minimal projection in a $C^*$ algebra












1














If $(H,pi)$ is a nonzero representation of a $C^*$ algebra $A$,does there exist a minimal projection $Ein A$ such that $pi(E)neq 0$?










share|cite|improve this question



























    1














    If $(H,pi)$ is a nonzero representation of a $C^*$ algebra $A$,does there exist a minimal projection $Ein A$ such that $pi(E)neq 0$?










    share|cite|improve this question

























      1












      1








      1







      If $(H,pi)$ is a nonzero representation of a $C^*$ algebra $A$,does there exist a minimal projection $Ein A$ such that $pi(E)neq 0$?










      share|cite|improve this question













      If $(H,pi)$ is a nonzero representation of a $C^*$ algebra $A$,does there exist a minimal projection $Ein A$ such that $pi(E)neq 0$?







      operator-theory operator-algebras c-star-algebras von-neumann-algebras






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Nov 26 at 3:00









      mathrookie

      804512




      804512






















          1 Answer
          1






          active

          oldest

          votes


















          2














          No. Let $A=B(H)$ for some Hilbert space $H$, let $rho:B(H)to B(H)/K(H)=Q(H)$ be the quotient map, and let $(K,pi)$ be a non-zero representation of $Q(H)$. Then $(K,picircrho)$ is a non-zero representation of $B(H)$ with $picircrho(P)=0$ for every finite-rank projection $P$ in $B(H)$, hence for all minimal projections.






          share|cite|improve this answer





















            Your Answer





            StackExchange.ifUsing("editor", function () {
            return StackExchange.using("mathjaxEditing", function () {
            StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix) {
            StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
            });
            });
            }, "mathjax-editing");

            StackExchange.ready(function() {
            var channelOptions = {
            tags: "".split(" "),
            id: "69"
            };
            initTagRenderer("".split(" "), "".split(" "), channelOptions);

            StackExchange.using("externalEditor", function() {
            // Have to fire editor after snippets, if snippets enabled
            if (StackExchange.settings.snippets.snippetsEnabled) {
            StackExchange.using("snippets", function() {
            createEditor();
            });
            }
            else {
            createEditor();
            }
            });

            function createEditor() {
            StackExchange.prepareEditor({
            heartbeatType: 'answer',
            autoActivateHeartbeat: false,
            convertImagesToLinks: true,
            noModals: true,
            showLowRepImageUploadWarning: true,
            reputationToPostImages: 10,
            bindNavPrevention: true,
            postfix: "",
            imageUploader: {
            brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
            contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
            allowUrls: true
            },
            noCode: true, onDemand: true,
            discardSelector: ".discard-answer"
            ,immediatelyShowMarkdownHelp:true
            });


            }
            });














            draft saved

            draft discarded


















            StackExchange.ready(
            function () {
            StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3013759%2fminimal-projection-in-a-c-algebra%23new-answer', 'question_page');
            }
            );

            Post as a guest















            Required, but never shown

























            1 Answer
            1






            active

            oldest

            votes








            1 Answer
            1






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            2














            No. Let $A=B(H)$ for some Hilbert space $H$, let $rho:B(H)to B(H)/K(H)=Q(H)$ be the quotient map, and let $(K,pi)$ be a non-zero representation of $Q(H)$. Then $(K,picircrho)$ is a non-zero representation of $B(H)$ with $picircrho(P)=0$ for every finite-rank projection $P$ in $B(H)$, hence for all minimal projections.






            share|cite|improve this answer


























              2














              No. Let $A=B(H)$ for some Hilbert space $H$, let $rho:B(H)to B(H)/K(H)=Q(H)$ be the quotient map, and let $(K,pi)$ be a non-zero representation of $Q(H)$. Then $(K,picircrho)$ is a non-zero representation of $B(H)$ with $picircrho(P)=0$ for every finite-rank projection $P$ in $B(H)$, hence for all minimal projections.






              share|cite|improve this answer
























                2












                2








                2






                No. Let $A=B(H)$ for some Hilbert space $H$, let $rho:B(H)to B(H)/K(H)=Q(H)$ be the quotient map, and let $(K,pi)$ be a non-zero representation of $Q(H)$. Then $(K,picircrho)$ is a non-zero representation of $B(H)$ with $picircrho(P)=0$ for every finite-rank projection $P$ in $B(H)$, hence for all minimal projections.






                share|cite|improve this answer












                No. Let $A=B(H)$ for some Hilbert space $H$, let $rho:B(H)to B(H)/K(H)=Q(H)$ be the quotient map, and let $(K,pi)$ be a non-zero representation of $Q(H)$. Then $(K,picircrho)$ is a non-zero representation of $B(H)$ with $picircrho(P)=0$ for every finite-rank projection $P$ in $B(H)$, hence for all minimal projections.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Nov 26 at 3:04









                Aweygan

                13.4k21441




                13.4k21441






























                    draft saved

                    draft discarded




















































                    Thanks for contributing an answer to Mathematics Stack Exchange!


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    Use MathJax to format equations. MathJax reference.


                    To learn more, see our tips on writing great answers.





                    Some of your past answers have not been well-received, and you're in danger of being blocked from answering.


                    Please pay close attention to the following guidance:


                    • Please be sure to answer the question. Provide details and share your research!

                    But avoid



                    • Asking for help, clarification, or responding to other answers.

                    • Making statements based on opinion; back them up with references or personal experience.


                    To learn more, see our tips on writing great answers.




                    draft saved


                    draft discarded














                    StackExchange.ready(
                    function () {
                    StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3013759%2fminimal-projection-in-a-c-algebra%23new-answer', 'question_page');
                    }
                    );

                    Post as a guest















                    Required, but never shown





















































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown

































                    Required, but never shown














                    Required, but never shown












                    Required, but never shown







                    Required, but never shown







                    Popular posts from this blog

                    Quarter-circle Tiles

                    build a pushdown automaton that recognizes the reverse language of a given pushdown automaton?

                    Mont Emei