Distribution property on the internal and external multiplication of matrices












0












$begingroup$


I have relation as :
A=E*(p1.p2)=270
which
E=[1 2 3];
p1=transpose([4 5 6]);
p2= transpose( [7 8 9]);
How can I withdraw p2 or make a factor from p2 f to make isolate (Ep1)






calculus linear-algebra combinatorics matrices matlab







share|cite|improve this question









$endgroup$












  • $begingroup$
    The dot product is symmetric.
    $endgroup$
    – amd
    Dec 28 '18 at 22:58
















0












$begingroup$


I have relation as :
A=E*(p1.p2)=270
which
E=[1 2 3];
p1=transpose([4 5 6]);
p2= transpose( [7 8 9]);
How can I withdraw p2 or make a factor from p2 f to make isolate (Ep1)






calculus linear-algebra combinatorics matrices matlab







share|cite|improve this question









$endgroup$












  • $begingroup$
    The dot product is symmetric.
    $endgroup$
    – amd
    Dec 28 '18 at 22:58














0












0








0





$begingroup$


I have relation as :
A=E*(p1.p2)=270
which
E=[1 2 3];
p1=transpose([4 5 6]);
p2= transpose( [7 8 9]);
How can I withdraw p2 or make a factor from p2 f to make isolate (Ep1)






calculus linear-algebra combinatorics matrices matlab







share|cite|improve this question









$endgroup$




I have relation as :
A=E*(p1.p2)=270
which
E=[1 2 3];
p1=transpose([4 5 6]);
p2= transpose( [7 8 9]);
How can I withdraw p2 or make a factor from p2 f to make isolate (Ep1)






calculus linear-algebra combinatorics matrices matlab




calculus linear-algebra combinatorics matrices matlab






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Dec 28 '18 at 21:52









Hamed HatamiHamed Hatami

1




1












  • $begingroup$
    The dot product is symmetric.
    $endgroup$
    – amd
    Dec 28 '18 at 22:58


















  • $begingroup$
    The dot product is symmetric.
    $endgroup$
    – amd
    Dec 28 '18 at 22:58
















$begingroup$
The dot product is symmetric.
$endgroup$
– amd
Dec 28 '18 at 22:58




$begingroup$
The dot product is symmetric.
$endgroup$
– amd
Dec 28 '18 at 22:58










0






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