Repeated alphabet in n^r
$begingroup$
Q: How many ways to form a word of 3 letters with English alphabet (repetition allowed)?
A: 26^3
but shouldn't we account for the repeated alphabet? like aab, and aab is the same?
Why isn't the question solved in the same way like "How many ways to arrange the word POOP"
which the answer is 4!/(2!2!)
permutations
asked Dec 22 '18 at 7:28
thikin haxthikin hax
11
$endgroup$
add a comment |
$begingroup$
Q: How many ways to form a word of 3 letters with English alphabet (repetition allowed)?
A: 26^3
but shouldn't we account for the repeated alphabet? like aab, and aab is the same?
Why isn't the question solved in the same way like "How many ways to arrange the word POOP"
which the answer is 4!/(2!2!)
permutations
asked Dec 22 '18 at 7:28
thikin haxthikin hax
11
$endgroup$
add a comment |
$begingroup$
Q: How many ways to form a word of 3 letters with English alphabet (repetition allowed)?
A: 26^3
but shouldn't we account for the repeated alphabet? like aab, and aab is the same?
Why isn't the question solved in the same way like "How many ways to arrange the word POOP"
which the answer is 4!/(2!2!)
permutations
asked Dec 22 '18 at 7:28
thikin haxthikin hax
11
$endgroup$
Q: How many ways to form a word of 3 letters with English alphabet (repetition allowed)?
A: 26^3
but shouldn't we account for the repeated alphabet? like aab, and aab is the same?
Why isn't the question solved in the same way like "How many ways to arrange the word POOP"
which the answer is 4!/(2!2!)
permutations
permutations
asked Dec 22 '18 at 7:28
thikin haxthikin hax
11
asked Dec 22 '18 at 7:28
thikin haxthikin hax
11
edited Dec 22 '18 at 7:35
thikin hax
asked Dec 22 '18 at 7:28
thikin haxthikin hax
11
asked Dec 22 '18 at 7:28
thikin haxthikin hax
11
asked Dec 22 '18 at 7:28
thikin haxthikin hax
11
11
add a comment |
add a comment |
1 Answer
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$begingroup$
We already are accounting for the repeated alphabet. That $26^3$ comes from answering three questions: What is the first letter? What is the second letter? What is the third letter?
Those three questions are allowed to have the same answers, as in your example "aab". That's $26$ possibilities for each question, and each answer is fully independent of the others.
Arranging the letters of a fixed word "deed"? We can ask which letter goes in each place, but those choices are tied together by the need to use each of that original word's letters. The numerator $4cdot 3cdot 2cdot 1$ comes from our choices being reduced at every step to whatever we haven't used yet, and the denominator $2times 2$ comes from letters of the same type being indistinguishable; $d_1e_1e_2d_2$ and $d_2e_1e_2d_1$ are the same words.
answered Dec 22 '18 at 7:39
jmerryjmerry
9,4981124
$endgroup$
add a comment |
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1 Answer
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1 Answer
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active
oldest
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$begingroup$
We already are accounting for the repeated alphabet. That $26^3$ comes from answering three questions: What is the first letter? What is the second letter? What is the third letter?
Those three questions are allowed to have the same answers, as in your example "aab". That's $26$ possibilities for each question, and each answer is fully independent of the others.
Arranging the letters of a fixed word "deed"? We can ask which letter goes in each place, but those choices are tied together by the need to use each of that original word's letters. The numerator $4cdot 3cdot 2cdot 1$ comes from our choices being reduced at every step to whatever we haven't used yet, and the denominator $2times 2$ comes from letters of the same type being indistinguishable; $d_1e_1e_2d_2$ and $d_2e_1e_2d_1$ are the same words.
answered Dec 22 '18 at 7:39
jmerryjmerry
9,4981124
$endgroup$
add a comment |
$begingroup$
We already are accounting for the repeated alphabet. That $26^3$ comes from answering three questions: What is the first letter? What is the second letter? What is the third letter?
Those three questions are allowed to have the same answers, as in your example "aab". That's $26$ possibilities for each question, and each answer is fully independent of the others.
Arranging the letters of a fixed word "deed"? We can ask which letter goes in each place, but those choices are tied together by the need to use each of that original word's letters. The numerator $4cdot 3cdot 2cdot 1$ comes from our choices being reduced at every step to whatever we haven't used yet, and the denominator $2times 2$ comes from letters of the same type being indistinguishable; $d_1e_1e_2d_2$ and $d_2e_1e_2d_1$ are the same words.
answered Dec 22 '18 at 7:39
jmerryjmerry
9,4981124
$endgroup$
add a comment |
$begingroup$
We already are accounting for the repeated alphabet. That $26^3$ comes from answering three questions: What is the first letter? What is the second letter? What is the third letter?
Those three questions are allowed to have the same answers, as in your example "aab". That's $26$ possibilities for each question, and each answer is fully independent of the others.
Arranging the letters of a fixed word "deed"? We can ask which letter goes in each place, but those choices are tied together by the need to use each of that original word's letters. The numerator $4cdot 3cdot 2cdot 1$ comes from our choices being reduced at every step to whatever we haven't used yet, and the denominator $2times 2$ comes from letters of the same type being indistinguishable; $d_1e_1e_2d_2$ and $d_2e_1e_2d_1$ are the same words.
answered Dec 22 '18 at 7:39
jmerryjmerry
9,4981124
$endgroup$
We already are accounting for the repeated alphabet. That $26^3$ comes from answering three questions: What is the first letter? What is the second letter? What is the third letter?
Those three questions are allowed to have the same answers, as in your example "aab". That's $26$ possibilities for each question, and each answer is fully independent of the others.
Arranging the letters of a fixed word "deed"? We can ask which letter goes in each place, but those choices are tied together by the need to use each of that original word's letters. The numerator $4cdot 3cdot 2cdot 1$ comes from our choices being reduced at every step to whatever we haven't used yet, and the denominator $2times 2$ comes from letters of the same type being indistinguishable; $d_1e_1e_2d_2$ and $d_2e_1e_2d_1$ are the same words.
answered Dec 22 '18 at 7:39
jmerryjmerry
9,4981124
answered Dec 22 '18 at 7:39
jmerryjmerry
9,4981124
answered Dec 22 '18 at 7:39
jmerryjmerry
9,4981124
answered Dec 22 '18 at 7:39
jmerryjmerry
9,4981124
9,4981124
add a comment |
add a comment |
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