Find the Cartesian form of the parametric equations: $x=2sin^2(theta)$, $y=7cos^2(theta)$
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I am trying to find the cartesian form of the parametric expressions $x=2sin^2(theta)$, $y=7cos^2(theta)$. I have $x=2-cos^2(theta)$ but i can't work it after that.
parametric
asked Dec 10 '18 at 21:44
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I am trying to find the cartesian form of the parametric expressions $x=2sin^2(theta)$, $y=7cos^2(theta)$. I have $x=2-cos^2(theta)$ but i can't work it after that.
parametric
asked Dec 10 '18 at 21:44
NeedHelpNeedHelp
161
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add a comment |
0
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0
$begingroup$
I am trying to find the cartesian form of the parametric expressions $x=2sin^2(theta)$, $y=7cos^2(theta)$. I have $x=2-cos^2(theta)$ but i can't work it after that.
parametric
asked Dec 10 '18 at 21:44
NeedHelpNeedHelp
161
$endgroup$
I am trying to find the cartesian form of the parametric expressions $x=2sin^2(theta)$, $y=7cos^2(theta)$. I have $x=2-cos^2(theta)$ but i can't work it after that.
parametric
parametric
asked Dec 10 '18 at 21:44
NeedHelpNeedHelp
161
asked Dec 10 '18 at 21:44
NeedHelpNeedHelp
161
asked Dec 10 '18 at 21:44
NeedHelpNeedHelp
161
asked Dec 10 '18 at 21:44
NeedHelpNeedHelp
161
asked Dec 10 '18 at 21:44
NeedHelpNeedHelp
161
161
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$$sin^2(theta)+cos^2(theta)=1$$
$$frac{x}{2}+frac{y}{7}=1$$
answered Dec 10 '18 at 21:48
mm-crjmm-crj
425213
$endgroup$
1
$begingroup$
Also with the restrictions $x, y ge 0$ (which also implies $x le 2$, $y le 7$).
$endgroup$
– Daniel Schepler
Dec 10 '18 at 22:04
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Yeah.. Thanks :)
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– mm-crj
Dec 10 '18 at 22:06
add a comment |
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1 Answer
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1 Answer
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0
$begingroup$
$$sin^2(theta)+cos^2(theta)=1$$
$$frac{x}{2}+frac{y}{7}=1$$
answered Dec 10 '18 at 21:48
mm-crjmm-crj
425213
$endgroup$
1
$begingroup$
Also with the restrictions $x, y ge 0$ (which also implies $x le 2$, $y le 7$).
$endgroup$
– Daniel Schepler
Dec 10 '18 at 22:04
$begingroup$
Yeah.. Thanks :)
$endgroup$
– mm-crj
Dec 10 '18 at 22:06
add a comment |
0
$begingroup$
$$sin^2(theta)+cos^2(theta)=1$$
$$frac{x}{2}+frac{y}{7}=1$$
answered Dec 10 '18 at 21:48
mm-crjmm-crj
425213
$endgroup$
1
$begingroup$
Also with the restrictions $x, y ge 0$ (which also implies $x le 2$, $y le 7$).
$endgroup$
– Daniel Schepler
Dec 10 '18 at 22:04
$begingroup$
Yeah.. Thanks :)
$endgroup$
– mm-crj
Dec 10 '18 at 22:06
add a comment |
0
0
0
$begingroup$
$$sin^2(theta)+cos^2(theta)=1$$
$$frac{x}{2}+frac{y}{7}=1$$
answered Dec 10 '18 at 21:48
mm-crjmm-crj
425213
$endgroup$
$$sin^2(theta)+cos^2(theta)=1$$
$$frac{x}{2}+frac{y}{7}=1$$
answered Dec 10 '18 at 21:48
mm-crjmm-crj
425213
answered Dec 10 '18 at 21:48
mm-crjmm-crj
425213
answered Dec 10 '18 at 21:48
mm-crjmm-crj
425213
answered Dec 10 '18 at 21:48
mm-crjmm-crj
425213
425213
1
$begingroup$
Also with the restrictions $x, y ge 0$ (which also implies $x le 2$, $y le 7$).
$endgroup$
– Daniel Schepler
Dec 10 '18 at 22:04
$begingroup$
Yeah.. Thanks :)
$endgroup$
– mm-crj
Dec 10 '18 at 22:06
add a comment |
1
$begingroup$
Also with the restrictions $x, y ge 0$ (which also implies $x le 2$, $y le 7$).
$endgroup$
– Daniel Schepler
Dec 10 '18 at 22:04
$begingroup$
Yeah.. Thanks :)
$endgroup$
– mm-crj
Dec 10 '18 at 22:06
1
1
$begingroup$
Also with the restrictions $x, y ge 0$ (which also implies $x le 2$, $y le 7$).
$endgroup$
– Daniel Schepler
Dec 10 '18 at 22:04
$begingroup$
Also with the restrictions $x, y ge 0$ (which also implies $x le 2$, $y le 7$).
$endgroup$
– Daniel Schepler
Dec 10 '18 at 22:04
$begingroup$
Yeah.. Thanks :)
$endgroup$
– mm-crj
Dec 10 '18 at 22:06
$begingroup$
Yeah.. Thanks :)
$endgroup$
– mm-crj
Dec 10 '18 at 22:06
add a comment |
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