Does absolute convergence of a sequence imply convergence?












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In my real analysis notes I've got that absolute convergence of a real SERIES implies convergence of the series. However what about absolute convergence of a sequence? Does this imply convergence of the sequence?










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    I have not seen the notion of absolute convergence of a sequence used anywhere.
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    – André Nicolas
    Aug 13 '14 at 22:55
















5












$begingroup$


In my real analysis notes I've got that absolute convergence of a real SERIES implies convergence of the series. However what about absolute convergence of a sequence? Does this imply convergence of the sequence?










share|cite|improve this question









$endgroup$












  • $begingroup$
    I have not seen the notion of absolute convergence of a sequence used anywhere.
    $endgroup$
    – André Nicolas
    Aug 13 '14 at 22:55














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5








5


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$begingroup$


In my real analysis notes I've got that absolute convergence of a real SERIES implies convergence of the series. However what about absolute convergence of a sequence? Does this imply convergence of the sequence?










share|cite|improve this question









$endgroup$




In my real analysis notes I've got that absolute convergence of a real SERIES implies convergence of the series. However what about absolute convergence of a sequence? Does this imply convergence of the sequence?







real-analysis






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asked Aug 13 '14 at 21:53









Spongebob SquarepantsSpongebob Squarepants

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  • $begingroup$
    I have not seen the notion of absolute convergence of a sequence used anywhere.
    $endgroup$
    – André Nicolas
    Aug 13 '14 at 22:55


















  • $begingroup$
    I have not seen the notion of absolute convergence of a sequence used anywhere.
    $endgroup$
    – André Nicolas
    Aug 13 '14 at 22:55
















$begingroup$
I have not seen the notion of absolute convergence of a sequence used anywhere.
$endgroup$
– André Nicolas
Aug 13 '14 at 22:55




$begingroup$
I have not seen the notion of absolute convergence of a sequence used anywhere.
$endgroup$
– André Nicolas
Aug 13 '14 at 22:55










1 Answer
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No. e.g. $(-1)^n$ does not converge but $left|(-1)^nright|=left|-1right|^n=1 quad $ does converge (to $1$).





As NotNotLogical has pointed out, the exception to this is when a sequence connverges absolutely to $0$, in which case the sequence converges to $0.$






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  • $begingroup$
    Worth adding that sequences which absolutely converge to zero will also converge to zero, but that is the only exception.
    $endgroup$
    – user142299
    Aug 13 '14 at 21:55










  • $begingroup$
    @NotNotLogical Well noted. Thanks!
    $endgroup$
    – beep-boop
    Aug 13 '14 at 21:57











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1 Answer
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active

oldest

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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









5












$begingroup$

No. e.g. $(-1)^n$ does not converge but $left|(-1)^nright|=left|-1right|^n=1 quad $ does converge (to $1$).





As NotNotLogical has pointed out, the exception to this is when a sequence connverges absolutely to $0$, in which case the sequence converges to $0.$






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Worth adding that sequences which absolutely converge to zero will also converge to zero, but that is the only exception.
    $endgroup$
    – user142299
    Aug 13 '14 at 21:55










  • $begingroup$
    @NotNotLogical Well noted. Thanks!
    $endgroup$
    – beep-boop
    Aug 13 '14 at 21:57
















5












$begingroup$

No. e.g. $(-1)^n$ does not converge but $left|(-1)^nright|=left|-1right|^n=1 quad $ does converge (to $1$).





As NotNotLogical has pointed out, the exception to this is when a sequence connverges absolutely to $0$, in which case the sequence converges to $0.$






share|cite|improve this answer











$endgroup$













  • $begingroup$
    Worth adding that sequences which absolutely converge to zero will also converge to zero, but that is the only exception.
    $endgroup$
    – user142299
    Aug 13 '14 at 21:55










  • $begingroup$
    @NotNotLogical Well noted. Thanks!
    $endgroup$
    – beep-boop
    Aug 13 '14 at 21:57














5












5








5





$begingroup$

No. e.g. $(-1)^n$ does not converge but $left|(-1)^nright|=left|-1right|^n=1 quad $ does converge (to $1$).





As NotNotLogical has pointed out, the exception to this is when a sequence connverges absolutely to $0$, in which case the sequence converges to $0.$






share|cite|improve this answer











$endgroup$



No. e.g. $(-1)^n$ does not converge but $left|(-1)^nright|=left|-1right|^n=1 quad $ does converge (to $1$).





As NotNotLogical has pointed out, the exception to this is when a sequence connverges absolutely to $0$, in which case the sequence converges to $0.$







share|cite|improve this answer














share|cite|improve this answer



share|cite|improve this answer








edited Aug 13 '14 at 22:50

























answered Aug 13 '14 at 21:54









beep-boopbeep-boop

7,97452860




7,97452860












  • $begingroup$
    Worth adding that sequences which absolutely converge to zero will also converge to zero, but that is the only exception.
    $endgroup$
    – user142299
    Aug 13 '14 at 21:55










  • $begingroup$
    @NotNotLogical Well noted. Thanks!
    $endgroup$
    – beep-boop
    Aug 13 '14 at 21:57


















  • $begingroup$
    Worth adding that sequences which absolutely converge to zero will also converge to zero, but that is the only exception.
    $endgroup$
    – user142299
    Aug 13 '14 at 21:55










  • $begingroup$
    @NotNotLogical Well noted. Thanks!
    $endgroup$
    – beep-boop
    Aug 13 '14 at 21:57
















$begingroup$
Worth adding that sequences which absolutely converge to zero will also converge to zero, but that is the only exception.
$endgroup$
– user142299
Aug 13 '14 at 21:55




$begingroup$
Worth adding that sequences which absolutely converge to zero will also converge to zero, but that is the only exception.
$endgroup$
– user142299
Aug 13 '14 at 21:55












$begingroup$
@NotNotLogical Well noted. Thanks!
$endgroup$
– beep-boop
Aug 13 '14 at 21:57




$begingroup$
@NotNotLogical Well noted. Thanks!
$endgroup$
– beep-boop
Aug 13 '14 at 21:57


















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