Jordan form corresponding to Discrete time impulse response.
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Which of the following discrete-time state-space models $(A,B,C,D)$ of the form
$x(t+1)=Ax(t)+Bu(t), quad y(t)=Cx(t)+Du(t), quad tin mathbb{N}$
with $A$ in jordan form has its impulse response given by
$h(t)=left{
begin{array}{ll}
delta(t-1)+2^{t-1} text{for} t = 1,2,3,...\
0 text{for} t = 0,\
end{array}
right.$
$quad$ where $delta = 0^t = left{
begin{array}{ll}
1 text{for} t = 0\
0 text{for} t = 1,2,3,...\
end{array}
right.$
Answer:
$A) quad left[ begin{array}{c|c} A&B \ hline C&D end{array} right] = left[ begin{array}{cc|c} 2&0 &1 \ 0&0&1 \ hline 1&1&0 end{array} right]$
$B) quad left[ begin{array}{c|c} A&B \ hline C&D end{array} right] = left[ begin{array}{cc|c} 1&1&1 \ 1&1&0 \ hline 2&0&0 end{array} right]$
$C) quad left[ begin{array}{c|c} A&B \ hline C&D end{array} right] = left[ begin{array}{c|c} 2&1 \ hline 1&0 end{array} right]$
$D) quad left[ begin{array}{c|c} A&B \ hline C&D end{array} right] = left[ begin{array}{cc|c} 2&0&0 \ 0&0&1 \ hline 1&0&0 end{array} right]$
$E) quad text{None of the above}$
I know that the DT impulse response output equals: $y(t) = CA^{t-1}B$
so $h(t) = CA^{t-1}B$.
Entering a few values of $t$ into $h(t)$
gives: $h(t) = 1 text{for} t = 1, $ $ h(t) = 2 text{for} t = 2, $ $h(t) = 4 text{for} t = 3, $ All answers fit this patern.
I know that $2^{t-1}$ means that the jordan form has at least a $2$ in it so $B$ is incorrect.
$A$ is the right answer, but I don't know how to get there.
linear-algebra control-theory linear-control
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up vote
0
down vote
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Which of the following discrete-time state-space models $(A,B,C,D)$ of the form
$x(t+1)=Ax(t)+Bu(t), quad y(t)=Cx(t)+Du(t), quad tin mathbb{N}$
with $A$ in jordan form has its impulse response given by
$h(t)=left{
begin{array}{ll}
delta(t-1)+2^{t-1} text{for} t = 1,2,3,...\
0 text{for} t = 0,\
end{array}
right.$
$quad$ where $delta = 0^t = left{
begin{array}{ll}
1 text{for} t = 0\
0 text{for} t = 1,2,3,...\
end{array}
right.$
Answer:
$A) quad left[ begin{array}{c|c} A&B \ hline C&D end{array} right] = left[ begin{array}{cc|c} 2&0 &1 \ 0&0&1 \ hline 1&1&0 end{array} right]$
$B) quad left[ begin{array}{c|c} A&B \ hline C&D end{array} right] = left[ begin{array}{cc|c} 1&1&1 \ 1&1&0 \ hline 2&0&0 end{array} right]$
$C) quad left[ begin{array}{c|c} A&B \ hline C&D end{array} right] = left[ begin{array}{c|c} 2&1 \ hline 1&0 end{array} right]$
$D) quad left[ begin{array}{c|c} A&B \ hline C&D end{array} right] = left[ begin{array}{cc|c} 2&0&0 \ 0&0&1 \ hline 1&0&0 end{array} right]$
$E) quad text{None of the above}$
I know that the DT impulse response output equals: $y(t) = CA^{t-1}B$
so $h(t) = CA^{t-1}B$.
Entering a few values of $t$ into $h(t)$
gives: $h(t) = 1 text{for} t = 1, $ $ h(t) = 2 text{for} t = 2, $ $h(t) = 4 text{for} t = 3, $ All answers fit this patern.
I know that $2^{t-1}$ means that the jordan form has at least a $2$ in it so $B$ is incorrect.
$A$ is the right answer, but I don't know how to get there.
linear-algebra control-theory linear-control
1
Your first value for the impulse response seems off, namely it should be $h(1)=2$. Did you also try evaluating $C,A^{t-1} B$ for any of the proposed solutions?
– Kwin van der Veen
Nov 16 at 5:11
for $t=1$, $CA^{t-1}B$ gives $A=B=2, C=1, D=0$ which leaves only $A$ and $B$ as possible answers. Entering further values of $t$ produces the same results for $A$ and $B$. The fact that $B$ does not have a $2$ in it makes $A$ the only correct answer. Thanks.
– user463102
17 hours ago
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
Which of the following discrete-time state-space models $(A,B,C,D)$ of the form
$x(t+1)=Ax(t)+Bu(t), quad y(t)=Cx(t)+Du(t), quad tin mathbb{N}$
with $A$ in jordan form has its impulse response given by
$h(t)=left{
begin{array}{ll}
delta(t-1)+2^{t-1} text{for} t = 1,2,3,...\
0 text{for} t = 0,\
end{array}
right.$
$quad$ where $delta = 0^t = left{
begin{array}{ll}
1 text{for} t = 0\
0 text{for} t = 1,2,3,...\
end{array}
right.$
Answer:
$A) quad left[ begin{array}{c|c} A&B \ hline C&D end{array} right] = left[ begin{array}{cc|c} 2&0 &1 \ 0&0&1 \ hline 1&1&0 end{array} right]$
$B) quad left[ begin{array}{c|c} A&B \ hline C&D end{array} right] = left[ begin{array}{cc|c} 1&1&1 \ 1&1&0 \ hline 2&0&0 end{array} right]$
$C) quad left[ begin{array}{c|c} A&B \ hline C&D end{array} right] = left[ begin{array}{c|c} 2&1 \ hline 1&0 end{array} right]$
$D) quad left[ begin{array}{c|c} A&B \ hline C&D end{array} right] = left[ begin{array}{cc|c} 2&0&0 \ 0&0&1 \ hline 1&0&0 end{array} right]$
$E) quad text{None of the above}$
I know that the DT impulse response output equals: $y(t) = CA^{t-1}B$
so $h(t) = CA^{t-1}B$.
Entering a few values of $t$ into $h(t)$
gives: $h(t) = 1 text{for} t = 1, $ $ h(t) = 2 text{for} t = 2, $ $h(t) = 4 text{for} t = 3, $ All answers fit this patern.
I know that $2^{t-1}$ means that the jordan form has at least a $2$ in it so $B$ is incorrect.
$A$ is the right answer, but I don't know how to get there.
linear-algebra control-theory linear-control
Which of the following discrete-time state-space models $(A,B,C,D)$ of the form
$x(t+1)=Ax(t)+Bu(t), quad y(t)=Cx(t)+Du(t), quad tin mathbb{N}$
with $A$ in jordan form has its impulse response given by
$h(t)=left{
begin{array}{ll}
delta(t-1)+2^{t-1} text{for} t = 1,2,3,...\
0 text{for} t = 0,\
end{array}
right.$
$quad$ where $delta = 0^t = left{
begin{array}{ll}
1 text{for} t = 0\
0 text{for} t = 1,2,3,...\
end{array}
right.$
Answer:
$A) quad left[ begin{array}{c|c} A&B \ hline C&D end{array} right] = left[ begin{array}{cc|c} 2&0 &1 \ 0&0&1 \ hline 1&1&0 end{array} right]$
$B) quad left[ begin{array}{c|c} A&B \ hline C&D end{array} right] = left[ begin{array}{cc|c} 1&1&1 \ 1&1&0 \ hline 2&0&0 end{array} right]$
$C) quad left[ begin{array}{c|c} A&B \ hline C&D end{array} right] = left[ begin{array}{c|c} 2&1 \ hline 1&0 end{array} right]$
$D) quad left[ begin{array}{c|c} A&B \ hline C&D end{array} right] = left[ begin{array}{cc|c} 2&0&0 \ 0&0&1 \ hline 1&0&0 end{array} right]$
$E) quad text{None of the above}$
I know that the DT impulse response output equals: $y(t) = CA^{t-1}B$
so $h(t) = CA^{t-1}B$.
Entering a few values of $t$ into $h(t)$
gives: $h(t) = 1 text{for} t = 1, $ $ h(t) = 2 text{for} t = 2, $ $h(t) = 4 text{for} t = 3, $ All answers fit this patern.
I know that $2^{t-1}$ means that the jordan form has at least a $2$ in it so $B$ is incorrect.
$A$ is the right answer, but I don't know how to get there.
linear-algebra control-theory linear-control
linear-algebra control-theory linear-control
asked Nov 15 at 11:11
user463102
13813
13813
1
Your first value for the impulse response seems off, namely it should be $h(1)=2$. Did you also try evaluating $C,A^{t-1} B$ for any of the proposed solutions?
– Kwin van der Veen
Nov 16 at 5:11
for $t=1$, $CA^{t-1}B$ gives $A=B=2, C=1, D=0$ which leaves only $A$ and $B$ as possible answers. Entering further values of $t$ produces the same results for $A$ and $B$. The fact that $B$ does not have a $2$ in it makes $A$ the only correct answer. Thanks.
– user463102
17 hours ago
add a comment |
1
Your first value for the impulse response seems off, namely it should be $h(1)=2$. Did you also try evaluating $C,A^{t-1} B$ for any of the proposed solutions?
– Kwin van der Veen
Nov 16 at 5:11
for $t=1$, $CA^{t-1}B$ gives $A=B=2, C=1, D=0$ which leaves only $A$ and $B$ as possible answers. Entering further values of $t$ produces the same results for $A$ and $B$. The fact that $B$ does not have a $2$ in it makes $A$ the only correct answer. Thanks.
– user463102
17 hours ago
1
1
Your first value for the impulse response seems off, namely it should be $h(1)=2$. Did you also try evaluating $C,A^{t-1} B$ for any of the proposed solutions?
– Kwin van der Veen
Nov 16 at 5:11
Your first value for the impulse response seems off, namely it should be $h(1)=2$. Did you also try evaluating $C,A^{t-1} B$ for any of the proposed solutions?
– Kwin van der Veen
Nov 16 at 5:11
for $t=1$, $CA^{t-1}B$ gives $A=B=2, C=1, D=0$ which leaves only $A$ and $B$ as possible answers. Entering further values of $t$ produces the same results for $A$ and $B$. The fact that $B$ does not have a $2$ in it makes $A$ the only correct answer. Thanks.
– user463102
17 hours ago
for $t=1$, $CA^{t-1}B$ gives $A=B=2, C=1, D=0$ which leaves only $A$ and $B$ as possible answers. Entering further values of $t$ produces the same results for $A$ and $B$. The fact that $B$ does not have a $2$ in it makes $A$ the only correct answer. Thanks.
– user463102
17 hours ago
add a comment |
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1
Your first value for the impulse response seems off, namely it should be $h(1)=2$. Did you also try evaluating $C,A^{t-1} B$ for any of the proposed solutions?
– Kwin van der Veen
Nov 16 at 5:11
for $t=1$, $CA^{t-1}B$ gives $A=B=2, C=1, D=0$ which leaves only $A$ and $B$ as possible answers. Entering further values of $t$ produces the same results for $A$ and $B$. The fact that $B$ does not have a $2$ in it makes $A$ the only correct answer. Thanks.
– user463102
17 hours ago