Convergence Uniform / Holder continuous
up vote
0
down vote
favorite
Let $f: R->R$ be a $2L-periodic$ function. Suppose there are 'The positive constant and $α$ $∈$ $(0, 1)$
such that
$| f (x) - f (y) | ≤ A(| x - y |^α + | x - y |) $∀ x,y $ and ∈ [-L, L].$
Show that $Sn$ converges uniformly to $f$ in any compact set of $R$
I was thinking of proving that $ f $ is continuous holder,
soon satisfies the Dini test, then $ Sn $ converges to $ f $.
But how can I ensure that convergence is uniform?
Should I use the fact that f is bounded variation?
real-analysis fourier-analysis
add a comment |
up vote
0
down vote
favorite
Let $f: R->R$ be a $2L-periodic$ function. Suppose there are 'The positive constant and $α$ $∈$ $(0, 1)$
such that
$| f (x) - f (y) | ≤ A(| x - y |^α + | x - y |) $∀ x,y $ and ∈ [-L, L].$
Show that $Sn$ converges uniformly to $f$ in any compact set of $R$
I was thinking of proving that $ f $ is continuous holder,
soon satisfies the Dini test, then $ Sn $ converges to $ f $.
But how can I ensure that convergence is uniform?
Should I use the fact that f is bounded variation?
real-analysis fourier-analysis
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Let $f: R->R$ be a $2L-periodic$ function. Suppose there are 'The positive constant and $α$ $∈$ $(0, 1)$
such that
$| f (x) - f (y) | ≤ A(| x - y |^α + | x - y |) $∀ x,y $ and ∈ [-L, L].$
Show that $Sn$ converges uniformly to $f$ in any compact set of $R$
I was thinking of proving that $ f $ is continuous holder,
soon satisfies the Dini test, then $ Sn $ converges to $ f $.
But how can I ensure that convergence is uniform?
Should I use the fact that f is bounded variation?
real-analysis fourier-analysis
Let $f: R->R$ be a $2L-periodic$ function. Suppose there are 'The positive constant and $α$ $∈$ $(0, 1)$
such that
$| f (x) - f (y) | ≤ A(| x - y |^α + | x - y |) $∀ x,y $ and ∈ [-L, L].$
Show that $Sn$ converges uniformly to $f$ in any compact set of $R$
I was thinking of proving that $ f $ is continuous holder,
soon satisfies the Dini test, then $ Sn $ converges to $ f $.
But how can I ensure that convergence is uniform?
Should I use the fact that f is bounded variation?
real-analysis fourier-analysis
real-analysis fourier-analysis
asked Nov 17 at 22:28
justlearningmath
175
175
add a comment |
add a comment |
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
active
oldest
votes
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3002892%2fconvergence-uniform-holder-continuous%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown