Can the help action trigger a Rogue's sneak attack?











up vote
4
down vote

favorite












Let's say that I determined the best course of action is using the Help action to give my Rogue buddy an advantage on his attack instead of attacking by myself. Would that attack then gain the sneak attack bonus since he's at attacking at advantage?






dnd-5e actions rogue sneak-attack helping







share|improve this question




















  • 3




    Possible duplicate of Can a Familiar aid a Rogue's Sneak Attack?
    – Luke
    2 days ago










  • This is a weird case... on the one hand, it seems like a distinct question being slightly more broad, but on the other, the answers clearly overlap
    – Ifusaso
    2 days ago










  • @Axoren The real question is, would someone looking for an answer to THIS question click on the other question. I'd say no.
    – Wesley Obenshain
    2 days ago






  • 1




    If anything, the other question is a duplicate of this one, as it's a more specific example of this more general question.
    – V2Blast
    2 days ago















up vote
4
down vote

favorite












Let's say that I determined the best course of action is using the Help action to give my Rogue buddy an advantage on his attack instead of attacking by myself. Would that attack then gain the sneak attack bonus since he's at attacking at advantage?






dnd-5e actions rogue sneak-attack helping







share|improve this question




















  • 3




    Possible duplicate of Can a Familiar aid a Rogue's Sneak Attack?
    – Luke
    2 days ago










  • This is a weird case... on the one hand, it seems like a distinct question being slightly more broad, but on the other, the answers clearly overlap
    – Ifusaso
    2 days ago










  • @Axoren The real question is, would someone looking for an answer to THIS question click on the other question. I'd say no.
    – Wesley Obenshain
    2 days ago






  • 1




    If anything, the other question is a duplicate of this one, as it's a more specific example of this more general question.
    – V2Blast
    2 days ago













up vote
4
down vote

favorite









up vote
4
down vote

favorite











Let's say that I determined the best course of action is using the Help action to give my Rogue buddy an advantage on his attack instead of attacking by myself. Would that attack then gain the sneak attack bonus since he's at attacking at advantage?






dnd-5e actions rogue sneak-attack helping







share|improve this question















Let's say that I determined the best course of action is using the Help action to give my Rogue buddy an advantage on his attack instead of attacking by myself. Would that attack then gain the sneak attack bonus since he's at attacking at advantage?






dnd-5e actions rogue sneak-attack helping




dnd-5e actions rogue sneak-attack helping






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 2 days ago









V2Blast

18.1k248114




18.1k248114










asked 2 days ago









Cyanic

4219




4219








  • 3




    Possible duplicate of Can a Familiar aid a Rogue's Sneak Attack?
    – Luke
    2 days ago










  • This is a weird case... on the one hand, it seems like a distinct question being slightly more broad, but on the other, the answers clearly overlap
    – Ifusaso
    2 days ago










  • @Axoren The real question is, would someone looking for an answer to THIS question click on the other question. I'd say no.
    – Wesley Obenshain
    2 days ago






  • 1




    If anything, the other question is a duplicate of this one, as it's a more specific example of this more general question.
    – V2Blast
    2 days ago














  • 3




    Possible duplicate of Can a Familiar aid a Rogue's Sneak Attack?
    – Luke
    2 days ago










  • This is a weird case... on the one hand, it seems like a distinct question being slightly more broad, but on the other, the answers clearly overlap
    – Ifusaso
    2 days ago










  • @Axoren The real question is, would someone looking for an answer to THIS question click on the other question. I'd say no.
    – Wesley Obenshain
    2 days ago






  • 1




    If anything, the other question is a duplicate of this one, as it's a more specific example of this more general question.
    – V2Blast
    2 days ago








3




3




Possible duplicate of Can a Familiar aid a Rogue's Sneak Attack?
– Luke
2 days ago




Possible duplicate of Can a Familiar aid a Rogue's Sneak Attack?
– Luke
2 days ago












This is a weird case... on the one hand, it seems like a distinct question being slightly more broad, but on the other, the answers clearly overlap
– Ifusaso
2 days ago




This is a weird case... on the one hand, it seems like a distinct question being slightly more broad, but on the other, the answers clearly overlap
– Ifusaso
2 days ago












@Axoren The real question is, would someone looking for an answer to THIS question click on the other question. I'd say no.
– Wesley Obenshain
2 days ago




@Axoren The real question is, would someone looking for an answer to THIS question click on the other question. I'd say no.
– Wesley Obenshain
2 days ago




1




1




If anything, the other question is a duplicate of this one, as it's a more specific example of this more general question.
– V2Blast
2 days ago




If anything, the other question is a duplicate of this one, as it's a more specific example of this more general question.
– V2Blast
2 days ago










1 Answer
1






active

oldest

votes

















up vote
16
down vote



accepted










Sneak Attack says:




Once per turn, you can deal an extra 1d6 damage to one creature you hit with an attack if you have advantage on the attack roll.




The Help action says:




If your ally attacks the target before your next turn, the first attack
roll is made with advantage.




Sneak Attack can be used if the attack roll is made with advantage (or an enemy of the target to be with 5 feet); the Help action gives that advantage, as long as the rogue is the first ally to attack the target (and the advantage isn't canceled out by disadvantage). It's that simple.






share|improve this answer























  • "as long as the rogue is the first ally to attack the target" - why is that? The wording seems to suggest you are aiding a specific ally, not just the next person attacking that target...
    – Chris
    2 days ago










  • Ah. rpg.stackexchange.com/questions/128393/… seems to answer my question. Strange that the wording is seemingly different in different places.
    – Chris
    2 days ago











Your Answer





StackExchange.ifUsing("editor", function () {
return StackExchange.using("mathjaxEditing", function () {
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["\$", "\$"]]);
});
});
}, "mathjax-editing");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "122"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});














 

draft saved


draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2frpg.stackexchange.com%2fquestions%2f136049%2fcan-the-help-action-trigger-a-rogues-sneak-attack%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes








up vote
16
down vote



accepted










Sneak Attack says:




Once per turn, you can deal an extra 1d6 damage to one creature you hit with an attack if you have advantage on the attack roll.




The Help action says:




If your ally attacks the target before your next turn, the first attack
roll is made with advantage.




Sneak Attack can be used if the attack roll is made with advantage (or an enemy of the target to be with 5 feet); the Help action gives that advantage, as long as the rogue is the first ally to attack the target (and the advantage isn't canceled out by disadvantage). It's that simple.






share|improve this answer























  • "as long as the rogue is the first ally to attack the target" - why is that? The wording seems to suggest you are aiding a specific ally, not just the next person attacking that target...
    – Chris
    2 days ago










  • Ah. rpg.stackexchange.com/questions/128393/… seems to answer my question. Strange that the wording is seemingly different in different places.
    – Chris
    2 days ago















up vote
16
down vote



accepted










Sneak Attack says:




Once per turn, you can deal an extra 1d6 damage to one creature you hit with an attack if you have advantage on the attack roll.




The Help action says:




If your ally attacks the target before your next turn, the first attack
roll is made with advantage.




Sneak Attack can be used if the attack roll is made with advantage (or an enemy of the target to be with 5 feet); the Help action gives that advantage, as long as the rogue is the first ally to attack the target (and the advantage isn't canceled out by disadvantage). It's that simple.






share|improve this answer























  • "as long as the rogue is the first ally to attack the target" - why is that? The wording seems to suggest you are aiding a specific ally, not just the next person attacking that target...
    – Chris
    2 days ago










  • Ah. rpg.stackexchange.com/questions/128393/… seems to answer my question. Strange that the wording is seemingly different in different places.
    – Chris
    2 days ago













up vote
16
down vote



accepted







up vote
16
down vote



accepted






Sneak Attack says:




Once per turn, you can deal an extra 1d6 damage to one creature you hit with an attack if you have advantage on the attack roll.




The Help action says:




If your ally attacks the target before your next turn, the first attack
roll is made with advantage.




Sneak Attack can be used if the attack roll is made with advantage (or an enemy of the target to be with 5 feet); the Help action gives that advantage, as long as the rogue is the first ally to attack the target (and the advantage isn't canceled out by disadvantage). It's that simple.






share|improve this answer














Sneak Attack says:




Once per turn, you can deal an extra 1d6 damage to one creature you hit with an attack if you have advantage on the attack roll.




The Help action says:




If your ally attacks the target before your next turn, the first attack
roll is made with advantage.




Sneak Attack can be used if the attack roll is made with advantage (or an enemy of the target to be with 5 feet); the Help action gives that advantage, as long as the rogue is the first ally to attack the target (and the advantage isn't canceled out by disadvantage). It's that simple.







share|improve this answer














share|improve this answer



share|improve this answer








edited 2 days ago









V2Blast

18.1k248114




18.1k248114










answered 2 days ago









Purple Monkey

37.3k7150231




37.3k7150231












  • "as long as the rogue is the first ally to attack the target" - why is that? The wording seems to suggest you are aiding a specific ally, not just the next person attacking that target...
    – Chris
    2 days ago










  • Ah. rpg.stackexchange.com/questions/128393/… seems to answer my question. Strange that the wording is seemingly different in different places.
    – Chris
    2 days ago


















  • "as long as the rogue is the first ally to attack the target" - why is that? The wording seems to suggest you are aiding a specific ally, not just the next person attacking that target...
    – Chris
    2 days ago










  • Ah. rpg.stackexchange.com/questions/128393/… seems to answer my question. Strange that the wording is seemingly different in different places.
    – Chris
    2 days ago
















"as long as the rogue is the first ally to attack the target" - why is that? The wording seems to suggest you are aiding a specific ally, not just the next person attacking that target...
– Chris
2 days ago




"as long as the rogue is the first ally to attack the target" - why is that? The wording seems to suggest you are aiding a specific ally, not just the next person attacking that target...
– Chris
2 days ago












Ah. rpg.stackexchange.com/questions/128393/… seems to answer my question. Strange that the wording is seemingly different in different places.
– Chris
2 days ago




Ah. rpg.stackexchange.com/questions/128393/… seems to answer my question. Strange that the wording is seemingly different in different places.
– Chris
2 days ago


















 

draft saved


draft discarded



















































 


draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2frpg.stackexchange.com%2fquestions%2f136049%2fcan-the-help-action-trigger-a-rogues-sneak-attack%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







-

Popular posts from this blog

Quarter-circle Tiles

Image
up vote 0 down vote favorite I have $99$ identical square tiles, each with a quarter-circle drawn on it like this: [asy] size(1.5cm); draw(Arc((2,0),1,90,180),red+1); draw((0,0)--(2,0)--(2,2)--(0,2)--(0,0)); [/asy] When I arrange the tiles in a $9times 11$ rectangular grid, each with a random orientation, what is the expected value of the number of full circles I form? I think this problem has to do with finding the chance any given 2x2 square has a circle, but I can't find it. expected-value share | cite | improve this question asked Nov 20 at 15:03 6minecraftninja 1 2
Read more

build a pushdown automaton that recognizes the reverse language of a given pushdown automaton?

Image
0 I think it's similiar to NFAs. I replace the finite states of the given automaton for start-states for my new automaton. I do it with $epsilon$ -transition from the start state to the actual finite states of the given automaton. The start state of the given automaton will be my accepting(finite) state of my new one. All transitions will be reversed of course to recognize the reversed word. But how do I have to change the stack of the pushdown automaton? That's tricky. formal-languages automata context-free-grammar share | cite | improve this question edited Nov 29 '18 at 14:20 joee
Read more

Mont Emei

Image
Mont Emei.mw-parser-output .entete.map{background-image:url("//upload.wikimedia.org/wikipedia/commons/7/7a/Picto_infobox_map.png")} Vue du sommet Wanfo du mont Emei Géographie Altitude 3 099  m , Wanfo Coordonnées 29° 31′ 11″ nord, 103° 19′ 57″ est Administration Pays   Chine Province Sichuan Ville-préfecture Leshan Géolocalisation sur la carte : Sichuan Mont Emei Géolocalisation sur la carte : Chine Mont Emei modifier   Paysage panoramique du mont Emei, incluant le paysage panoramique du grand Bouddha de Leshan *   Patrimoine mondial de l'UNESCO Passerelle en bois sur le versant ouest Pays   Chine Subdivision Sichuan Type Mixte Critères (iv) (vi) (x) Superficie 15 400 ha Numéro d’identification 779 Zone géographique Asie et Pacifique  ** Année d’inscription 1996 (20 e session) * Descriptif officiel UNESCO ** Classification géog
Read more