Finding the angle b/w two lines in Coordinate Geometry












0












$begingroup$


In my coaching class I was taught that the tangent of the angle between two lines having slopes $m_1$ and $m_2$ is given by the formula modulus of
$frac{m_1-m_2}{1+m_1m_2}$.
We can then use $tan$-inverse to find the angle.
However, some angles have negative tangent values, which will not be obtained by this formula which uses modulus. But shouldn't these angles also exist between two lines?










share|cite|improve this question











$endgroup$












  • $begingroup$
    You might consider how many angles are created when two lines intersect.
    $endgroup$
    – euler1944
    Jan 10 '16 at 5:00










  • $begingroup$
    Negative angles might be that they are in clockwise direction thats why we use mod also intersection creates $4$ angles.
    $endgroup$
    – Archis Welankar
    Jan 10 '16 at 5:21
















0












$begingroup$


In my coaching class I was taught that the tangent of the angle between two lines having slopes $m_1$ and $m_2$ is given by the formula modulus of
$frac{m_1-m_2}{1+m_1m_2}$.
We can then use $tan$-inverse to find the angle.
However, some angles have negative tangent values, which will not be obtained by this formula which uses modulus. But shouldn't these angles also exist between two lines?










share|cite|improve this question











$endgroup$












  • $begingroup$
    You might consider how many angles are created when two lines intersect.
    $endgroup$
    – euler1944
    Jan 10 '16 at 5:00










  • $begingroup$
    Negative angles might be that they are in clockwise direction thats why we use mod also intersection creates $4$ angles.
    $endgroup$
    – Archis Welankar
    Jan 10 '16 at 5:21














0












0








0





$begingroup$


In my coaching class I was taught that the tangent of the angle between two lines having slopes $m_1$ and $m_2$ is given by the formula modulus of
$frac{m_1-m_2}{1+m_1m_2}$.
We can then use $tan$-inverse to find the angle.
However, some angles have negative tangent values, which will not be obtained by this formula which uses modulus. But shouldn't these angles also exist between two lines?










share|cite|improve this question











$endgroup$




In my coaching class I was taught that the tangent of the angle between two lines having slopes $m_1$ and $m_2$ is given by the formula modulus of
$frac{m_1-m_2}{1+m_1m_2}$.
We can then use $tan$-inverse to find the angle.
However, some angles have negative tangent values, which will not be obtained by this formula which uses modulus. But shouldn't these angles also exist between two lines?







analytic-geometry






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Jan 10 '16 at 5:03









Winther

20.6k33156




20.6k33156










asked Jan 10 '16 at 4:55









N.S.JOHNN.S.JOHN

1,177620




1,177620












  • $begingroup$
    You might consider how many angles are created when two lines intersect.
    $endgroup$
    – euler1944
    Jan 10 '16 at 5:00










  • $begingroup$
    Negative angles might be that they are in clockwise direction thats why we use mod also intersection creates $4$ angles.
    $endgroup$
    – Archis Welankar
    Jan 10 '16 at 5:21


















  • $begingroup$
    You might consider how many angles are created when two lines intersect.
    $endgroup$
    – euler1944
    Jan 10 '16 at 5:00










  • $begingroup$
    Negative angles might be that they are in clockwise direction thats why we use mod also intersection creates $4$ angles.
    $endgroup$
    – Archis Welankar
    Jan 10 '16 at 5:21
















$begingroup$
You might consider how many angles are created when two lines intersect.
$endgroup$
– euler1944
Jan 10 '16 at 5:00




$begingroup$
You might consider how many angles are created when two lines intersect.
$endgroup$
– euler1944
Jan 10 '16 at 5:00












$begingroup$
Negative angles might be that they are in clockwise direction thats why we use mod also intersection creates $4$ angles.
$endgroup$
– Archis Welankar
Jan 10 '16 at 5:21




$begingroup$
Negative angles might be that they are in clockwise direction thats why we use mod also intersection creates $4$ angles.
$endgroup$
– Archis Welankar
Jan 10 '16 at 5:21










2 Answers
2






active

oldest

votes


















0












$begingroup$

Before you use the formula, you should determine what type of angle you are looking for, specifically, acute or obtuse - when two lines intersect, two pairs of identical angles are formed. To specify which angle you are targeting, use your formula, with $m_{2}$ being the angle's starting line. If you get a negative output after taking inverse tangent, just take the positive of the answer. This results from the fact that inverse tangent is an odd function; specifically, $arctan(-theta) = -arctan(theta).$ Hope this helps!






share|cite|improve this answer









$endgroup$





















    0












    $begingroup$

    My interpretation of the vertical bars in the formula ($tan theta = |dfrac {m_1 – m_2}{1 + m_1m_2}|$) is NOT modulus but absolute value instead.



    This means $tan theta = + dfrac {m_1 – m_2}{1 + m_1m_2}$ or $tan theta =–dfrac {m_1 – m_2}{1 + m_1m_2}$.



    If one value does not give an acute value of $theta$, the other will.






    share|cite|improve this answer









    $endgroup$













      Your Answer





      StackExchange.ifUsing("editor", function () {
      return StackExchange.using("mathjaxEditing", function () {
      StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
      StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
      });
      });
      }, "mathjax-editing");

      StackExchange.ready(function() {
      var channelOptions = {
      tags: "".split(" "),
      id: "69"
      };
      initTagRenderer("".split(" "), "".split(" "), channelOptions);

      StackExchange.using("externalEditor", function() {
      // Have to fire editor after snippets, if snippets enabled
      if (StackExchange.settings.snippets.snippetsEnabled) {
      StackExchange.using("snippets", function() {
      createEditor();
      });
      }
      else {
      createEditor();
      }
      });

      function createEditor() {
      StackExchange.prepareEditor({
      heartbeatType: 'answer',
      autoActivateHeartbeat: false,
      convertImagesToLinks: true,
      noModals: true,
      showLowRepImageUploadWarning: true,
      reputationToPostImages: 10,
      bindNavPrevention: true,
      postfix: "",
      imageUploader: {
      brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
      contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
      allowUrls: true
      },
      noCode: true, onDemand: true,
      discardSelector: ".discard-answer"
      ,immediatelyShowMarkdownHelp:true
      });


      }
      });














      draft saved

      draft discarded


















      StackExchange.ready(
      function () {
      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1606380%2ffinding-the-angle-b-w-two-lines-in-coordinate-geometry%23new-answer', 'question_page');
      }
      );

      Post as a guest















      Required, but never shown

























      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      0












      $begingroup$

      Before you use the formula, you should determine what type of angle you are looking for, specifically, acute or obtuse - when two lines intersect, two pairs of identical angles are formed. To specify which angle you are targeting, use your formula, with $m_{2}$ being the angle's starting line. If you get a negative output after taking inverse tangent, just take the positive of the answer. This results from the fact that inverse tangent is an odd function; specifically, $arctan(-theta) = -arctan(theta).$ Hope this helps!






      share|cite|improve this answer









      $endgroup$


















        0












        $begingroup$

        Before you use the formula, you should determine what type of angle you are looking for, specifically, acute or obtuse - when two lines intersect, two pairs of identical angles are formed. To specify which angle you are targeting, use your formula, with $m_{2}$ being the angle's starting line. If you get a negative output after taking inverse tangent, just take the positive of the answer. This results from the fact that inverse tangent is an odd function; specifically, $arctan(-theta) = -arctan(theta).$ Hope this helps!






        share|cite|improve this answer









        $endgroup$
















          0












          0








          0





          $begingroup$

          Before you use the formula, you should determine what type of angle you are looking for, specifically, acute or obtuse - when two lines intersect, two pairs of identical angles are formed. To specify which angle you are targeting, use your formula, with $m_{2}$ being the angle's starting line. If you get a negative output after taking inverse tangent, just take the positive of the answer. This results from the fact that inverse tangent is an odd function; specifically, $arctan(-theta) = -arctan(theta).$ Hope this helps!






          share|cite|improve this answer









          $endgroup$



          Before you use the formula, you should determine what type of angle you are looking for, specifically, acute or obtuse - when two lines intersect, two pairs of identical angles are formed. To specify which angle you are targeting, use your formula, with $m_{2}$ being the angle's starting line. If you get a negative output after taking inverse tangent, just take the positive of the answer. This results from the fact that inverse tangent is an odd function; specifically, $arctan(-theta) = -arctan(theta).$ Hope this helps!







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Jan 10 '16 at 5:31









          K. JiangK. Jiang

          3,0311513




          3,0311513























              0












              $begingroup$

              My interpretation of the vertical bars in the formula ($tan theta = |dfrac {m_1 – m_2}{1 + m_1m_2}|$) is NOT modulus but absolute value instead.



              This means $tan theta = + dfrac {m_1 – m_2}{1 + m_1m_2}$ or $tan theta =–dfrac {m_1 – m_2}{1 + m_1m_2}$.



              If one value does not give an acute value of $theta$, the other will.






              share|cite|improve this answer









              $endgroup$


















                0












                $begingroup$

                My interpretation of the vertical bars in the formula ($tan theta = |dfrac {m_1 – m_2}{1 + m_1m_2}|$) is NOT modulus but absolute value instead.



                This means $tan theta = + dfrac {m_1 – m_2}{1 + m_1m_2}$ or $tan theta =–dfrac {m_1 – m_2}{1 + m_1m_2}$.



                If one value does not give an acute value of $theta$, the other will.






                share|cite|improve this answer









                $endgroup$
















                  0












                  0








                  0





                  $begingroup$

                  My interpretation of the vertical bars in the formula ($tan theta = |dfrac {m_1 – m_2}{1 + m_1m_2}|$) is NOT modulus but absolute value instead.



                  This means $tan theta = + dfrac {m_1 – m_2}{1 + m_1m_2}$ or $tan theta =–dfrac {m_1 – m_2}{1 + m_1m_2}$.



                  If one value does not give an acute value of $theta$, the other will.






                  share|cite|improve this answer









                  $endgroup$



                  My interpretation of the vertical bars in the formula ($tan theta = |dfrac {m_1 – m_2}{1 + m_1m_2}|$) is NOT modulus but absolute value instead.



                  This means $tan theta = + dfrac {m_1 – m_2}{1 + m_1m_2}$ or $tan theta =–dfrac {m_1 – m_2}{1 + m_1m_2}$.



                  If one value does not give an acute value of $theta$, the other will.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Jan 10 '16 at 5:38









                  MickMick

                  11.9k21641




                  11.9k21641






























                      draft saved

                      draft discarded




















































                      Thanks for contributing an answer to Mathematics Stack Exchange!


                      • Please be sure to answer the question. Provide details and share your research!

                      But avoid



                      • Asking for help, clarification, or responding to other answers.

                      • Making statements based on opinion; back them up with references or personal experience.


                      Use MathJax to format equations. MathJax reference.


                      To learn more, see our tips on writing great answers.




                      draft saved


                      draft discarded














                      StackExchange.ready(
                      function () {
                      StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1606380%2ffinding-the-angle-b-w-two-lines-in-coordinate-geometry%23new-answer', 'question_page');
                      }
                      );

                      Post as a guest















                      Required, but never shown





















































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown

































                      Required, but never shown














                      Required, but never shown












                      Required, but never shown







                      Required, but never shown







                      Popular posts from this blog

                      Ellipse (mathématiques)

                      Quarter-circle Tiles

                      Mont Emei