Limit $lim _{n to infty}frac{-2^{n}+3^{n}}{{-2^{n+1}+3^{n+1}}}$ without L'Hospital [closed]
-1
$begingroup$
I am trying to solve this limit without L'Hospital but i just dont know what do to with exponents.
$$lim _{n to infty}frac{-2^{n}+3^{n}}{{-2^{n+1}+3^{n+1}}}$$
I just dont know what to do with this exponenets
limits-without-lhopital
edited Dec 23 '18 at 20:57
Jyrki Lahtonen
109k13169374
asked Dec 23 '18 at 17:52
Juraj JakubovJuraj Jakubov
45
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closed as off-topic by RRL, KReiser, Jyrki Lahtonen, Tianlalu, Saad Dec 24 '18 at 0:07
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – RRL, KReiser, Jyrki Lahtonen, Tianlalu, Saad
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
-1
$begingroup$
I am trying to solve this limit without L'Hospital but i just dont know what do to with exponents.
$$lim _{n to infty}frac{-2^{n}+3^{n}}{{-2^{n+1}+3^{n+1}}}$$
I just dont know what to do with this exponenets
limits-without-lhopital
edited Dec 23 '18 at 20:57
Jyrki Lahtonen
109k13169374
asked Dec 23 '18 at 17:52
Juraj JakubovJuraj Jakubov
45
$endgroup$
closed as off-topic by RRL, KReiser, Jyrki Lahtonen, Tianlalu, Saad Dec 24 '18 at 0:07
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – RRL, KReiser, Jyrki Lahtonen, Tianlalu, Saad
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
-1
-1
-1
$begingroup$
I am trying to solve this limit without L'Hospital but i just dont know what do to with exponents.
$$lim _{n to infty}frac{-2^{n}+3^{n}}{{-2^{n+1}+3^{n+1}}}$$
I just dont know what to do with this exponenets
limits-without-lhopital
edited Dec 23 '18 at 20:57
Jyrki Lahtonen
109k13169374
asked Dec 23 '18 at 17:52
Juraj JakubovJuraj Jakubov
45
$endgroup$
I am trying to solve this limit without L'Hospital but i just dont know what do to with exponents.
$$lim _{n to infty}frac{-2^{n}+3^{n}}{{-2^{n+1}+3^{n+1}}}$$
I just dont know what to do with this exponenets
limits-without-lhopital
limits-without-lhopital
edited Dec 23 '18 at 20:57
Jyrki Lahtonen
109k13169374
asked Dec 23 '18 at 17:52
Juraj JakubovJuraj Jakubov
45
edited Dec 23 '18 at 20:57
Jyrki Lahtonen
109k13169374
asked Dec 23 '18 at 17:52
Juraj JakubovJuraj Jakubov
45
edited Dec 23 '18 at 20:57
Jyrki Lahtonen
109k13169374
edited Dec 23 '18 at 20:57
Jyrki Lahtonen
109k13169374
edited Dec 23 '18 at 20:57
Jyrki Lahtonen
109k13169374
109k13169374
asked Dec 23 '18 at 17:52
Juraj JakubovJuraj Jakubov
45
asked Dec 23 '18 at 17:52
Juraj JakubovJuraj Jakubov
45
asked Dec 23 '18 at 17:52
Juraj JakubovJuraj Jakubov
45
45
closed as off-topic by RRL, KReiser, Jyrki Lahtonen, Tianlalu, Saad Dec 24 '18 at 0:07
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – RRL, KReiser, Jyrki Lahtonen, Tianlalu, Saad
If this question can be reworded to fit the rules in the help center, please edit the question.
closed as off-topic by RRL, KReiser, Jyrki Lahtonen, Tianlalu, Saad Dec 24 '18 at 0:07
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – RRL, KReiser, Jyrki Lahtonen, Tianlalu, Saad
If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
2
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Hint: $displaystylefrac{-2^n+3^n}{-2^{n+1}+3^{n+1}}=frac{-left(frac23right)^n+1}{-2timesleft(frac23right)^n+3}$.
answered Dec 23 '18 at 17:55
José Carlos SantosJosé Carlos Santos
163k22130233
$endgroup$
$begingroup$
Please can you explain it little more i just dont know how you make that right side.
$endgroup$
– Juraj Jakubov
Dec 23 '18 at 18:04
$begingroup$
I divided the numerator and the denominator by $3^n$.
$endgroup$
– José Carlos Santos
Dec 23 '18 at 18:04
$begingroup$
Ou nice thank you now i understand :)
$endgroup$
– Juraj Jakubov
Dec 23 '18 at 18:05
add a comment |
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
$begingroup$
Hint: $displaystylefrac{-2^n+3^n}{-2^{n+1}+3^{n+1}}=frac{-left(frac23right)^n+1}{-2timesleft(frac23right)^n+3}$.
answered Dec 23 '18 at 17:55
José Carlos SantosJosé Carlos Santos
163k22130233
$endgroup$
$begingroup$
Please can you explain it little more i just dont know how you make that right side.
$endgroup$
– Juraj Jakubov
Dec 23 '18 at 18:04
$begingroup$
I divided the numerator and the denominator by $3^n$.
$endgroup$
– José Carlos Santos
Dec 23 '18 at 18:04
$begingroup$
Ou nice thank you now i understand :)
$endgroup$
– Juraj Jakubov
Dec 23 '18 at 18:05
add a comment |
2
$begingroup$
Hint: $displaystylefrac{-2^n+3^n}{-2^{n+1}+3^{n+1}}=frac{-left(frac23right)^n+1}{-2timesleft(frac23right)^n+3}$.
answered Dec 23 '18 at 17:55
José Carlos SantosJosé Carlos Santos
163k22130233
$endgroup$
$begingroup$
Please can you explain it little more i just dont know how you make that right side.
$endgroup$
– Juraj Jakubov
Dec 23 '18 at 18:04
$begingroup$
I divided the numerator and the denominator by $3^n$.
$endgroup$
– José Carlos Santos
Dec 23 '18 at 18:04
$begingroup$
Ou nice thank you now i understand :)
$endgroup$
– Juraj Jakubov
Dec 23 '18 at 18:05
add a comment |
2
2
2
$begingroup$
Hint: $displaystylefrac{-2^n+3^n}{-2^{n+1}+3^{n+1}}=frac{-left(frac23right)^n+1}{-2timesleft(frac23right)^n+3}$.
answered Dec 23 '18 at 17:55
José Carlos SantosJosé Carlos Santos
163k22130233
$endgroup$
Hint: $displaystylefrac{-2^n+3^n}{-2^{n+1}+3^{n+1}}=frac{-left(frac23right)^n+1}{-2timesleft(frac23right)^n+3}$.
answered Dec 23 '18 at 17:55
José Carlos SantosJosé Carlos Santos
163k22130233
answered Dec 23 '18 at 17:55
José Carlos SantosJosé Carlos Santos
163k22130233
answered Dec 23 '18 at 17:55
José Carlos SantosJosé Carlos Santos
163k22130233
answered Dec 23 '18 at 17:55
José Carlos SantosJosé Carlos Santos
163k22130233
163k22130233
$begingroup$
Please can you explain it little more i just dont know how you make that right side.
$endgroup$
– Juraj Jakubov
Dec 23 '18 at 18:04
$begingroup$
I divided the numerator and the denominator by $3^n$.
$endgroup$
– José Carlos Santos
Dec 23 '18 at 18:04
$begingroup$
Ou nice thank you now i understand :)
$endgroup$
– Juraj Jakubov
Dec 23 '18 at 18:05
add a comment |
$begingroup$
Please can you explain it little more i just dont know how you make that right side.
$endgroup$
– Juraj Jakubov
Dec 23 '18 at 18:04
$begingroup$
I divided the numerator and the denominator by $3^n$.
$endgroup$
– José Carlos Santos
Dec 23 '18 at 18:04
$begingroup$
Ou nice thank you now i understand :)
$endgroup$
– Juraj Jakubov
Dec 23 '18 at 18:05
$begingroup$
Please can you explain it little more i just dont know how you make that right side.
$endgroup$
– Juraj Jakubov
Dec 23 '18 at 18:04
$begingroup$
Please can you explain it little more i just dont know how you make that right side.
$endgroup$
– Juraj Jakubov
Dec 23 '18 at 18:04
$begingroup$
I divided the numerator and the denominator by $3^n$.
$endgroup$
– José Carlos Santos
Dec 23 '18 at 18:04
$begingroup$
I divided the numerator and the denominator by $3^n$.
$endgroup$
– José Carlos Santos
Dec 23 '18 at 18:04
$begingroup$
Ou nice thank you now i understand :)
$endgroup$
– Juraj Jakubov
Dec 23 '18 at 18:05
$begingroup$
Ou nice thank you now i understand :)
$endgroup$
– Juraj Jakubov
Dec 23 '18 at 18:05
add a comment |
