Hilbert space. Self-adjoint operator. [closed]
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Let H be a Hilbert space, A is self-adjoint operator, $ x notin KerA $. How to prove that $ a_{n}=frac{parallel A^{n+1}xparallel}{parallel A^nx parallel} $ sequence converges?
functional-analysis
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closed as off-topic by Saad, Eevee Trainer, mrtaurho, José Carlos Santos, Paul Frost Dec 23 '18 at 16:15
This question appears to be off-topic. The users who voted to close gave this specific reason:
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If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
$begingroup$
Let H be a Hilbert space, A is self-adjoint operator, $ x notin KerA $. How to prove that $ a_{n}=frac{parallel A^{n+1}xparallel}{parallel A^nx parallel} $ sequence converges?
functional-analysis
$endgroup$
closed as off-topic by Saad, Eevee Trainer, mrtaurho, José Carlos Santos, Paul Frost Dec 23 '18 at 16:15
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Eevee Trainer, mrtaurho, José Carlos Santos, Paul Frost
If this question can be reworded to fit the rules in the help center, please edit the question.
2
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Have you tried using the spectral theorem?
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– Eric Wofsey
Dec 23 '18 at 5:57
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@EricWofsey don't you need to assume something more about $A$?
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– lcv
Dec 23 '18 at 10:30
add a comment |
$begingroup$
Let H be a Hilbert space, A is self-adjoint operator, $ x notin KerA $. How to prove that $ a_{n}=frac{parallel A^{n+1}xparallel}{parallel A^nx parallel} $ sequence converges?
functional-analysis
$endgroup$
Let H be a Hilbert space, A is self-adjoint operator, $ x notin KerA $. How to prove that $ a_{n}=frac{parallel A^{n+1}xparallel}{parallel A^nx parallel} $ sequence converges?
functional-analysis
functional-analysis
asked Dec 23 '18 at 1:59
T. ElmiraT. Elmira
174
174
closed as off-topic by Saad, Eevee Trainer, mrtaurho, José Carlos Santos, Paul Frost Dec 23 '18 at 16:15
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Eevee Trainer, mrtaurho, José Carlos Santos, Paul Frost
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by Saad, Eevee Trainer, mrtaurho, José Carlos Santos, Paul Frost Dec 23 '18 at 16:15
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, Eevee Trainer, mrtaurho, José Carlos Santos, Paul Frost
If this question can be reworded to fit the rules in the help center, please edit the question.
2
$begingroup$
Have you tried using the spectral theorem?
$endgroup$
– Eric Wofsey
Dec 23 '18 at 5:57
$begingroup$
@EricWofsey don't you need to assume something more about $A$?
$endgroup$
– lcv
Dec 23 '18 at 10:30
add a comment |
2
$begingroup$
Have you tried using the spectral theorem?
$endgroup$
– Eric Wofsey
Dec 23 '18 at 5:57
$begingroup$
@EricWofsey don't you need to assume something more about $A$?
$endgroup$
– lcv
Dec 23 '18 at 10:30
2
2
$begingroup$
Have you tried using the spectral theorem?
$endgroup$
– Eric Wofsey
Dec 23 '18 at 5:57
$begingroup$
Have you tried using the spectral theorem?
$endgroup$
– Eric Wofsey
Dec 23 '18 at 5:57
$begingroup$
@EricWofsey don't you need to assume something more about $A$?
$endgroup$
– lcv
Dec 23 '18 at 10:30
$begingroup$
@EricWofsey don't you need to assume something more about $A$?
$endgroup$
– lcv
Dec 23 '18 at 10:30
add a comment |
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$begingroup$
Have you tried using the spectral theorem?
$endgroup$
– Eric Wofsey
Dec 23 '18 at 5:57
$begingroup$
@EricWofsey don't you need to assume something more about $A$?
$endgroup$
– lcv
Dec 23 '18 at 10:30