if a characteristic function is constant on a interval then is constant in all R.
0
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I need help with this, please:
If a characteristic function is constant equals 1 on a interval $-rleq tleq r$ then is constant in all $mathbb{R}$
probability characteristic-functions
asked Dec 19 '18 at 17:49
Giancarlos Giancarlos
42
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add a comment |
0
$begingroup$
I need help with this, please:
If a characteristic function is constant equals 1 on a interval $-rleq tleq r$ then is constant in all $mathbb{R}$
probability characteristic-functions
asked Dec 19 '18 at 17:49
Giancarlos Giancarlos
42
$endgroup$
2
$begingroup$
The derivatives of the characteristic function at zero are related to the moments of the random variable. Maybe you can argue from there.
$endgroup$
– passerby51
Dec 19 '18 at 18:01
1
$begingroup$
... in particular, consider the second derivative.
$endgroup$
– Robert Israel
Dec 19 '18 at 18:09
add a comment |
0
0
0
$begingroup$
I need help with this, please:
If a characteristic function is constant equals 1 on a interval $-rleq tleq r$ then is constant in all $mathbb{R}$
probability characteristic-functions
asked Dec 19 '18 at 17:49
Giancarlos Giancarlos
42
$endgroup$
I need help with this, please:
If a characteristic function is constant equals 1 on a interval $-rleq tleq r$ then is constant in all $mathbb{R}$
probability characteristic-functions
probability characteristic-functions
asked Dec 19 '18 at 17:49
Giancarlos Giancarlos
42
asked Dec 19 '18 at 17:49
Giancarlos Giancarlos
42
asked Dec 19 '18 at 17:49
Giancarlos Giancarlos
42
asked Dec 19 '18 at 17:49
Giancarlos Giancarlos
42
asked Dec 19 '18 at 17:49
Giancarlos Giancarlos
42
42
2
$begingroup$
The derivatives of the characteristic function at zero are related to the moments of the random variable. Maybe you can argue from there.
$endgroup$
– passerby51
Dec 19 '18 at 18:01
1
$begingroup$
... in particular, consider the second derivative.
$endgroup$
– Robert Israel
Dec 19 '18 at 18:09
add a comment |
2
$begingroup$
The derivatives of the characteristic function at zero are related to the moments of the random variable. Maybe you can argue from there.
$endgroup$
– passerby51
Dec 19 '18 at 18:01
1
$begingroup$
... in particular, consider the second derivative.
$endgroup$
– Robert Israel
Dec 19 '18 at 18:09
2
2
$begingroup$
The derivatives of the characteristic function at zero are related to the moments of the random variable. Maybe you can argue from there.
$endgroup$
– passerby51
Dec 19 '18 at 18:01
$begingroup$
The derivatives of the characteristic function at zero are related to the moments of the random variable. Maybe you can argue from there.
$endgroup$
– passerby51
Dec 19 '18 at 18:01
1
1
$begingroup$
... in particular, consider the second derivative.
$endgroup$
– Robert Israel
Dec 19 '18 at 18:09
$begingroup$
... in particular, consider the second derivative.
$endgroup$
– Robert Israel
Dec 19 '18 at 18:09
add a comment |
0
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2
$begingroup$
The derivatives of the characteristic function at zero are related to the moments of the random variable. Maybe you can argue from there.
$endgroup$
– passerby51
Dec 19 '18 at 18:01
1
$begingroup$
... in particular, consider the second derivative.
$endgroup$
– Robert Israel
Dec 19 '18 at 18:09