edited yesterday

























                          answered 2 days ago









                          kglr

                          173k8194400




                          173k8194400






























                               

                              draft saved


                              draft discarded



















































                               


                              draft saved


                              draft discarded














                              StackExchange.ready(
                              function () {
                              StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f186640%2falternatives-of-lists-vs-alternatives-of-strings%23new-answer', 'question_page');
                              }
                              );

                              Post as a guest















                              Required, but never shown





















































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown

































                              Required, but never shown














                              Required, but never shown












                              Required, but never shown







                              Required, but never shown







                              -

                              Popular posts from this blog

                              Quarter-circle Tiles

                              Image
                              up vote 0 down vote favorite I have $99$ identical square tiles, each with a quarter-circle drawn on it like this: [asy] size(1.5cm); draw(Arc((2,0),1,90,180),red+1); draw((0,0)--(2,0)--(2,2)--(0,2)--(0,0)); [/asy] When I arrange the tiles in a $9times 11$ rectangular grid, each with a random orientation, what is the expected value of the number of full circles I form? I think this problem has to do with finding the chance any given 2x2 square has a circle, but I can't find it. expected-value share | cite | improve this question asked Nov 20 at 15:03 6minecraftninja 1 2
                              Read more

                              build a pushdown automaton that recognizes the reverse language of a given pushdown automaton?

                              Image
                              0 I think it's similiar to NFAs. I replace the finite states of the given automaton for start-states for my new automaton. I do it with $epsilon$ -transition from the start state to the actual finite states of the given automaton. The start state of the given automaton will be my accepting(finite) state of my new one. All transitions will be reversed of course to recognize the reversed word. But how do I have to change the stack of the pushdown automaton? That's tricky. formal-languages automata context-free-grammar share | cite | improve this question edited Nov 29 '18 at 14:20 joee
                              Read more

                              Mont Emei

                              Image
                              Mont Emei.mw-parser-output .entete.map{background-image:url("//upload.wikimedia.org/wikipedia/commons/7/7a/Picto_infobox_map.png")} Vue du sommet Wanfo du mont Emei Géographie Altitude 3 099  m , Wanfo Coordonnées 29° 31′ 11″ nord, 103° 19′ 57″ est Administration Pays   Chine Province Sichuan Ville-préfecture Leshan Géolocalisation sur la carte : Sichuan Mont Emei Géolocalisation sur la carte : Chine Mont Emei modifier   Paysage panoramique du mont Emei, incluant le paysage panoramique du grand Bouddha de Leshan *   Patrimoine mondial de l'UNESCO Passerelle en bois sur le versant ouest Pays   Chine Subdivision Sichuan Type Mixte Critères (iv) (vi) (x) Superficie 15 400 ha Numéro d’identification 779 Zone géographique Asie et Pacifique  ** Année d’inscription 1996 (20 e session) * Descriptif officiel UNESCO ** Classification géog
                              Read more