math puzzle: 4 digit number times 3












1












$begingroup$


A four-digit number $overline{abcd}$, and a five-digit number $overline{efghi}$, where $a,b, c, ..., i$ are from 1-9 and are distinct. We have



$overline{abcd}*3=overline{efghi}$.



What are $a, b, ..., i$?



What I have tried: I can deduce that $overline{efghi}$ must be divisible by 9, but then the enumeration does not give the answer? Can this hold at all?










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$endgroup$

















    1












    $begingroup$


    A four-digit number $overline{abcd}$, and a five-digit number $overline{efghi}$, where $a,b, c, ..., i$ are from 1-9 and are distinct. We have



    $overline{abcd}*3=overline{efghi}$.



    What are $a, b, ..., i$?



    What I have tried: I can deduce that $overline{efghi}$ must be divisible by 9, but then the enumeration does not give the answer? Can this hold at all?










    share|cite|improve this question









    $endgroup$















      1












      1








      1





      $begingroup$


      A four-digit number $overline{abcd}$, and a five-digit number $overline{efghi}$, where $a,b, c, ..., i$ are from 1-9 and are distinct. We have



      $overline{abcd}*3=overline{efghi}$.



      What are $a, b, ..., i$?



      What I have tried: I can deduce that $overline{efghi}$ must be divisible by 9, but then the enumeration does not give the answer? Can this hold at all?










      share|cite|improve this question









      $endgroup$




      A four-digit number $overline{abcd}$, and a five-digit number $overline{efghi}$, where $a,b, c, ..., i$ are from 1-9 and are distinct. We have



      $overline{abcd}*3=overline{efghi}$.



      What are $a, b, ..., i$?



      What I have tried: I can deduce that $overline{efghi}$ must be divisible by 9, but then the enumeration does not give the answer? Can this hold at all?







      puzzle






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      asked Dec 23 '18 at 21:27









      maomaomaomao

      27218




      27218






















          1 Answer
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          $begingroup$

          By exhaustive search there are two solutions:



          $$5823cdot 3 = 17469$$
          $$5832cdot 3 = 17496$$






          share|cite|improve this answer









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            1 Answer
            1






            active

            oldest

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            active

            oldest

            votes






            active

            oldest

            votes









            1












            $begingroup$

            By exhaustive search there are two solutions:



            $$5823cdot 3 = 17469$$
            $$5832cdot 3 = 17496$$






            share|cite|improve this answer









            $endgroup$


















              1












              $begingroup$

              By exhaustive search there are two solutions:



              $$5823cdot 3 = 17469$$
              $$5832cdot 3 = 17496$$






              share|cite|improve this answer









              $endgroup$
















                1












                1








                1





                $begingroup$

                By exhaustive search there are two solutions:



                $$5823cdot 3 = 17469$$
                $$5832cdot 3 = 17496$$






                share|cite|improve this answer









                $endgroup$



                By exhaustive search there are two solutions:



                $$5823cdot 3 = 17469$$
                $$5832cdot 3 = 17496$$







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Dec 23 '18 at 21:35









                orlporlp

                7,5791433




                7,5791433






























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