What is the purpose of op-amp in the output of Instrumentation amplifier
I encountered a problem while solving an analog circuit.
I just need to know the purpose of the last op-amp (K4) at this circuit:
while solving I understand it just amplify the output voltage from the Instrumentation Amplifier, but there is known purpose for it beside to amplify Vout3.
thanks!
op-amp analog instrumentation-amplifier
add a comment |
I encountered a problem while solving an analog circuit.
I just need to know the purpose of the last op-amp (K4) at this circuit:
while solving I understand it just amplify the output voltage from the Instrumentation Amplifier, but there is known purpose for it beside to amplify Vout3.
thanks!
op-amp analog instrumentation-amplifier
Is this from EEG or EKG or EMG sensors?
– analogsystemsrf
Dec 10 at 13:31
it just a problem from my homework. I know this kind of circuits very common so possibly it used in these sensors.
– Michael Astahov
Dec 11 at 21:23
add a comment |
I encountered a problem while solving an analog circuit.
I just need to know the purpose of the last op-amp (K4) at this circuit:
while solving I understand it just amplify the output voltage from the Instrumentation Amplifier, but there is known purpose for it beside to amplify Vout3.
thanks!
op-amp analog instrumentation-amplifier
I encountered a problem while solving an analog circuit.
I just need to know the purpose of the last op-amp (K4) at this circuit:
while solving I understand it just amplify the output voltage from the Instrumentation Amplifier, but there is known purpose for it beside to amplify Vout3.
thanks!
op-amp analog instrumentation-amplifier
op-amp analog instrumentation-amplifier
asked Dec 10 at 11:48
Michael Astahov
132
132
Is this from EEG or EKG or EMG sensors?
– analogsystemsrf
Dec 10 at 13:31
it just a problem from my homework. I know this kind of circuits very common so possibly it used in these sensors.
– Michael Astahov
Dec 11 at 21:23
add a comment |
Is this from EEG or EKG or EMG sensors?
– analogsystemsrf
Dec 10 at 13:31
it just a problem from my homework. I know this kind of circuits very common so possibly it used in these sensors.
– Michael Astahov
Dec 11 at 21:23
Is this from EEG or EKG or EMG sensors?
– analogsystemsrf
Dec 10 at 13:31
Is this from EEG or EKG or EMG sensors?
– analogsystemsrf
Dec 10 at 13:31
it just a problem from my homework. I know this kind of circuits very common so possibly it used in these sensors.
– Michael Astahov
Dec 11 at 21:23
it just a problem from my homework. I know this kind of circuits very common so possibly it used in these sensors.
– Michael Astahov
Dec 11 at 21:23
add a comment |
1 Answer
1
active
oldest
votes
K4 produces amplification for AC signals whilst providing a DC amplification of 1 (so that DC levels are maintained from the InAmp output to whatever stage follows K4). It might also be used to share the burden of AC signal gain between InAmp and itself thus minimizing slew rate problems in the InAmp.
thanks Andy for the quick reponse.
– Michael Astahov
Dec 10 at 12:03
So - the last stage acts as a sort of highpass.
– LvW
Dec 10 at 13:10
@LvW are you asking or saying!
– Andy aka
Dec 10 at 13:12
@Andy aka...there is no question mark. Hence, it is not a question. To me, the transfer function [1+sR2C/(1+sR1C)] is a highpass with a fixed gain of unity at low frequencies. Why are you asking?
– LvW
Dec 10 at 14:51
@LvW it's always best to be careful!!
– Andy aka
Dec 10 at 16:08
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
K4 produces amplification for AC signals whilst providing a DC amplification of 1 (so that DC levels are maintained from the InAmp output to whatever stage follows K4). It might also be used to share the burden of AC signal gain between InAmp and itself thus minimizing slew rate problems in the InAmp.
thanks Andy for the quick reponse.
– Michael Astahov
Dec 10 at 12:03
So - the last stage acts as a sort of highpass.
– LvW
Dec 10 at 13:10
@LvW are you asking or saying!
– Andy aka
Dec 10 at 13:12
@Andy aka...there is no question mark. Hence, it is not a question. To me, the transfer function [1+sR2C/(1+sR1C)] is a highpass with a fixed gain of unity at low frequencies. Why are you asking?
– LvW
Dec 10 at 14:51
@LvW it's always best to be careful!!
– Andy aka
Dec 10 at 16:08
add a comment |
K4 produces amplification for AC signals whilst providing a DC amplification of 1 (so that DC levels are maintained from the InAmp output to whatever stage follows K4). It might also be used to share the burden of AC signal gain between InAmp and itself thus minimizing slew rate problems in the InAmp.
thanks Andy for the quick reponse.
– Michael Astahov
Dec 10 at 12:03
So - the last stage acts as a sort of highpass.
– LvW
Dec 10 at 13:10
@LvW are you asking or saying!
– Andy aka
Dec 10 at 13:12
@Andy aka...there is no question mark. Hence, it is not a question. To me, the transfer function [1+sR2C/(1+sR1C)] is a highpass with a fixed gain of unity at low frequencies. Why are you asking?
– LvW
Dec 10 at 14:51
@LvW it's always best to be careful!!
– Andy aka
Dec 10 at 16:08
add a comment |
K4 produces amplification for AC signals whilst providing a DC amplification of 1 (so that DC levels are maintained from the InAmp output to whatever stage follows K4). It might also be used to share the burden of AC signal gain between InAmp and itself thus minimizing slew rate problems in the InAmp.
K4 produces amplification for AC signals whilst providing a DC amplification of 1 (so that DC levels are maintained from the InAmp output to whatever stage follows K4). It might also be used to share the burden of AC signal gain between InAmp and itself thus minimizing slew rate problems in the InAmp.
answered Dec 10 at 11:54
Andy aka
239k10176407
239k10176407
thanks Andy for the quick reponse.
– Michael Astahov
Dec 10 at 12:03
So - the last stage acts as a sort of highpass.
– LvW
Dec 10 at 13:10
@LvW are you asking or saying!
– Andy aka
Dec 10 at 13:12
@Andy aka...there is no question mark. Hence, it is not a question. To me, the transfer function [1+sR2C/(1+sR1C)] is a highpass with a fixed gain of unity at low frequencies. Why are you asking?
– LvW
Dec 10 at 14:51
@LvW it's always best to be careful!!
– Andy aka
Dec 10 at 16:08
add a comment |
thanks Andy for the quick reponse.
– Michael Astahov
Dec 10 at 12:03
So - the last stage acts as a sort of highpass.
– LvW
Dec 10 at 13:10
@LvW are you asking or saying!
– Andy aka
Dec 10 at 13:12
@Andy aka...there is no question mark. Hence, it is not a question. To me, the transfer function [1+sR2C/(1+sR1C)] is a highpass with a fixed gain of unity at low frequencies. Why are you asking?
– LvW
Dec 10 at 14:51
@LvW it's always best to be careful!!
– Andy aka
Dec 10 at 16:08
thanks Andy for the quick reponse.
– Michael Astahov
Dec 10 at 12:03
thanks Andy for the quick reponse.
– Michael Astahov
Dec 10 at 12:03
So - the last stage acts as a sort of highpass.
– LvW
Dec 10 at 13:10
So - the last stage acts as a sort of highpass.
– LvW
Dec 10 at 13:10
@LvW are you asking or saying!
– Andy aka
Dec 10 at 13:12
@LvW are you asking or saying!
– Andy aka
Dec 10 at 13:12
@Andy aka...there is no question mark. Hence, it is not a question. To me, the transfer function [1+sR2C/(1+sR1C)] is a highpass with a fixed gain of unity at low frequencies. Why are you asking?
– LvW
Dec 10 at 14:51
@Andy aka...there is no question mark. Hence, it is not a question. To me, the transfer function [1+sR2C/(1+sR1C)] is a highpass with a fixed gain of unity at low frequencies. Why are you asking?
– LvW
Dec 10 at 14:51
@LvW it's always best to be careful!!
– Andy aka
Dec 10 at 16:08
@LvW it's always best to be careful!!
– Andy aka
Dec 10 at 16:08
add a comment |
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Is this from EEG or EKG or EMG sensors?
– analogsystemsrf
Dec 10 at 13:31
it just a problem from my homework. I know this kind of circuits very common so possibly it used in these sensors.
– Michael Astahov
Dec 11 at 21:23