Solve sine and exponential nonlinear differential equation?












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$begingroup$


Is it possible to solve this kind of differential equation with forward Euler?



$$ddot y^2 + sin(ddot y ) + dot y + y = u$$



I haven't even write this ODE on the first order form. If I would do that, I would say $dot y = x_2$ and $y = x_1$. Then the ODE would be:



$$x_2 = dot x_1$$
$$dot x_2^2 + sin(dot x_2 ) + x_2 + x_1 = u$$



Then I move all the derivatives to the LHP and non-derivatives to RHP.



$$dot x_1 = x_2 $$
$$dot x_2^2 + sin(dot x_2 )= u - x_2 - x_1 $$



But how about these: $dot x_2^2 + sin(dot x_2 )$ ? My goal is to find $dot x_2$.










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$endgroup$












  • $begingroup$
    You can't find $dot{x}_2$ explicitly.
    $endgroup$
    – xpaul
    Dec 19 '18 at 17:40










  • $begingroup$
    And in many cases also not uniquely, especially if $2dot x_2+cos(dot x_2)=0$ or close to this point.
    $endgroup$
    – LutzL
    Dec 19 '18 at 17:42










  • $begingroup$
    @xpaul So the highest order need to be alone?
    $endgroup$
    – Daniel Mårtensson
    Dec 19 '18 at 18:00










  • $begingroup$
    $x^2 + sin(x)$ is not a one-to-one function of $x$.
    $endgroup$
    – Robert Israel
    Dec 19 '18 at 18:25










  • $begingroup$
    what is $u$ ? ...
    $endgroup$
    – JJacquelin
    Dec 20 '18 at 7:19
















0












$begingroup$


Is it possible to solve this kind of differential equation with forward Euler?



$$ddot y^2 + sin(ddot y ) + dot y + y = u$$



I haven't even write this ODE on the first order form. If I would do that, I would say $dot y = x_2$ and $y = x_1$. Then the ODE would be:



$$x_2 = dot x_1$$
$$dot x_2^2 + sin(dot x_2 ) + x_2 + x_1 = u$$



Then I move all the derivatives to the LHP and non-derivatives to RHP.



$$dot x_1 = x_2 $$
$$dot x_2^2 + sin(dot x_2 )= u - x_2 - x_1 $$



But how about these: $dot x_2^2 + sin(dot x_2 )$ ? My goal is to find $dot x_2$.










share|cite|improve this question









$endgroup$












  • $begingroup$
    You can't find $dot{x}_2$ explicitly.
    $endgroup$
    – xpaul
    Dec 19 '18 at 17:40










  • $begingroup$
    And in many cases also not uniquely, especially if $2dot x_2+cos(dot x_2)=0$ or close to this point.
    $endgroup$
    – LutzL
    Dec 19 '18 at 17:42










  • $begingroup$
    @xpaul So the highest order need to be alone?
    $endgroup$
    – Daniel Mårtensson
    Dec 19 '18 at 18:00










  • $begingroup$
    $x^2 + sin(x)$ is not a one-to-one function of $x$.
    $endgroup$
    – Robert Israel
    Dec 19 '18 at 18:25










  • $begingroup$
    what is $u$ ? ...
    $endgroup$
    – JJacquelin
    Dec 20 '18 at 7:19














0












0








0





$begingroup$


Is it possible to solve this kind of differential equation with forward Euler?



$$ddot y^2 + sin(ddot y ) + dot y + y = u$$



I haven't even write this ODE on the first order form. If I would do that, I would say $dot y = x_2$ and $y = x_1$. Then the ODE would be:



$$x_2 = dot x_1$$
$$dot x_2^2 + sin(dot x_2 ) + x_2 + x_1 = u$$



Then I move all the derivatives to the LHP and non-derivatives to RHP.



$$dot x_1 = x_2 $$
$$dot x_2^2 + sin(dot x_2 )= u - x_2 - x_1 $$



But how about these: $dot x_2^2 + sin(dot x_2 )$ ? My goal is to find $dot x_2$.










share|cite|improve this question









$endgroup$




Is it possible to solve this kind of differential equation with forward Euler?



$$ddot y^2 + sin(ddot y ) + dot y + y = u$$



I haven't even write this ODE on the first order form. If I would do that, I would say $dot y = x_2$ and $y = x_1$. Then the ODE would be:



$$x_2 = dot x_1$$
$$dot x_2^2 + sin(dot x_2 ) + x_2 + x_1 = u$$



Then I move all the derivatives to the LHP and non-derivatives to RHP.



$$dot x_1 = x_2 $$
$$dot x_2^2 + sin(dot x_2 )= u - x_2 - x_1 $$



But how about these: $dot x_2^2 + sin(dot x_2 )$ ? My goal is to find $dot x_2$.







ordinary-differential-equations nonlinear-system non-linear-dynamics






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share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Dec 19 '18 at 17:33









Daniel MårtenssonDaniel Mårtensson

944416




944416












  • $begingroup$
    You can't find $dot{x}_2$ explicitly.
    $endgroup$
    – xpaul
    Dec 19 '18 at 17:40










  • $begingroup$
    And in many cases also not uniquely, especially if $2dot x_2+cos(dot x_2)=0$ or close to this point.
    $endgroup$
    – LutzL
    Dec 19 '18 at 17:42










  • $begingroup$
    @xpaul So the highest order need to be alone?
    $endgroup$
    – Daniel Mårtensson
    Dec 19 '18 at 18:00










  • $begingroup$
    $x^2 + sin(x)$ is not a one-to-one function of $x$.
    $endgroup$
    – Robert Israel
    Dec 19 '18 at 18:25










  • $begingroup$
    what is $u$ ? ...
    $endgroup$
    – JJacquelin
    Dec 20 '18 at 7:19


















  • $begingroup$
    You can't find $dot{x}_2$ explicitly.
    $endgroup$
    – xpaul
    Dec 19 '18 at 17:40










  • $begingroup$
    And in many cases also not uniquely, especially if $2dot x_2+cos(dot x_2)=0$ or close to this point.
    $endgroup$
    – LutzL
    Dec 19 '18 at 17:42










  • $begingroup$
    @xpaul So the highest order need to be alone?
    $endgroup$
    – Daniel Mårtensson
    Dec 19 '18 at 18:00










  • $begingroup$
    $x^2 + sin(x)$ is not a one-to-one function of $x$.
    $endgroup$
    – Robert Israel
    Dec 19 '18 at 18:25










  • $begingroup$
    what is $u$ ? ...
    $endgroup$
    – JJacquelin
    Dec 20 '18 at 7:19
















$begingroup$
You can't find $dot{x}_2$ explicitly.
$endgroup$
– xpaul
Dec 19 '18 at 17:40




$begingroup$
You can't find $dot{x}_2$ explicitly.
$endgroup$
– xpaul
Dec 19 '18 at 17:40












$begingroup$
And in many cases also not uniquely, especially if $2dot x_2+cos(dot x_2)=0$ or close to this point.
$endgroup$
– LutzL
Dec 19 '18 at 17:42




$begingroup$
And in many cases also not uniquely, especially if $2dot x_2+cos(dot x_2)=0$ or close to this point.
$endgroup$
– LutzL
Dec 19 '18 at 17:42












$begingroup$
@xpaul So the highest order need to be alone?
$endgroup$
– Daniel Mårtensson
Dec 19 '18 at 18:00




$begingroup$
@xpaul So the highest order need to be alone?
$endgroup$
– Daniel Mårtensson
Dec 19 '18 at 18:00












$begingroup$
$x^2 + sin(x)$ is not a one-to-one function of $x$.
$endgroup$
– Robert Israel
Dec 19 '18 at 18:25




$begingroup$
$x^2 + sin(x)$ is not a one-to-one function of $x$.
$endgroup$
– Robert Israel
Dec 19 '18 at 18:25












$begingroup$
what is $u$ ? ...
$endgroup$
– JJacquelin
Dec 20 '18 at 7:19




$begingroup$
what is $u$ ? ...
$endgroup$
– JJacquelin
Dec 20 '18 at 7:19










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