Assuming every seed has a 40% chance of growing, what is the chance of 5/5 seeds growing [closed]












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I know this is a super simple question, but I was discussing it with a friend.






probability







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closed as off-topic by José Carlos Santos, Don Thousand, Karn Watcharasupat, Leucippus, Lord_Farin Dec 19 '18 at 18:03


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, Don Thousand, Karn Watcharasupat, Leucippus, Lord_Farin

If this question can be reworded to fit the rules in the help center, please edit the question.












  • 2




    $begingroup$
    If each seed is independent from the others, why can't you just take the product?
    $endgroup$
    – Don Thousand
    Dec 19 '18 at 17:28
















0












$begingroup$


I know this is a super simple question, but I was discussing it with a friend.






probability







share|cite|improve this question









$endgroup$



closed as off-topic by José Carlos Santos, Don Thousand, Karn Watcharasupat, Leucippus, Lord_Farin Dec 19 '18 at 18:03


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, Don Thousand, Karn Watcharasupat, Leucippus, Lord_Farin

If this question can be reworded to fit the rules in the help center, please edit the question.












  • 2




    $begingroup$
    If each seed is independent from the others, why can't you just take the product?
    $endgroup$
    – Don Thousand
    Dec 19 '18 at 17:28














0












0








0





$begingroup$


I know this is a super simple question, but I was discussing it with a friend.






probability







share|cite|improve this question









$endgroup$




I know this is a super simple question, but I was discussing it with a friend.






probability




probability






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Dec 19 '18 at 17:22









C. DoughC. Dough

1




1




closed as off-topic by José Carlos Santos, Don Thousand, Karn Watcharasupat, Leucippus, Lord_Farin Dec 19 '18 at 18:03


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, Don Thousand, Karn Watcharasupat, Leucippus, Lord_Farin

If this question can be reworded to fit the rules in the help center, please edit the question.







closed as off-topic by José Carlos Santos, Don Thousand, Karn Watcharasupat, Leucippus, Lord_Farin Dec 19 '18 at 18:03


This question appears to be off-topic. The users who voted to close gave this specific reason:


  • "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – José Carlos Santos, Don Thousand, Karn Watcharasupat, Leucippus, Lord_Farin

If this question can be reworded to fit the rules in the help center, please edit the question.








  • 2




    $begingroup$
    If each seed is independent from the others, why can't you just take the product?
    $endgroup$
    – Don Thousand
    Dec 19 '18 at 17:28














  • 2




    $begingroup$
    If each seed is independent from the others, why can't you just take the product?
    $endgroup$
    – Don Thousand
    Dec 19 '18 at 17:28








2




2




$begingroup$
If each seed is independent from the others, why can't you just take the product?
$endgroup$
– Don Thousand
Dec 19 '18 at 17:28




$begingroup$
If each seed is independent from the others, why can't you just take the product?
$endgroup$
– Don Thousand
Dec 19 '18 at 17:28










1 Answer
1






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1












$begingroup$

Assuming that all seeds grow independent of each other, we can apply the multiplication rule,



P(all seeds growing) = P(seed1 growing)*P(seed2 growing)...*P(seed5 growing) $ = (0.4)^5= 0.01024$






share|cite|improve this answer









$endgroup$




















    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1












    $begingroup$

    Assuming that all seeds grow independent of each other, we can apply the multiplication rule,



    P(all seeds growing) = P(seed1 growing)*P(seed2 growing)...*P(seed5 growing) $ = (0.4)^5= 0.01024$






    share|cite|improve this answer









    $endgroup$


















      1












      $begingroup$

      Assuming that all seeds grow independent of each other, we can apply the multiplication rule,



      P(all seeds growing) = P(seed1 growing)*P(seed2 growing)...*P(seed5 growing) $ = (0.4)^5= 0.01024$






      share|cite|improve this answer









      $endgroup$
















        1












        1








        1





        $begingroup$

        Assuming that all seeds grow independent of each other, we can apply the multiplication rule,



        P(all seeds growing) = P(seed1 growing)*P(seed2 growing)...*P(seed5 growing) $ = (0.4)^5= 0.01024$






        share|cite|improve this answer









        $endgroup$



        Assuming that all seeds grow independent of each other, we can apply the multiplication rule,



        P(all seeds growing) = P(seed1 growing)*P(seed2 growing)...*P(seed5 growing) $ = (0.4)^5= 0.01024$







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Dec 19 '18 at 17:33









        Kshitij MishraKshitij Mishra

        413




        413















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